Formulas where Subject Appears Twice (Cambridge (CIE) IGCSE Maths)

Revision Note

Subject Appears Twice

How do I rearrange formulae where the subject appears twice?  

  • If the subject appears twice, you will need to factorise at some point

    • E.g. When making x the subject of x plus x y equals 3 minus 2 y

    • Factorise out xon the left to get x open parentheses 1 plus y close parentheses equals 3 minus 2 y

      • Notice that the subject now only appears once!

    • Then divide both sides by open parentheses 1 plus y close parentheses to get x equals fraction numerator 3 minus 2 y over denominator 1 plus y end fraction

  • If the subject appears twice, and any of these are inside a set of brackets, you will need to expand these brackets first

    • E.g. When making x the subject of c open parentheses x plus 2 close parentheses minus x equals f

    • Expand the bracket first to c x plus 2 c minus x equals f

    • Keep the x terms on one side c x minus x equals f minus 2 c

    • x can then be made the subject using factorising as above

  • If the subject appears on two sides of a formula, you will need to bring those terms to the same side before you can factorise

    • E.g. When making xthe subject of 3 x equals y minus p x

    • Add p x to both sides first to form 3 x plus p x equals y

    • x can then be made the subject using factorising as above

How do I factorise powers of a subject? 

  • If the subject appears twice, and both have the same power, you will need to collect these terms together before applying their inverse

    • E.g. When making xthe subject of x squared equals negative p x squared plus r

    • Add p x squared to both sides first to form x squared plus p x squared equals r

    • x squared can then be factorised out x squared open parentheses 1 plus p close parentheses equals r to give x squared equals fraction numerator r over denominator 1 plus p end fraction

      • Now take plus-or-minus square roots

      • x equals plus-or-minus square root of fraction numerator r over denominator 1 plus p end fraction end root

  • Be careful when square rooting, or cube rooting etc

    • E.g. To make x the subject of x cubed equals fraction numerator t cubed plus 1 over denominator t cubed plus 8 end fraction

      • The whole right hand side must be cube rooted

      • x equals cube root of fraction numerator t cubed plus 1 over denominator t cubed plus 8 end fraction end root

      • This cannot be simplified further

      • The right hand side is not equal to fraction numerator t plus 1 over denominator t plus 2 end fraction, (this is a common error)

Worked Example

Rearrange the formula p equals fraction numerator 2 space minus space a x over denominator x space minus space b space end fraction to make x the subject.

Get rid of the fraction by multiplying both sides by the expression on the denominator

p open parentheses x space minus space b close parentheses space equals space 2 space minus space a x

Expand the brackets on the left hand side to 'release' the x

p x space minus space p b space equals space 2 space minus space a x

Bring the terms containing x to one side of the equals sign and any other terms to the other side

table row cell p x space minus space p b space end cell equals cell space 2 space minus space a x end cell end table

table row blank blank cell open parentheses plus a x close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open parentheses plus a x close parentheses end cell end table

table row cell p x space minus space p b space plus space a x space end cell equals cell space 2 end cell end table

table row blank blank cell open parentheses plus p b close parentheses space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open parentheses plus p b close parentheses end cell end table

table attributes columnalign right center left columnspacing 0px end attributes row cell p x space plus space a x space end cell equals cell space 2 space plus space p b end cell end table

Factorise the left-hand side to bring x outside of the brackets, so that it appears only once

x open parentheses p space plus space a close parentheses space equals space 2 space plus space p b

Make x the subject by dividing by the whole expression open parentheses p space plus space a close parentheses

bold italic x bold space bold equals bold space fraction numerator bold 2 bold space bold plus bold space bold italic p bold italic b over denominator bold italic p bold space bold plus bold space bold italic a end fraction

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.