Solving Quadratics by Factorising (Cambridge (CIE) IGCSE Maths)
Revision Note
Written by: Jamie Wood
Reviewed by: Dan Finlay
Solving Quadratics by Factorising
How do I solve a quadratic equation using factorisation?
Rearrange it into the form ax2 + bx + c = 0
Zero must be on one side
It is easier if you rearrange so that a is positive
Factorise the quadratic and solve each bracket equal to zero
If (x + 4)(x - 1) = 0, then either x + 4 = 0 or x - 1 = 0
Because if two things multiply together to give zero,
then one or the other of them must be equal to zero
To solve
…solve first bracket = 0:
x – 3 = 0
add 3 to both sides: x = 3
…and solve second bracket = 0
x + 7 = 0
subtract 7 from both sides: x = -7
The two solutions are x = 3 or x = -7
The solutions in this example are the numbers in the brackets, but with opposite signs
What if there are numbers in front of the x's in the brackets?
The process is the same
There's a bit more work to find the solutions
You can't just write down the answers by changing the signs
To solve
…solve first bracket = 0
2x – 3 = 0
add 3 to both sides: 2x = 3
divide both sides by 2: x =
…solve second bracket = 0
3x + 5 = 0
subtract 5 from both sides: 3x = -5
divide both sides by 3: x =
The two solutions are x = or x =
What if x is a factor?
The process is the same
Just be sure to handle the x correctly
That 'x as a factor' gives one of the solutions
To solve
it may help to think of x as (x – 0) or (x)
…solve first bracket = 0
(x) = 0, so x = 0
…solve second bracket = 0
x – 4 = 0
add 4 to both sides: x = 4
The two solutions are x = 0 or x = 4
It is a common mistake to divide (cancel) both sides by x at the beginning
If you do this you will lose a solution (the x = 0 solution)
How can I use my calculator to help with solving quadratics by factorising?
You can use your calculator to help you to factorise
A calculator gives solutions to as x = and x =
Reverse the method above to factorise!
Be careful: a calculator also gives solutions to 12x2 + 2x – 4 = 0 as x = and x =
But 12x2 + 2x – 4 ≠
The right-hand side expands to 6x2 + ... not 12x2 + ...
Multiply outside the brackets by 2 to correct this
12x2 + 2x – 4 =
Examiner Tips and Tricks
Remember that you can check your solutions by either
substituting them back into the original equation
using a different quadratic method
or using a calculator
Worked Example
(a) Solve
Set the first bracket equal to zero
x – 2 = 0
Add 2 to both sides
x = 2
Set the second bracket equal to zero
x + 5 = 0
Subtract 5 from both sides
x = -5
Write both solutions together using “or”
x = 2 or x = -5
(b) Solve
Set the first bracket equal to zero
8x + 7 = 0
Subtract 7 from both sides
8x = -7
Divide both sides by 8
x =
Set the second bracket equal to zero
2x - 3 = 0
Add 3 to both sides
2x = 3
Divide both sides by 2
x =
Write both solutions together using “or”
x = or x =
(c) Solve
Do not divide both sides by x (this will lose a solution at the end)
Set the first “bracket” equal to zero
(x) = 0
Solve this equation to find x
x = 0
Set the second bracket equal to zero
5x - 1 = 0
Add 1 to both sides
5x = 1
Divide both sides by 5
x =
Write both solutions together using “or”
x = 0 or x =
Last updated:
You've read 0 of your 5 free revision notes this week
Sign up now. It’s free!
Did this page help you?