How to Test for Anions (Edexcel IGCSE Chemistry (Modular))

Revision Note

Test yourself

Tests for anions

  • Negatively charged non-metal ions are known as anions

  • You must be able to describe the tests for the following ions:

    • Carbonate ions, CO32– 

    • Halide ions, Cl , Br , I 

    • Sulfate ions, SO42– 

Test for carbonate ions

  • Carbonate compounds contain the carbonate ion, CO32-

  • The test for the carbonate ion is:

    • Add dilute acid 

    • Bubble the gas released through limewater

    • Limewater turns cloudy if the carbonate ion is present

  • If a carbonate compound is present then fizzing / effervescence should be seen as CO2 gas is produced, which forms a white precipitate of calcium carbonate when bubbled through limewater:

CO32- (aq) + 2H(aq) → CO(g) + H2O (l)

CO(g) + Ca(OH)2 (aq) → CaCO3(s) + H2O(l)

  • The white precipitate turns limewater cloudy 

Testing for carbonate ions

The diagram shows carbon dioxide being bubbled through limewater, and the limewater turning milky / cloudy to confirm the presence of carbon dioxide

Limewater turns milky in the presence of carbon dixoide caused by the formation of insoluble calcium carbonate

Examiner Tip

  • If you are asked to describe the test for carbonate ions, make sure that you say:

    • Bubble the gas produced through limewater, which turns cloudy if the carbonate ion is present

  •   Just saying that limewater turns cloudy is not enough

    • This isn't describing the test, it is stating the result

Test for halide ions

  • Halide ions are the negative ions / anions formed by the elements in Group 7 

  • The test for the halide ions is:

    • Acidify the sample with nitric acid

    • Add silver nitrate solution, AgNO3,  

    • A silver halide precipitate forms if a halide ion is present

      • The precipitate is indicated by the state symbol (s)

  • The colour of the silver halide precipitate depends on the halide ion:

    • The chloride ion forms a white precipitate of silver chloride 

potassium chloride +  silver nitrate   →  potassium nitrate + silver chloride 

KCl (aq)   +     AgNO3 (aq)   →  KNO3 (aq)  +  AgCl (s) 

  • The bromide ion forms a cream precipitate of silver bromide 

potassium bromide +  silver nitrate   →  potassium nitrate + silver bromide

KBr (aq)   +     AgNO3 (aq)   →  KNO3 (aq)  +  AgBr (s) 

  • The iodide ions forms a yellow precipitate of silver iodide 

potassium iodide +  silver nitrate   →  potassium nitrate + silver iodide

KI (aq)   +     AgNO3 (aq)   →  KNO3 (aq)  +  AgI (s) 

Testing for halide ions

The diagram shows chloride ions forming a whilte precipitate, bromide ions forming a cream precipitate and iodide ions forming a yellow precipitate

Each silver halide produces a precipitate of a different colour

Examiner Tip

The acidification step in the halide ion test must be done with nitric acid rather than hydrochloric acid.

HCl contains the chloride ion which would interfere with the results.

Test for sulfate ions

  • Sulfate compounds contain the sulfate ion, SO42-

  • The test for the sulfate ion is:

    • Acidify the sample with dilute hydrochloric acid 

    • Add a few drops of barium chloride solution

    • A white precipitate of barium sulfate is formed, if the sulfate ion is present

Ba2+ (aq) + SO42- (aq) → BaSO4 (s)

  • The test can also be carried out with barium nitrate solution

Testing for sulfate ions 

The diagram shows barium chloride solution being added to a sample, which forms a white precipitate if sulfate ions are present

A white precipitate of barium sulfate is a positive result for the presence of sulfate ions

Examiner Tip

HCl is added first to remove any carbonates which may be present which would also produce a precipitate and interfere with the results.

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