Each tablet contains the same number of moles of CaCO3 and MgCO3. One tablet reacted with excess hydrochloric acid to produce 0.24 dm3 of carbon dioxide at r.t.p.
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
MgCO3 + 2HCl → MgCl2 + CO2 + H2O
i)
Calculate how many moles of CaCO3 there are in one tablet.
Number of moles CO2 =
Number of moles of CaCO3 and MgCO3 =
Number of moles of CaCO3 =
[3]
ii)
Calculate the volume of hydrochloric acid, 1.0 mol / dm3, needed to react with one tablet.
Number of moles of CaCO3 and MgCO3 in one tablet =
Use your answer to (c)(i).
Number of moles of HCl needed to react with one tablet =
Volume of hydrochloric acid, 1.0 mol / dm3, needed to react with one tablet =
[2]