Freefall (CIE IGCSE Physics)

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Acceleration of free fall

  • In the absence of air resistance, all objects fall with the same acceleration regardless of their mass
  • This is called the acceleration of freefall
    • This is also sometimes called acceleration due to gravity

acceleration space of space freefall space equals space straight g space equals space 9.8 space straight m divided by straight s squared

leaning-tower-of-pisa, IGCSE & GCSE Chemistry revision notes

In the absence of air resistance, Galileo discovered that all objects (near Earth's surface) fall with an acceleration of about 9.8 m/s2

  • This means that for every second an object falls, its velocity will increase by 9.8 m/s

  • The symbol g also stands for the gravitational field strength, and can be used to calculate the force of weight acting an object using its mass:

W space equals space m g

  • Where:
    • W = the force of weight acting on an object, measured in newtons (N)
    • m = mass of object, measured in kilograms (kg)
    • g = gravitational field strength, measured in newtons per kilogram (N/kg)

Motion of falling objects

Extended tier only

Falling objects without air resistance

  • A vacuum is a space that contains no matter, so there are no particles to exert frictional forces on a falling object
  • When objects fall in a vacuum, there is no air resistance or liquid resistance so the only force acting on them is the force of weight

W space equals space m g

a space equals fraction numerator space F over denominator m end fraction

  • Where:
    • a = acceleration, measured in metres per second squared (m/s2)
    • F = force exerted on object, measured in newtons (N)
    • m = mass of object, measured in kilograms (kg)

  • Since the only force acting on a falling object in a vacuum is weight, the equation can be expressed as 

a space equals fraction numerator space W over denominator m end fraction

  • Weight is the product of mass and gravitational field strength, so the equation can be expressed as 

a space equals fraction numerator space m g over denominator m end fraction space

  • Here, the masses cancel each other out

a space equals fraction numerator space up diagonal strike m g over denominator up diagonal strike m end fraction

  • So, for objects falling in a vacuum

a space equals space g

  • Where g = acceleration of free fall

  • This theory was tested by astronauts on the Moon
    • A hammer and a feather were dropped from equal heights on the Moon, where there is no air resistance
    • The hammer and the feather fell with the same acceleration and landed at the same time
    • This proved that objects falling in a vacuum have the same acceleration regardless of their mass

  • This also applies when air resistance is so small that it can be disregarded
    • When air resistance is described as negligible, it can be approximated to an object is falling in a vacuum

 Object falling with no air resistance

Freefall graph, IGCSE & GCSE Physics revision notes

In the absence of air resistance, objects fall with constant acceleration

  • Objects falling through a vacuum will never reach a terminal velocity

 Falling objects with air resistance

  • When objects fall through a fluid, the fluid exerts a frictional force on the object as it falls
    • Fluids are liquids or gases
  • Frictional forces oppose the motion of an object
    • They act to slow it down
  • When an object falls through air, it experiences air resistance
    • Air resistance is a frictional force produced by collisions with air particles as the object moves through the air
  • Air resistance increases as the speed of the object increases

 

  • When objects fall through air, two forces are exerted on the object:
    • The force of weight
    • The force of air resistance
  • When the force of air resistance becomes equal to the force of weight, then the object stops accelerating and falls at a constant speed
    • This is called terminal velocity

 

How does a skydiver reach terminal velocity?

Diagram showing the phases of a parachute jump for IGCSE & GCSE revision notes

The stages of a skydivers fall until they reach terminal velocity

  • When a skydiver jumps out of a plane, initially the only force acting on them is weight
    • The resultant force acts in the downward direction
    • The skydiver accelerates

  • As the skydiver accelerates, their speed increases, so the force of air resistance increases
    • The resultant force acts in the downward direction with a smaller magnitude
    • The skydiver continues to accelerate but at a slower rate

  • Air resistance increases until it is equal to the weight
    • The forces are balanced
    • There is no resultant force
    • Terminal velocity is reached

  • The parachute is deployed, increasing the surface area of the skydiver
    • The parachute collides with many more air particles
    • Air resistance increases greatly

  • The force of air resistance is now greater than the force of weight
    • The resultant force acts in the upward direction
    • The skydiver continues falling in a downward direction
    • The skydiver is decelerating

  • As the skydiver decelerates, their speed decreases
    • Therefore, air resistance decreases
    • Therefore, the resultant force decreases

  • Air resistance decreases until it is equal to the weight
    • The forces are balanced
    • There is no resultant force
    • A new, slower terminal velocity is reached

 

Graph showing the motion of the skydiver as they reach terminal velocity

terminal-velocity-graph, IGCSE & GCSE Chemistry revision notes

The graph shows how the speed of the skydiver changes during the descent. The horizontal parts of the graph show the periods of terminal velocity

Worked example

A small object falls out of an aircraft. Choose words from the list to complete the sentences below:

air resistance       gravitational field strength       air pressure

accelerates       falls at a steady speed       slows down

 

(a) The weight of an object is the product of the object's mass and the __________.

(b) When an object falls, initially it ____________.

(c) As the object falls faster, the force of ______________ acting upon the object increases.

(d) Eventually the object ______________ when the force of friction equals the force of weight acting on it.

Answer:

Part (a)

The weight of an object is the product of the object's mass and the gravitational field strength.

  • The weight force is due to the Earth's gravitational pull on the object's mass as it falls through a uniform gravitational field

Part (b)

When an object falls, initially it accelerates.

  • The resultant force on the object is very large initially, so it accelerates
  • This is because there is a large unbalanced force downwards (its weight) - the upward force of air resistance is very small to begin with

Part (c)

As the object falls faster, the force of air resistance acting on the object increases.

  • The force of air resistance is due to friction between the object's motion and collisions with air particles
  • Collisions with air particles slow the object down, so air itself produces a frictional force, called air resistance (sometimes called drag)

Part (d)

Eventually, the object falls at a steady speed when the force of friction equals the force of weight acting on it.

  • When the upward acting air resistance increases enough to balance the downward weight force, the resultant force on the object is zero
  • This means the object is no longer accelerating; it is moving at a steady speed called terminal velocity

 

Exam Tip

Don't confuse 'air resistance' with 'air pressure' - these are two different concepts!

Exam questions about terminal velocity tend to involve the motion of skydivers as they fall

A common misconception is that skydivers move upwards when their parachutes are deployed; however, this is not the case, they are in fact decelerating to a lower terminal velocity

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Leander

Author: Leander

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.