Calculating Acceleration from Speed-Time Graphs (Cambridge (CIE) IGCSE Physics): Revision Note

Exam code: 0625 & 0972

Leander Oates

Written by: Leander Oates

Reviewed by: Tim

Updated on

Interpreting speed-time graphs

Extended tier only

  • When interpreting speed-time graphs, the shape of the graph can show:

    • constant acceleration

    • changing acceleration

  • The gradient of a speed-time graph shows the acceleration of a moving object

    • The gradient is positive if the object is accelerating (speed increases with time)

    • The gradient is negative if the object is decelerating (speed decreases with time)

Interpreting constant positive acceleration on a speed-time graph

  • When the acceleration is constant and non-zero:

    • the graph is a straight line

    • velocity is increasing at a constant rate, i.e. speed changes by the same amount in equal intervals of time

Constant positive acceleration on a speed-time graph

Speed–time graph showing speed rising linearly from 0 to 30 m/s over 120 s, with 5 m/s increase every 20 s.
A speed-time graph for an object with constant positive acceleration. Its speed increases by 5 m/s every 20 s, showing that the rate at which the speed increases is constant.

Interpreting increasing positive acceleration on a speed-time graph

  • When the acceleration is increasing:

    • the graph is a curve 

    • velocity is increasing at an increasing rate, i.e. the speed changes by the same amount in increasingly shorter time intervals

Increasing positive acceleration on a speed-time graph

Speed–time graph with a curved line showing increasing acceleration. Speed gains of 5 m/s occur in progressively shorter time intervals.
A speed-time graph for an object with changing positive acceleration. The time taken for the speed to increase by 5 m/s decreases over time, showing that acceleration is increasing.

Interpreting decreasing positive acceleration on a speed-time graph

  • When the acceleration is decreasing:

    • the graph is a curve

    • velocity is increasing at a decreasing rate, i.e. the speed changes by the same amount in increasingly longer time intervals

Decreasing positive acceleration on a speed-time graph

Speed–time graph with a curved line showing decreasing acceleration before levelling off. Speed gains of 5 m/s occur in progressively longer times.
A speed-time graph for an object with changing positive acceleration. The time taken for the speed to increase by 5 m/s increases over time, showing that acceleration is decreasing.

Interpreting decreasing negative acceleration on a speed-time graph

  • When the deceleration is decreasing:

    • the graph is a curve

    • the velocity is decreasing at a decreasing rate, i.e. the speed changes by the same amount in increasingly longer intervals of time

Decreasing negative acceleration on a speed-time graph

Speed–time graph with a curved line showing decreasing deceleration before levelling off. Speed losses of 5 m/s from 40 m/s to 5 m/s occur in progressively longer times.
A speed-time graph for an object with changing negative acceleration. The time taken for the speed to decrease by 5 m/s increases over time, showing that deceleration is decreasing.

Examiner Tips and Tricks

In CIE IGCSE Physics, interpreting graphs is a required skill

  • For your exam, you are also expected to calculate the gradient of a graph and the area under a graph

  • Finding the area under a graph is covered in the revision note Speed-time graphs

Calculating acceleration

Extended Tier Only

Finding the gradient when acceleration is constant

  • When acceleration is constant, the speed-time graph will be a straight line

  • The gradient of a straight line can be found using:

 gradient = yx

  • Where:

    • y = change in y (speed) values

    • x = change in x (time) values

  • Therefore, the gradient is equal to:

 a = vt

  • Where:

    • a = acceleration, measured in metres per second squared (m/s2)

    • v = change in speed, measured in metres per second (m/s)

    • t = change in time, measured in seconds (s)

Speed–time graph with a straight sloped line; horizontal change Δx and vertical change Δy marked to show gradient equals Δy divided by Δx.
The gradient of a speed-time graph for constant acceleration can be found using Δy divided by Δx

Finding the gradient when acceleration is changing

  • When acceleration is changing, the speed-time graph will be a curve

  • The gradient of a point on a curve can be found by drawing a tangent to the curve

    • A tangent to the curve is a straight line drawn to match the gradient of the curve at a specific point

A tangent to the curve

Graph showing a curve, a vertical line from the x‑axis meeting the curve, and a straight tangent at that point, labelled to illustrate gradient at that point.
The value of the gradient at a single point on a curve can be determined by finding the gradient of the tangent to that point 
  • The tangent provides a gradient that is representative of the gradient at a specific point on the curve

  • The gradient of the tangent can be found using:

gradient = yx

  • The value of the gradient at a specific point on the curve represents the acceleration of the object at that moment

    • This is called instantaneous acceleration

Worked Example

A cyclist is training for a cycling tournament.

