Bond Breaking & Bond Forming (Cambridge (CIE) IGCSE Chemistry)
Revision Note
Written by: Alexandra Brennan
Reviewed by: Stewart Hird
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Bond breaking & bond forming
Extended tier only
Whether a reaction is endothermic or exothermic depends on the difference between the energy needed to break existing bonds and the energy released when the new bonds are formed
Bond breaking is always an endothermic process as energy needs to be taken in from the surroundings to break the chemical bonds
Bond making is always an exothermic process as energy is transferred to the surroundings as the new bond is formed
Exothermic reactions
If more energy is released than is absorbed, then the reaction is exothermic
More energy is released when new bonds are formed than energy required to break the bonds in the reactants
The change in energy is negative since the products have less energy than the reactants
Therefore, an exothermic reaction has a negative ΔH value
This can be shown in reaction pathway diagrams and calculations
Making new chemical bonds releases energy which radiates outwards from the reaction to the surroundings in the form of heat
Endothermic reactions
If more energy is absorbed to break bonds than is released to form new bonds, this reaction is endothermic overall
The change in energy is positive since the products have more energy than the reactants
The symbol ΔH is used to show the change in heat energy
H is the symbol for enthaply, which is a measure of the total heat of reaction of a chemical reaction
Therefore, an endothermic reaction has a positive ΔH value
This can be shown in reaction pathway diagrams and calculations
Breaking chemical bonds requires energy which is taken in from the surroundings in the form of heat
Bond energy calculations
Extended tier only
Each chemical bond has specific bond energy associated with it
This is the amount of energy required to break the bond or the amount of energy given out when the bond is formed
This energy can be used to calculate how much heat would be released or absorbed in a reaction
To do this it is necessary to know the bonds present in both the reactants and products
How to complete bond energy calculations
Write a balanced equation if none is present already
Optional - draw the displayed formula in order to identify the type and number of bonds more easily
Add together all the bond energies for all the bonds in the reactants – this is the ‘energy in’
Add together the bond energies for all the bonds in the products – this is the ‘energy out’
Calculate the enthalpy change:
Enthalpy change (ΔH) = Energy taken in - Energy given out
Worked Example
Hydrogen and chlorine react to form hydrogen chloride gas:
H2 + Cl2 ⟶ 2HCl
The bond energies are given in the table below.
Bond | Energy (kJ) |
---|---|
H–H | 436 |
Cl–Cl | 242 |
H–Cl | 431 |
Calculate the overall energy change for this reaction and use this value to explain whether the reaction is exothermic or endothermic.
Answer:
Calculate the energy in
436 + 242 = 678 (kJ)
Calculate the energy out
2 x 431 = 862 (kJ)
Calculate the energy change
678 - 862 = –184 (kJ)
Since the energy change is a negative number, energy is being released (to the surroundings)
Therefore, the reaction is exothermic
Examiner Tips and Tricks
When calculating enthalpy change using bond energies, it is helpful to write down a displayed formula equation for the reaction before identifying the type and number of bonds, to avoid making mistakes.
So, the reaction for the above worked example is:
H-H + Cl-Cl → H-Cl + H-Cl
Worked Example
Hydrogen reacts with iodine to form hydrogen iodide.
H2 + I2 ⟶ 2HI
The relevant bond energies are shown in the table below.
Bond | Energy (kJ) |
---|---|
H–I | 295 |
H–H | 436 |
I–I | 151 |
Calculate the overall energy change for this reaction and use this value to explain why the reaction is exothermic.
Answer:
Calculate the energy in
436 + 151 = 587 (kJ)
Calculate the energy out
2 x 295 = 590 (kJ)
Calculate the energy change
587 - 590 = -3 (kJ)
The reaction is exothermic because:
More energy is released than taken in
Worked Example
Hydrogen bromide decomposes to form hydrogen and bromine:
2HBr ⟶ H2 + Br2
The overall energy change for this reaction is +103 kJ.
The relevant bond energies are shown in the table below.
Bond | Energy (kJ) |
---|---|
H–Br | 366 |
Br–Br |
|
H–H | 436 |
Calculate the bond energy of the Br–Br bond.
Answer:
Calculate the energy in
2 x 366 = 732 (kJ)
State the energy out
436 + Br–Br
Overall energy change = energy in - energy out
+103 = 732 - (436 + Br–Br)
+103 = 732 - 436 - Br–Br
Calculate the bond energy of the Br–Br bond
Br–Br = 732 - 436 - 103
Br–Br = +193 (kJ)
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