Calculate Concentrations of Solutions (Edexcel IGCSE Chemistry)
Revision Note
Written by: Stewart Hird
Reviewed by: Lucy Kirkham
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Calculate Concentrations of Solutions
A solute is a solid substance that dissolves into a liquid
The amount of solute can be expressed in grams (g) or moles (mol)
A solvent is the liquid that a solute dissolves in
The amount / volume of a solvent is measured in cm3 or dm3
Most chemical reactions occur between solutes which are dissolved in solvents, such as water or an organic solvent
A solution is the mixture formed when a solute dissolves in a solvent
The amount / volume of a solution measured in cm3 or dm3
Concentration refers to the amount of solute there is in a specific volume of the solvent
The greater the amount of solute in a given volume, the greater the concentration
Concentration is sometimes commonly referred to as strength
For example, dissolving more coffee in hot water results in a stronger coffee
Typically, concentration is expressed in terms of the amount of substance per dm3
Therefore, the units of concentration are:
g / dm3
mol / dm3
It is more useful to a chemist to express concentration in terms of moles per unit volume rather than mass per unit volume
To calculate concentration in mol / dm3 we use the following equation:
The concentration-moles formula triangle
Volumes are often expressed in cm3, but dm3 must be used when calculating concentration
To convert cm3 to dm3, divide by 1000
To convert dm3 to cm3, multiply by 1000
Converting between cm3 and dm3
Worked Example
Calculate the amount of solute, in moles, present in 2.5 dm3 of a solution whose concentration is 0.2 mol / dm3.
Answer:
Write down the information you are given in the question:
Concentration of solution: 0.2 mol / dm3
Volume of solution: 2.5 dm3
Calculate the number of moles:
Moles = concentration x volume
Moles = 0.2 x 2.5 = 0.5 mol
Worked Example
Calculate the concentration of a solution of sodium hydroxide, NaOH, in mol / dm3, when 80 g is dissolved in 500 cm3 of water.
Relative atomic masses, Ar: Na = 23; H = 1; O = 16
Answer:
Calculate the Mr of NaOH:
23 + 16 + 1 = 40
Determine the number of moles of NaOH:
40 g = 1 mole
So, 80 g = 2 moles
Convert cm3 to dm3:
= 0.5 dm3
Calculate the concentration:
Concentration =
Concentration = = 4 mol / dm3
Worked Example
25.0 cm3 of 0.050 mol / dm3 sodium carbonate was completely neutralised by 20.00 cm3 of dilute hydrochloric acid. Calculate the concentration in mol / dm3 of the hydrochloric acid.
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
Answer:
Calculate the moles of sodium carbonate:
Moles of Na2CO3 = concentration x volume
Remember: The volume needs to be in dm3
Moles of Na2CO3 = 0.05 x = 0.00125
Calculate the moles of hydrochloric acid:
The balanced symbol equation shows that 1 mole of Na2CO3 reacts with 2 moles of HCl
So, 0.00125 moles of Na2CO3 reacts with 0.00250 moles of HCl
Calculate the concentration of hydrochloric acid:
Concentration =
Remember: The volume needs to be in dm3
20 cm3 ÷ 1000 = 0.02 dm3
Concentration = = 0.125 mol / dm3
Examiner Tips and Tricks
Don't forget your unit conversions:
To go from cm3 to dm3 : divide by 1000
To go from dm3 to cm3 : multiply by 1000
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