Recurring Decimals (Cambridge (CIE) IGCSE Maths)

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Recurring Decimals

What are recurring decimals?

  • When writing a rational number as a decimal, it will either be:

    • A decimal that stops, called a "terminating" decimal

      • 1 fourth equals 0.25

    • Or a decimal that repeats with a pattern, called a "recurring" decimal

      • 32 over 99 equals 0.32323232...

  • The recurring part can be written with a dot above the digit that repeats

  • If multiple digits repeat, dots are used on the first and last digits that repeat

    • 0.3333... space equals space 0.3 with dot on top

    • 0.121212... space equals 0.1 with dot on top 2 with dot on top

    • 0.325632563256... equals 0.3 with dot on top 25 6 with dot on top

How do I write recurring decimals as fractions?

Write out the first few decimal places to show the recurring pattern and then:

  • STEP 1
    Write the recurring decimal as x equals...

    • x equals 0.35353535...

  • STEP 2
    Multiply both sides by 10 repeatedly until two lines have the same recurring decimal part

    • table row x equals cell 0.35353535... end cell end table

    • table row cell 10 x end cell equals cell 3.5353535... end cell end table

    • table row cell 100 x end cell equals cell 35.353535... end cell end table

      • Note that x and 100x have 35 repeating after the decimal point, the repeating pattern after 10x is 53 repeating

  • STEP 3
    Subtract the two lines which have matching recurring decimal parts

    • table row cell 100 x minus x end cell equals cell 35.353535... negative 0.35353535... end cell end table

    • table row cell 99 x end cell equals 35 end table

  • STEP 4
    Divide both sides to get x equals...
    Cancel if necessary to get fraction in its lowest terms

    • x equals 35 over 99

Worked Example

Write 0.3 with dot on top 0 7 with dot on top as a fraction in its lowest terms.

Write as x equals... to show the pattern

x equals 0.307307307307...

Multiply both sides by 10 repeatedly until two lines have the same recurring decimal part

table row cell 10 x end cell equals cell 3.07307307307... end cell row cell 100 x end cell equals cell 30.730730730... end cell row cell 1000 x end cell equals cell 307.307307307... end cell end table

Notice that x and 1000 x have matching recurring decimal parts

Subtract one from the other

table row cell 1000 x minus x end cell equals cell 307.307307307... negative 0.307307307... end cell row cell 999 x end cell equals 307 end table

Divide both sides by 999

x equals 307 over 999

This cannot be simplified, so this is the final answer

307 over 999

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

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Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.