Basic Coordinate Geometry (Edexcel IGCSE Further Pure Maths)

Revision Note

Roger B

Written by: Roger B

Reviewed by: Dan Finlay

Basic Coordinate Geometry

What are Cartesian coordinates?

  • Cartesian coordinates are the coordinates used in the x-y coordinate system

    • They allow us to label where things are in a two-dimensional plane

  • In the 2D Cartesian system, the horizontal axis is labelled x  and the vertical axis is labelled y

     

What can I do with coordinates?

  • If you have two points with coordinates open parentheses x subscript 1 comma space y subscript 1 close parentheses and open parentheses x subscript 2 comma space y subscript 2 close parentheses then you should be able to find

    • The distance between the two points

    • The point that divides the line between the two points in a given ratio

    • The gradient of the line joining the two points

How do I find the distance between two points?

  • The distance d between two points with coordinates open parentheses x subscript 1 comma space y subscript 1 close parentheses and open parentheses x subscript 2 comma space y subscript 2 close parentheses can be found using the formula

    • d space equals blank square root of open parentheses x subscript 1 minus blank x subscript 2 close parentheses squared space plus space open parentheses y subscript 1 minus blank y subscript 2 close parentheses squared end root blank

  • d is the hypotenuse of a right-angled triangle

    • The differences between the x-coordinates and the y-coordinates give the other two side lengths

    • So by Pythagoras’ Theorem  d squared space equals space open parentheses x subscript 1 minus x subscript 2 close parentheses squared space plus space open parentheses y subscript 1 minus y subscript 2 close parentheses squared

How do I divide the line between two points in a given ratio?

  • The coordinates of the point dividing the line joining open parentheses x subscript 1 comma space y subscript 1 close parentheses and open parentheses x subscript 2 comma space y subscript 2 close parentheses in the ratio m colon n are given by

    • open parentheses fraction numerator n x subscript 1 plus m x subscript 2 over denominator m plus n end fraction comma space fraction numerator n y subscript 1 plus m y subscript 2 over denominator m plus n end fraction close parentheses

  • If bold italic m bold greater than bold italic n then the point is closer to open parentheses x subscript 2 comma space y subscript 2 close parentheses

  • If bold italic m bold less than bold italic n then the point is closer to open parentheses x subscript 1 comma space y subscript 1 close parentheses

How do I find the midpoint between two points?

  • The midpoint is the point halfway between the two points

    • This is just 'dividing in a given ratio' where the ratio is 1 colon 1

  • The coordinates of the midpoint will be

    • open parentheses fraction numerator x subscript 1 plus blank x subscript 2 over denominator 2 end fraction blank comma blank fraction numerator y subscript 1 plus blank y subscript 2 over denominator 2 end fraction blank close parentheses

Midpoint of a line segment

How do I find the gradient of a straight line joining two points?

  • The gradient m of a line between two points with coordinates open parentheses x subscript 1 comma space y subscript 1 close parentheses and open parentheses x subscript 2 comma space y subscript 2 close parentheses can be found using the formula

    • m equals blank fraction numerator y subscript 2 minus blank y subscript 1 over denominator x subscript 2 minus blank x subscript 1 end fraction

  • This is also known as  m equals rise over run

Worked Example

Point A has coordinates open parentheses 3 comma space minus 4 close parentheses and point B has coordinates open parentheses negative 5 comma space 8 close parentheses.

(a) Calculate the distance between points A and B.


Let A open parentheses 3 comma space minus 4 close parenthesesbe 'point 1', so x subscript 1 equals 3 and y subscript 1 equals negative 4

Let B open parentheses negative 5 comma space 8 close parentheses be 'point 2', so x subscript 2 equals negative 5 and y subscript 2 equals 8

Use the formula  d space equals blank square root of open parentheses x subscript 1 minus blank x subscript 2 close parentheses squared space plus space open parentheses y subscript 1 minus blank y subscript 2 close parentheses squared end root blank

d space equals space square root of open parentheses 3 minus open parentheses negative 5 close parentheses close parentheses squared space plus space open parentheses negative 4 minus 8 close parentheses squared end root space equals blank square root of 8 squared plus open parentheses negative 12 close parentheses squared end root space equals space square root of 64 plus 144 end root

square root of bold 208  (or bold 4 square root of bold 13 or 14.4 to 3 s.f.)

(b) Find the gradient of the line joining points A and B.


Let A open parentheses 3 comma space minus 4 close parentheses be 'point 1', so x subscript 1 equals 3 and y subscript 1 equals negative 4

Let B open parentheses negative 5 comma space 8 close parentheses be 'point 2', so x subscript 2 equals negative 5 and y subscript 2 equals 8

Use the formula m equals blank fraction numerator y subscript 2 minus blank y subscript 1 over denominator x subscript 2 minus blank x subscript 1 end fraction

m equals fraction numerator 8 minus open parentheses negative 4 close parentheses over denominator negative 5 minus 3 end fraction equals fraction numerator 12 over denominator negative 8 end fraction

Simplify the fraction

bold minus bold 3 over bold 2

(c) Find point that divides the line joining points A and B in the ratio 1 colon 3.

Let A open parentheses 3 comma space minus 4 close parenthesesbe 'point 1', so x subscript 1 equals 3 and y subscript 1 equals negative 4

Let B open parentheses negative 5 comma space 8 close parentheses be 'point 2', so x subscript 2 equals negative 5 and y subscript 2 equals 8

Use the formula  open parentheses fraction numerator n x subscript 1 plus m x subscript 2 over denominator m plus n end fraction comma space fraction numerator n y subscript 1 plus m y subscript 2 over denominator m plus n end fraction close parentheses with m equals 1 and n equals 3

open parentheses fraction numerator open parentheses 3 open parentheses 3 close parentheses plus 1 open parentheses negative 5 close parentheses close parentheses over denominator 1 plus 3 end fraction comma space fraction numerator open parentheses 3 open parentheses negative 4 close parentheses plus 1 open parentheses 8 close parentheses close parentheses over denominator 1 plus 3 end fraction close parentheses equals open parentheses fraction numerator 9 minus 5 over denominator 4 end fraction comma space fraction numerator negative 12 plus 8 over denominator 4 end fraction close parentheses 

stretchy left parenthesis 1 comma space minus 1 stretchy right parenthesis

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Roger B

Author: Roger B

Expertise: Maths

Roger's teaching experience stretches all the way back to 1992, and in that time he has taught students at all levels between Year 7 and university undergraduate. Having conducted and published postgraduate research into the mathematical theory behind quantum computing, he is more than confident in dealing with mathematics at any level the exam boards might throw at you.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.