Further Graphs & Tangents (Cambridge (CIE) IGCSE Maths)

Flashcards

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  • Why does the graph of y equals 1 over x not touch the y-axis?

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Cards in this collection (13)

  • Why does the graph of y equals 1 over x not touch the y-axis?

    The graph of y equals 1 over x not touch the y-axis because on the y-axis, x equals 0. You cannot divide by zero therefore the graph does not have any values on the y-axis.

  • True or False?

    y equals a k to the power of x is an example of an exponential graph.

    True.

    y equals a k to the power of x is an example of an exponential graph; it has a variable power.
    E.g. y equals 2 cross times 3 to the power of x

  • What is an asymptote?

    An asymptote is a line on a graph that a curve gets closer and closer to but never touches.

    These may be horizontal or vertical.

    E.g. y equals 1 over x has asymptotes at y equals 0 and x equals 0.

  • True or False?

    The graph of y equals x to the power of 1 half end exponent is never below the x-axis.

    True.

    The graph of y equals x to the power of 1 half end exponent is never below the x-axis.

    It is equivalent to y equals square root of x and this means the positive root of x.

    So it is on the x-axis when x equals 0, and above the x-axis for all other (positive) values of x.

  • True or False?

    You should always use a ruler when plotting the graph of a function.

    False.

    You should only use a ruler if a graph is linear (and for drawing the axes if they are not given).

    For curves, draw a single smooth freehand curve.

  • How would you find the y-intercept of a graph using its equation?

    To find the y-intercept of a graph, you would substitute x equals 0 into the equation.

  • True or False?

    The solutions to x cubed minus 4 x equals 0 are the value(s) where the graph of y equals x cubed minus 4 x crosses the y-axis.

    False.

    The solutions to x cubed minus 4 x equals 0 are not the value(s) where the graph of y equals x cubed minus 4 x crosses the y-axis.

    x cubed minus 4 x equals 0 when y equals 0 which is the x-axis. Therefore the solutions are the values where the graph crosses the x-axis.

  • The solutions of x cubed plus x squared minus 3 equals x minus 2 are the x values of the intersections between y equals x cubed plus x squared minus 3 and which other graph?

    The solutions of x cubed plus x squared minus 3 equals x minus 2 are the x values of the intersections between y equals x cubed plus x squared minus 3 and bold italic y bold equals bold italic x bold minus bold 2.

  • True or False?

    The x values of the intersections of the two graphs y equals x plus 1 and y equals x squared plus 5 x plus 4 are the solutions of x squared plus 4 x plus 3 equals 0.

    True.

    The x values of the intersections of the two graphs y equals x plus 1 and y equals x squared plus 5 x plus 4 are the solutions of x squared plus 4 x plus 3 equals 0.

    Set the equations equal to each other and rearrange: x squared plus 5 x plus 4 equals x plus 1.

  • What is meant by a tangent to a graph?

    A tangent is a line that touches a curve at a point (and does not cross it).

  • What is meant by the gradient of a curve at a point?

    The gradient of a curve at a point is defined to be the same as the gradient of the tangent to the curve at that point.

  • True or False?

    Drawing a tangent line to a curve at a point will always give the exact gradient of the curve at that point.

    False.

    Drawing a tangent line to a curve at a point will not always give the exact gradient of the curve at that point.

    A tangent line is drawn by eye so it will give an estimate of the gradient.

    Differentiation can be used to find the exact equation of the tangent.

  • How do you estimate the gradient of a curve at a point?

    To find an estimate for the gradient of a curve at a point:

    • Draw a tangent to the curve at the point.

    • Find the gradient of the tangent using

      • Gradient = rise ÷ run

      • or difference in y ÷ difference in x.

    • The gradient of the tangent will give the estimate for the gradient of the curve at the point.