Averages from Grouped Data (Edexcel IGCSE Maths A (Modular))

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Flashcards

Averages from Grouped Data

What is grouped data?

  • Data can be collected into groups or class intervals

    • It is useful for organising data if you have a lot of individual data points

    • You can present grouped data in a grouped frequency table

  • Grouped data may be discrete or continuous

    • Discrete data is numerical data that can only take on specific values, it needs to be counted

      • E.g. Shoe size

    • Continuous data can take any value within a range of infinite values, it needs to be measured

      • E.g. Length of a foot in cm

Why do I find an estimate for the mean from grouped data?

  • It is impossible to find the mean for grouped data, because we don't have access to the original data values

    • i.e. there is no way to find the exact sum of all the data values

    • so we can't use the formula, mean equals fraction numerator sum space of space values over denominator number space of space values end fraction

  • However we can estimate the mean for grouped data

    • To do this we use the class midpoints as our data values

      • e.g. if a class interval is 150 ≤ x < 160

      • we assume that all the data values are equal to the midpoint, 155

Examiner Tips and Tricks

  • When presented with data in a table it may not be obvious whether the data is grouped or not

    • When you see the phrase “estimate the mean” you know that you are in the world of grouped data!

How do I find an estimate for the mean from grouped data?

  • To find an estimate for the mean from grouped data, complete the following steps:

  • STEP 1
    Draw an extra two columns on the end of a table of the grouped data

    • In the first new column write down the midpoint of each class interval

    • If the midpoint isn't obvious, add the endpoints and divide by 2

      • e.g. if a class interval is 150 ≤ x < 160

      • the midpoint is fraction numerator 150 plus 160 over denominator 2 end fraction equals 310 over 2 equals 155

  • STEP 2
    Calculate "frequency" × "midpoint" (this is often called fx)

    • Write these values in the second column you added to the table

  • STEP 3
    Find the total for the fx column

    • If the question does not tell you the total number of data values (i.e. the total frequency), find the total of the frequency column also

  • STEP 4
    Estimate the mean by using the formula

    • estimated space mean equals fraction numerator total space of space open parentheses midpoints cross times frequencies close parentheses space over denominator total space frequency end fraction

    • i.e. divide the total of the fx column by the total number of data values

How do I find the modal class?

  • For grouped data we talk about the modal class instead of the mode

    • This is the class with the highest frequency

  • Find the highest frequency in the table

    • The corresponding class interval tells you the modal class

How do I find the class interval that the median lies in?

  • Find the position of the median using fraction numerator n plus 1 over denominator 2 end fraction, where n is the number of data values (total of the frequency column)

  • Use the table to deduce the class interval containing the open parentheses fraction numerator n plus 1 over denominator 2 end fraction close parentheses to the power of th value

    • e.g. if the median is the 7th value and the frequency of the first two class intervals are 4 and 7

      • the median will lie in the second class interval of the table

  • Note that rather than 'the median' we refer to the 'class interval containing the median'

Examiner Tips and Tricks

  • Be careful not to confuse the modal class with its frequency

    • e.g. if the highest frequency in the table is 34, corresponding to the class interval 40 less or equal than x less than 50

    • then the modal class is 40 less or equal than x less than 50, not '34'!

    • This also applies to the interval containing the median

Worked Example

The weights of 20 three-week-old Labrador puppies were recorded at a vet's clinic. The results are shown in the table below.

Weight, w kg

Frequency

3 ≤ w < 3.5

2

3.5 ≤ w < 4

4

4 ≤ w < 4.5

6

4.5 ≤ w < 5

5

5 ≤ w < 5.5

2

5.5 ≤ w < 6

1

(a) Estimate the mean weight of these puppies.

First add two columns to the table
Complete the first new column with the midpoints of the class intervals
Complete the second extra column by calculating "fx"
A total row is also useful

Weight, w kg

Frequency

Midpoint

"fx"

3 ≤ w < 3.5

2

3.25

2 × 3.25 = 6.5

3.5 ≤ w < 4

4

3.75

4 × 3.75 = 15

4 ≤ w < 4.5

6

4.25

6 × 4.25 = 25.5

4.5 ≤ w < 5

5

4.75

5 × 4.75 = 23.75

5 ≤ w < 5.5

2

5.25

2 × 5.5 = 10.5

5.5 ≤ w < 6

1

5.75

1 × 5.75 = 5.75

Total

20

 

87

Now we can find the mean using

estimated space mean equals fraction numerator total space of space open parentheses midpoints space cross times frequencies close parentheses over denominator total space frequency end fraction

estimated space mean equals 87 over 20 equals 4.35

4.35 kg

(b) Write down the modal class.

The highest frequency in the table is 6
This corresponds to the interval 4 ≤ w < 4.5

4 ≤ w < 4.5

A common error here would be to write down 6
(the frequency) as the modal class

(c) Find the interval that contains the median.

There are 20 dogs
The median interval will be the interval containing the 10.5th dog
Keep a running total

Weight, w kg

Frequency

Running Total

3 ≤ w < 3.5

3

3

3.5 ≤ w < 4

4

3 + 4 = 7

4 ≤ w < 4.5

6

7 + 6 = 13

4.5 ≤ w < 5

5

13 + 5 = 18

5 ≤ w < 6

2

18 + 2 = 20

The 10.5th dog is in the third interval

The median is in the interval 4 ≤ w < 4.5 

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Roger B

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