The speed-time graph below shows the cyclist's motion as they cycle along a flat, straight road.

Speed-time graph with speed in metres per second on the vertical axis and time in seconds on the horizontal axis, showing five lines. Line A shows the cyclist stationary for 5 seconds. Line B shows the cyclist constantly accelerating from 0 to 5 m/s between 5 s and 10 s. Line C shows the cyclist maintaining a constant 5 m/s speed between 10 s and 13 s. Line D shows the cyclist constantly accelerating from 5 m/s to 10 m/s between 13 s and 15 s. Line E shows the cyclist maintaining a constant 10 m/s speed between 15 s and 20 s.

(a) In which section (A, B, C, D, or E) of the speed-time graph is the cyclist's acceleration the largest? [1]

(b) Calculate the cyclist's acceleration between 5 and 10 seconds. [3]

 

Answer:

Part (a)

Step 1: Recall that the slope of a speed-time graph represents the magnitude of acceleration

  • The slope of a speed-time graph indicates the magnitude of acceleration

  • Therefore, the only sections of the graph where the cyclist is accelerating are sections B and D

  • Sections A, C and E are flat; in other words, the cyclist is moving at a constant speed (therefore, not accelerating)

Step 2: Identify the section with the steepest slope

  • Section D of the graph has the steepest slope

  • Hence, the largest acceleration is shown in section D [1 mark]

 

Part (b)

Step 1: Recall that the gradient of a speed-time graph gives the acceleration

  • Calculating the gradient of a slope on a speed-time graph gives the acceleration for that time period [1 mark]

Step 2: Draw a large gradient triangle at the appropriate section of the graph

  • A gradient triangle is drawn for the time period between 5 and 10 seconds [1 mark]

Speed-time graph with speed in metres per second on the vertical axis and time in seconds on the horizontal axis, showing five lines. Line B shows the cyclist constantly accelerating from 0 to 5 m/s between 5 s and 10 s. Red Δx and Δy arrows are illustrating the gradient of line B.

Step 3: Calculate the size of the gradient and state this as the acceleration

  • The acceleration is given by the gradient, which can be calculated using:

a = yx

a = 55

a = 1 m/s2

  • Therefore, the cyclist accelerated at 1 m/s2 between 5 and 10 seconds [1 mark]

Examiner Tips and Tricks

Use the entire straight-line section, where possible, to calculate the gradient. Examiners tend to award credit if they see a large gradient triangle used.

Remember to actually draw the lines directly on the graph itself, particularly when the question asks you to use the graph to calculate the acceleration. 

Worked Example

A skydiver jumps from a plane and reaches terminal velocity after 15 seconds. A  speed-time graph of their motion is shown below.

Use the graph to find the acceleration at 5 seconds.

Speed–time graph of a car accelerating from 0 to 50 m/s over 10 s, where the curve rises steeply then flattens off.

[3]

Answer:

Step 1: Draw a tangent to the curve at the point where t = 5 s [1 mark]

Speed–time graph with black curved line and green straight line, showing changing speed from 0–10 seconds, with labelled points at 5 s, 20 m/s and 60 m/s
Speed–time graph of a car accelerating from 0 to 50 m/s over 10 s, where the black curve rises steeply then flattens off. Green tangent to black curve is drawn at t = 5 s, which has end values of 9.75 s, 58 m/s and 0.75 s, 20 m/s.

Step 2: Calculate the gradient of the tangent

  • Change in y (speed): y 

  • Change in x (time): x 

a = yx

a = 58  209.75  0.75 [1 mark]

a =389.0

a = 4.2 m/s2 (2 s.f.) [1 mark]

Examiner Tips and Tricks

The CIE IGCSE Physics specification includes knowing how to calculate the gradient of a tangent to the curve in the maths skills section. This means that you could be asked to demonstrate this skill in any topic. The skills in this revision note are applicable to any type of graph. For more information on interpreting graphs in Physics, see the article Graph skills in GCSE Physics

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Leander Oates

Author: Leander Oates

Expertise: Development Editor

Leander graduated with First-class honours in Science and Education from Sheffield Hallam University. She won the prestigious Lord Robert Winston Solomon Lipson Prize in recognition of her dedication to science and teaching excellence. After teaching and tutoring both science and maths students, Leander now brings this passion for helping young people reach their potential to her work at SME.

Tim

Reviewer: Tim

Expertise: Content Creator

Timothy graduated with a first class degree in Mathematics and Physics from the University of Warwick. After working as a postgraduate researcher, Timothy has worked as a content creator for various online revision platforms, creating physics resources for a range of levels and exam boards.