Quadratic Sequences (Cambridge (CIE) IGCSE Maths)

Revision Note

Quadratic Sequences

What is a quadratic sequence?

  • A quadratic sequence has an n th term formula that involves n2

  • The second differences are constant (the same)

    • These are the differences between the first differences

    • For example,   3, 9, 19, 33, 51, …
      1st Differences: 6, 10, 14, 18, ...

      2nd Differences:  4,   4,   4, ...

How do I find the nth term formula for a simple quadratic sequence?

  • The sequence with the n th term formula n2 are the square numbers 

    • 1, 4, 9, 16, 25, 36, 49, ...

      • From 12, 22, 32, 42, ...

  • Finding the n th term formula comes from comparing sequences to the square numbers

    • 2, 5, 10, 17, 26, 37, 50, ... has the formula n2 + 1

      • Each term is 1 more than the square numbers

    • 2, 8, 18, 32, 50, 72, 98, ... has the formula 2n2

      • Each term is double a square number

  • It may be a simple combination of both

    • For example, doubling then adding 1

      • 3, 9, 19, 33, 51, 73, 99, ... has the formula 2n2 + 1

  • Some sequences are just the square numbers but starting later

    • 16, 25, 36, 49, ... has the formula (n + 3)2

      • Substitute in n = 1, n = 2, n = 3 to see why

  • You can also use second differences to help find the n th term

    • For the simple quadratic sequence an2 + b

      • a  is half of the second difference

    • E.g. for the sequence 3, 9, 19, 33, 51, ...

      • The second difference is 4, so a = 1 half × 4, a = 2

      • Compare the sequence 2n2, (2, 8, 18, 32, 50, ...) to the original sequence

      • The original sequence has the n th term rule 2n2 + 1

Examiner Tips and Tricks

  • You must learn the square numbers from 12 to 152

Worked Example

For the sequence 6, 9, 14, 21, 30, ....

(a) Find a formula for the nth term.

Method 1

Find the first and second differences

Sequence:   6,   9,   14,   21,   30
     First differences:   3,    5,     7,     9, ...           
    Second differences:   2,    2,     2, ...               

The second differences are constant so this must be a quadratic sequence
Compare each term to terms in the sequence n2 (the square numbers)

           n2 :  1,   4,   9,   16,   25,  ... 
 Sequence:  6,   9,   14,   21,   30, ...      

Each term is 5 more than the terms in n2, so add 5 to n2

nth term = n2 + 5

Method 2

Find the first and second differences

Sequence:   6,   9,   14,   21,   30
     First differences:   3,    5,     7,     9, ...           
    Second differences:   2,    2,     2, ...               

Halve the second difference, this is the value of a
Write down the sequence an2
Compare this to the original sequence

           1n2 :  1,   4,   9,   16,   25,  ... 
 Sequence:  6,   9,   14,   21,   30, ...      

Each term is 5 more than the terms in n2, so add 5 to n2

nth term = n2 + 5

(b) Hence, find the 20th term of the sequence.

Substitute n = 20 into n2 + 5

(20)2 + 5 = 400 + 5

The 20th term is 405

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