A student needs to find the value of x in the formula (NH4)2SO4.Fe2(SO4)3.xH2O
He uses this apparatus.
The hydrated solid decomposes when heated gently.
The equation for the reaction is
(NH4)2SO4.Fe2(SO4)3.xH2O —> (NH4)2SO4.Fe2(SO4)3 + xH2O
The table shows the student's results.
mass of empty test tube in g |
22.04 |
mass of test tube and (NH4)2SO4.Fe2(SO4)3.xH2O in g |
34.09 |
mass of test tube and (NH4)2SO4.Fe2(SO4)3 in g |
28.69 |
(i)
Calculate the mass of (NH4)2SO4.Fe2(SO4)3 produced by heating.
(1)
mass of (NH4)2SO4.Fe2(SO4)3 = .............................. g
(ii)
Calculate the mass of water produced.
(1)
mass of water = ..................................... g
(iii)
Calculate the value of x.
[Mr of (NH4)2SO4.Fe2(SO4)3 = 532 and Mr of H2O = 18]
Give your answer to the nearest whole number.
(4)
Value of x = .....................................