Stationary Points & Turning Points (Edexcel IGCSE Further Pure Maths)
Revision Note
Written by: Paul
Reviewed by: Dan Finlay
Stationary Points & Turning Points
What is the difference between a stationary point and a turning point?
A stationary point is a point at which the derivative of a function is equal to zero
The tangent to the curve of the function is horizontal (gradient = 0)
A turning point is a point at which
the derivative of a function is equal to zero
AND the derivative changes sign (from negative to positive, or positive to negative)
i.e. the curve changes from ‘going upwards’ to ‘going downwards’ (or vice versa)
Turning points will either be (local) minimum or (local) maximum points
All turning points are also stationary points
But not all stationary points are turning points
How do I find stationary points and turning points?
For the function , stationary points can be found using the following process
STEP 1
Find the derivative,STEP 2
Solve the equationThe solution(s) are the -coordinate(s) of any stationary points
Remember, 'stationary points' includes turning points
STEP 3
Find the corresponding -coordinates (if necessary)Substitute each-coordinate(s) into
If the question only asks for the -coordinates, you can skip this step!
More work is needed to find if a stationary point is a turning point
i.e. if it is a (local) maximum or (local) minimum
See the following note
Testing for Local Minimum & Maximum Points
What are local minimum and maximum points?
Local minimum and maximum points are two types of stationary point
The derivative at stationary points equals zero
i.e.
But not all points with a zero derivative are maximum or minimum points
A local minimum point,
will have the lowest value of in the local vicinity of the value
But may reach a lower value further away
A local maximum point,
will have the highest value of in the local vicinity of the value
But may reach a higher value further away
A global maximum (or global minimum) point
has the highest (or lowest) value of for all values of in the domain of
A global maximum (or minimum) may not be a local maximum (or minimum)
and vice versa
Not all functions have a global maximum (or minimum)
e.g. some functions tend to infinity as tends to infinity
or as approaches some other value (vertical asymptotes)
How can I use the derivative to identify local minimum & maximum points?
The nature of a stationary point can be determined using the derivative
For the function …
STEP 1
Find and solveThe solutions are the the -coordinates of any stationary points
STEP 2
Find the sign of the derivative just either side of each stationary pointi.e. evaluate and for small
Choose a convenient value for
Just make sure you don't 'jump over' any other stationary points!
At a local minimum point
the derivative changes from negative to positive
At a local maximum point
the derivative changes from positive to negative
If the derivative does not change sign at the point
(i.e. if it is positive on both sides or negative on both sides)
then the point is not a local minimum or a local maximum
But it is still a stationary point if there
What is the second derivative?
It is possible to differentiate a function more than once
If you differentiate , you find its (first) derivative
e.g. the (first) derivative of is
Then you can differentiate the derivative again to find the second derivative
e.g. the derivative of is
so the second derivative of is
The second derivative can be used to test the nature of a stationary point
How can I use the second derivative to identify local minimum & maximum points?
STEP 1
Find and solveThe solutions are the the -coordinates of any stationary points
STEP 2
Find the second derivativeDo this by differentiating from Step 1
STEP 3
Find the value of at each of the stationary pointsi.e., by substituting the -coordinate of each point into
If
then the stationary point is a local minimum
If
then the stationary point is a local maximum
If
then the test does not tell you anything
the stationary point may be a local maximum, a local minimum, or neither
In this case, use the first derivative test instead
Examiner Tips and Tricks
Don't just assume that a zero derivative corresponds to a maximum or minimum point
Especially if a question asks you to justify that a point is a maximum or minimum
The second derivative test is usually much quicker for identifying maximum and minimum points
But it is good to understand how to use the first derivative test as well
Your calculator may be able to show graphs of functions
You can use this to check your work
Worked Example
Find the coordinates and determine the nature of any stationary points on the graph of , where is the function defined by .
Start by finding
Solve to find the -coordinates of any stationary points
Substitute into to find the corresponding -coordinates
So the stationary points are and
Method 1: using the second derivative to test the points
Differentiate to find the second derivative
Now substitute in the -coordinates of the two stationary points
This will give the value of the second derivative at those points
That is less than zero, so is a local maximum point
That is greater than zero, so is a local minimum point
Method 2: using the first derivative to test the points
Test the values of at either side of the stationary points
(Note that, where applicable, is a very convenient test value!)
At the derivative changes from positive to negative, so that is a local maximum point
At the derivative changes from negative to positive, so that is a local minimum point
Note that for this function both stationary points are also turning points
is a local maximum point
is a local minimum point
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