Momentum (OCR GCSE Combined Science A (Gateway): Physics): Revision Note

Exam code: J250

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Updated on

Momentum

Higher Tier Only

Calculating Momentum

  • A moving object has momentum which is defined by the equation:

p = mv

  • Where:

    • p = momentum in kilogram metre per second (kg m/s)

    • m = mass in kilograms (kg)

    • v = velocity in metres per second (m/s)

  • This means that an object at rest (i.e. v = 0) has no momentum

  • Momentum keeps an object moving in the same direction, making it difficult to change the direction of an object with a large momentum

  • Since velocity is a vector this means that the momentum of an object also depends on its direction of travel

  • This means that momentum can be either positive or negative

    • If an object travelling to the right has positive momentum, an object travelling in the opposite direction (to the left) will have negative momentum

A 60 g tennis ball travelling right at 2 m/s: p = mv = 0.12 kg m/s. Travelling left at −2 m/s gives p = −0.12 kg m/s; opposite velocity means negative momentum.
The tennis ball's momentum is negative when it moves in the opposite direction to which it initially was travelling in
  • Therefore, the momentum of an object will change if:

    • the object accelerates (speeds up) or decelerates (slows down)

    • the object changes direction

    • the mass of the object changes

Worked Example

Which object has the most momentum?

Comparison diagram: a 60-gram tennis ball travelling right at 75 metres per second and a 3-kilogram brick travelling right at 1.5 metres per second. The question asks which object has the most momentum.

Answer:

Worked-example answer showing both objects have momentum of 4.5 kilogram metres per second: 0.06 kilograms times 75 metres per second for the tennis ball, and 3 kilograms times 1.5 metres per second for the brick.
  • Both the tennis ball and the brick have the same momentum

  • Even though the brick is much heavier than the ball, the ball is travelling much faster than the brick

  • This means that on impact, they would both exert a similar force (depending on the time it takes for each to come to rest)

Examples of Momentum

  • Examples of momentum in an event are collisions

  • Objects will either:

    • Collide and bounce apart

    • Collide and stick together, moving off in the same direction

  • When the objects bounce apart:

    • Each object will have a different velocity depending on its mass and the initial momentum of the system

  • When the objects stick together:

    • They will have a combined mass and velocity

  • Momentum is always conserved in a collision

Before a collision, a purple and an orange ball move towards each other. After an elastic collision they move apart; after an inelastic collision they stick together and move right.
Objects can bounce apart or stick together after a collision

Conservation of Momentum

  • The principle of conservation of momentum states that:

In a closed system, the total momentum before an event is equal to the total momentum after the event

  • A closed system means there are no external forces (e.g. friction) acting on the objects

  • In other words:

Total momentum before a collision = total momentum after a collision

  • A system is a certain number of objects under consideration

    • This can be just one object or multiple objects

  • Since momentum is a vector quantity, a system of objects moving in opposite directions (e.g. towards each other) at the same speed will have an overall momentum of 0 since they will cancel out

    • Momentum is always conserved over time

  • The diagram below shows two masses with velocity u and M at rest (ie. zero velocity)

Before collision: mass m moves right at velocity u towards stationary mass M. After collision: m moves left at velocity v and M moves right at velocity V; momentum changes from m times u to M times V minus m times v.
The momentum of a system before and after a collision

Worked Example

The diagram shows a car and a van, just before and just after the car collided with the van, which is initially at rest.

Collision diagram: before, a 990-kilogram car travels right at 10 metres per second towards a stationary 4200-kilogram van; after, the car travels right at 2 metres per second and the van’s velocity is unknown.

Use the idea of conservation of momentum to calculate the velocity of the van when it is pushed forward by the collision.

Answer:

Step 1: State the principle of conservation of momentum

  • In a closed system, the total momentum before an event is equal to the total momentum after the event

Step 2: Calculate total momentum before the collision

p = mv

  • Momentum of the car:

    p = 990 × 10 = 9900 kg m/s

  • Momentum of the van:

The van is at rest, therefore v = 0 m/s and p = 0 kg m/s

  • Total momentum before:

pbefore = 9900 + 0 = 9900 kg m/s

Step 3: Calculate the momentum after the collision

  • Momentum of the car:

p = 990 × 2 = 1980 kg m/s

  • Momentum of the van:

p = 4200 × v

  • Total momentum after:

pafter = 1980 + 4200v

Step 4: Rearrange the conservation of momentum equation for the velocity of the van

pbefore = pafter

9900 = 1980 + 4200v

9900 - 1980 = 4200v

v = 990019804200 = 1.9 m/s

Newton's Third Law & Momentum

  • Newton’s third law of motion states:

Whenever two bodies interact, the forces they exert on each other are equal and opposite

  • This means:

    • When one object exerts a force on another object, the second object will exert an equal force on the first object in the opposite direction

    • When two objects collide, both objects will react, generally causing one object to speed up (gain momentum) and the other object to slow down (lose momentum)

Two trolleys, A on the left and B on the right, connected by a compressed spring. Arrows show opposite forces: F sub B–A acts left on A and F sub A–B acts right on B.
Newton's third law can be applied to collisions
  • Consider the collision between two trolleys, A and B:

    • When trolley A exerts a force on trolley B, trolley B will exert an equal force on trolley A in the opposite direction

  • In this case:

FB–A = –FA–B

  • While the forces are equal in magnitude and opposite in direction, the accelerations of the objects are not necessarily equal in magnitude

  • From Newton's second law, acceleration depends upon both force and mass, this means:

    • For objects of equal mass, they will have equal accelerations

    • For objects of unequal mass, they will have unequal accelerations

Examiner Tips and Tricks

Remember the units of momentum as kg m/s, which is the product of the units of mass (kg) and velocity (m/s). The direction you take as positive is completely up to you in the exam. In general, the right and upwards are taken as positive, and down or to the left as negative.

If an exam question asks you to analyse a collision, follow these tips for full marks:

  • Always consider the motion before and after the collision and state:

    • The velocities of each object

    • The direction each object moves

  • Describe any energy transfers that occur during the collision

    • For example, energy may be transferred to the thermal store of the surroundings, including by sound

If it is not given in the question already, drawing a diagram of before and after helps keep track of all the masses and velocities (and directions) in the conservation of momentum questions.

Remember, with Newton's third law, the two forces should always be from different objects.

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Katie M

Author: Katie M

Expertise: Curriculum Expert

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Reviewer: Caroline Carroll

Expertise: Head of Content Delivery

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about delivering high-quality resources to help students achieve their full potential.