Two-Way Tables (Cambridge (CIE) IGCSE International Maths)

Revision Note

Author

Mark Curtis

Expertise

Maths

Two Way Tables

What are two-way tables?

Two-way tables are tables that compare two types of characteristics
- For example, a college of 55 students has two year groups (Year 12 and Year 13) and two language options (Spanish and German)
- The two-way table is shown:
  
  Spanish
  German
  Year 12
  15
  10
  Year 13
  5
  25

	Spanish	German
Year 12	15	10
Year 13	5	25

How do I find probabilities from a two-way table?

Draw in the totals of each row and column
- Include an overall total in the bottom-right corner
  - It should be the sum of the totals above, or to its left (both work)
- For the example above:
  
  Spanish
  German
  Total
  Year 12
  15
  10
  25
  Year 13
  5
  25
  30
  Total
  20
  35
  55
Use this to answer probability questions
- If a random student is selected from the whole college, it will be out of 55
  - The probability a student selected from the college studies Spanish and is in Year 12 is $\frac{15}{55}$
  - The probability a student selected from the college studies Spanish is $\frac{20}{55}$
- If a random student is selected from a specific category, the denominator will be that category total
  - The probability a student selected from Year 13 studies Spanish is $\frac{5}{30}$

	Spanish	German	Total
Year 12	15	10	25
Year 13	5	25	30
Total	20	35	55

Exam Tip

Check your row and column totals add up to the overall total, otherwise all your probabilities will be wrong!

Worked Example

At an art group, children are allowed to choose between colouring, painting, clay modelling and sketching.

A total of 60 children attend and are split into two classes: class A and class B.
12 of class A chose the activity colouring and 13 of class B chose clay modelling.
A total of 20 children chose painting and a total of 15 chose clay modelling.
8 of the 30 children in class A chose sketching, as did 4 children in class B.

(a) Construct a two-way table to show this information.

Read through each sentence and fill in the numbers that are given

	Colouring	Painting	Clay modelling	Sketching	Total
Class A	12			8	30
Class B			13	4
Total		20	15		60

Use the row and column totals to fill in any obvious missing numbers

	Colouring	Painting	Clay modelling	Sketching	Total
Class A	12		15 - 13 = 2	8	30
Class B			13	4	60 - 30 = 30
Total		20	15	8 + 4 = 12	60

Use the row and column totals again to find the last few numbers

	Colouring	Painting	Clay modelling	Sketching	Total
Class A	12	30 - 12 - 2 - 8 = 8	2	8	30
Class B	30 - 12 - 13 - 4 = 1	20 - 8 = 12	13	4	30
Total	12 + 1 = 13	20	15	12	60

Write out your final answer

	Colouring	Painting	Clay modelling	Sketching	Total
Class A	12	8	2	8	30
Class B	1	12	13	4	30
Total	13	20	15	12	60

(b) Find the probability that a randomly selected child

(i) chose colouring,

(ii) is in class A, who chose sketching.

(i) We are not interested in whether the child is in class A or B
A total of 13 children chose colouring, out of 60 children

P(colouring) = $\frac{13}{60}$

(ii) 8 children in class A chose sketching
There are 60 children to select from

P(class A and sketching) = $\frac{8}{60} = \frac{2}{15}$

As we are only selecting from class B, this will be out of 30 (rather than the total of 60)
12 in class B chose painting

P(painting, from class B only) = $\frac{12}{30} = \frac{2}{5}$

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