Deciding the Quadratic Method (Edexcel IGCSE Maths A (Modular))
Revision Note
Written by: Mark Curtis
Reviewed by: Dan Finlay
Deciding the Quadratic Method
If you have to solve a quadratic equation but are not told which method to use, here is a guide for what to do.
When should I solve by factorisation?
Use factorisation when the question asks to solve by factorisation
For example
part (a) Factorise 6x2 + 7x – 3
part (b) Solve 6x2 + 7x – 3 = 0
Use factorisation when solving two-term quadratic equations
For example, solve x2 – 4x = 0
Take out a common factor of x to get x(x – 4) = 0
So x = 0 and x = 4
For example, solve x2 – 9 = 0
Use the difference of two squares to factorise it as (x + 3)(x – 3) = 0
So x = -3 and x = 3
(Or rearrange to x2 = 9 and use ±√ to get x = ±3)
Factorising can often be the quickest way to solve a quadratic equation
When should I use the quadratic formula?
Use the quadratic formula when the question says to leave solutions correct to a given accuracy (2 decimal places, 3 significant figures etc)
This is a hint that the equation will not factorise
Use the quadratic formula when it may be faster than factorising
It's quicker to solve 36x2 + 33x – 20 = 0 using the quadratic formula than by factorisation
Use the quadratic formula if in doubt, as it always works
When should I solve by completing the square?
Use completing the square when part (a) of a question says to complete the square and part (b) says to use part (a) to solve the equation
Use completing the square when making x the subject of harder formulae containing both x2 and x terms
For example, make x the subject of the formula x2 + 6x = y
Complete the square: (x + 3)2 – 9 = y
Add 9 to both sides: (x + 3)2 = y + 9
Take square roots and use ±:
Subtract 3:
Completing the square always works
But it's not always quick or easy to do
Examiner Tips and Tricks
If your calculator solves quadratic equations, use it to check your solutions
If the solutions on your calculator are whole numbers or fractions (with no square roots), this means the quadratic equation does factorise
Worked Example
(a) Solve , giving your answers correct to 2 decimal places.
“Correct to 2 decimal places” suggests using the quadratic formula
Substitute a = 1, b = -7 and c = 2 into the formula
Put brackets around any negative numbers
Use a calculator to find each solution
x = 6.70156… or 0.2984...
Round your final answers to 2 decimal places
x = 6.70 or x = 0.30 (2 d.p.)
(b) Solve .
Method 1
If you cannot spot the factorisation, use the quadratic formula
Substitute a = 16, b = -82 and c = 45 into the formula
Put brackets around any negative numbers
Use a calculator to find each solution
x = or x =
Method 2
If you do spot the factorisation, (2x – 9)(8x – 5), then use that method instead
Set the first bracket equal to zero
Add 9 to both sides then divide by 2
Set the second bracket equal to zero
Add 5 to both sides then divide by 8
x = or x =
(c) By writing in the form , solve .
This question wants you to complete the square first
Find p (by halving the middle number)
Write x2 + 6x as (x + p)2 - p2
Replace x2 + 6x with (x + 3)2 – 9 in the equation
Now solve it
Make x the subject of the equation (start by adding 4 to both sides)
Take square roots of both sides (include a ± sign to get both solutions)
Subtract 3 from both sides
Find each solution separately using + first, then - second
x = - 1 or x = - 5
Even though the quadratic factorises to (x + 5)(x + 1), this is not the method asked for in the question
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