Nuclear Equations for Fission & Fusion (WJEC GCSE Physics)

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Balancing Nuclear Equations for Fission & Fusion

Nuclear Fission Equations

  • An example of a fission reaction is uranium-235 being bombarded with a neutron to produce two daughter nuclei, three neutrons and energy in the form of gamma radiation
  • This can be written in the form of an equation:

straight U presubscript 92 presuperscript 235 space plus space straight n presubscript 0 presuperscript 1 space rightwards arrow space Kr presubscript 36 presuperscript 92 space plus space Ba presubscript 56 presuperscript 141 space plus thin space 3 straight n presubscript 0 presuperscript 1 + energy

  • Where:
    • straight U presubscript 92 presuperscript 235 is an isotope of uranium
    • n presubscript 0 presuperscript 1 space is a neutron
    • space Kr presubscript 36 presuperscript 92 is an isotope of krypton (one daughter nucleus)
    • Ba presubscript 56 presuperscript 141 is an isotope of barium (the other daughter nucleus)
  • The sum of the top (nucleon) numbers on the left-hand side equals the sum of the top number on the right-hand side: 235 + 1 = 92 + 141 + (3 × 1)
  • The same is true for the lower (proton) numbers: 92 + 0 = 36 + 56 + (3 × 0)

Representing Nuclear Fission Reactions

Nuclear fission

A neutron is fired at a target nucleus, causing it to split into two fission products plus 3 neutrons

  • The above equation represents a fission reaction where
    • A uranium nucleus absorbs a neutron
    • It splits into two smaller nuclei – a krypton nucleus and a barium nucleus
    • