Hooke's Law (OCR Gateway GCSE Physics: Combined Science)

Revision Note

Katie M

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Katie M

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Hooke's Law

  • The relationship between the extension of an elastic object and the force applied is defined by Hooke's Law
  • Hooke's Law states that:

   The extension of an elastic object is directly proportional to the force applied, up to the limit of proportionality

  • Directly proportional means that as the force is increased, the extension increases 
    • If the force is doubled, then the extension will double
    • If the force is halved, then the extension will also halve
  • The limit of proportionality is the point beyond which the relationship between force and extension is no longer directly proportional 
    • This limit varies according to the material

Load extension and force, downloadable AS & A Level Physics revision notes

Hooke's Law states that a force applied to a spring will cause it to extend by an amount proportional to the force

  • Hooke's Law is defined by the equation:

F = k × x

  • Where:
    • F = force in newtons (N)
    • k = spring constant in newtons per metres (N/m)
    • x = extension in metres (m)

  • The symbol x can represent either the extension or compression of an elastic object
  • The Hooke's law equation can be rearranged using the following formula triangle:

Hookes Law Formula Triangle GCSE, downloadable IGCSE & GCSE Physics revision notes

  • The spring constant represents how stiff the spring is
    • The higher the spring constant, the higher the stiffness

  • The extension of an object can be calculated by:

Final length – Original length

  • The extension of the spring can be measured by marking the position of bottom of the unstretched spring
  • When the spring is stretched the final length must be measured from the bottom of the spring

Extension worked example, IGCSE & GCSE Physics revision notes

The extension measured from its final and original length

Worked example

The figure below shows the forces acting on a child who is balancing on a pogo stick. The child and pogo stick are not moving.Hookes Law Worked Example, downloadable IGCSE & GCSE Physics revision notesThe spring constant of the spring on the pogo stick is 4900 N/m. The weight of the child causes the spring to compress elastically from a length of 40 cm to a new length of 33 cm. Calculate the weight of the child.

Step 1: List the known quantities

    • Spring constant, k = 4900 N/m
    • Original length = 40 cm
    • Final length = 33 cm

Step 2: Write the relevant equation

F = kx

Step 3: Calculate the extension, x

x = final length – original length = 40 – 33 = 7 cm

Step 4: Convert any units

    • Since the spring constant is given in N/m, x must be in metres (m)

7 cm = 0.07 m

Step 5: Substitute the values into the Hooke's Law equation

F = 4900 × 0.07 = 343 N

Examiner Tip

Look out for unit conversions! Unless the spring constant is given in N/cm, make sure the extension is converted into metres (÷ 100) before substituting values into the Hooke's Law equation. 

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.