Factorising by Grouping (Edexcel IGCSE Maths A (Modular))

Revision Note

Flashcards

Factorising by Grouping

How do I factorise expressions with a common bracket?

  • Look at the expression 3x(t + 4) + 2(t + 4)

    • Both terms have a common bracket, (t + 4)

    • The whole bracket, (t + 4), can be "taken out" like a common factor:

      • (t + 4)(3x + 2)

  • This is like factorising 3xy + 2y to get y(3x + 2)

    • y represents (t + 4) above

How do I factorise by grouping?

  • Some questions may require you to form a common bracket yourself

    • For example xy + 3x + 5y + 15

      • The first two terms have a common factor of x

      • The second two terms have a common factor of 5

    • Factorising fully the first pair of terms, and the last pair of terms:

      • x(y + 3) + 5(y + 3)

    • You can now spot a common bracket of (y + 3)

      • (y + 3)(x + 5)

  • This is called factorising by grouping

Does it matter what order I group in?

  • You can often rearrange terms to factorise in a different order

    • Rewriting the same example, xy + 3x + 5y + 15, but in a different order:

      • xy + 5y + 3x + 15

      • The first pair of terms have a common factor of y

      • The second pair of terms have a common factor of 3

    • Factorising gives y(x + 5) + 3(x + 5)

      • You can now spot a common bracket, this time of (x + 5)

    • (x+5)(y+3)

      • This gives the same result as found previously

  • Some rearrangements cannot be factorised as "first pair" then "second pair"

    • For example, rewriting the above example as xy + 15 + 3x + 5y

Exam Tip

Once you have factorised something, expand it by hand to check your answer is correct.

Worked Example

Factorise ab + 3b + 2a + 6.

Method 1:
Notice that ab and 3b have a common factor of b
Notice that 2a and 6 have a common factor of 2

Factorise the first two terms, using b as a common factor

b(a + 3) + 2+ 6 

Factorise the second two terms, using 2 as a common factor 

b(a + 3) + 2(a + 3) 

(+ 3) is a common bracket 
We can now factorise out the bracket (a + 3)

(a + 3)(b + 2)

Method 2:
Notice that ab and 2a have a common factor of a
Notice that 3b and 6 have a common factor of 3

Rewrite the expression, grouping these terms together 

ab + 2a + 3b + 6

Factorise the first two terms, using a as a common factor 

a(b + 2) + 3b + 6

Factorise the second two terms, using 3 as a common factor 

a(b + 2) + 3(b + 2) 

(b + 2) is a common bracket
 We can now factorise out the bracket (b + 2)

(b + 2)(a + 3)

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Mark Curtis

Author: Mark Curtis

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.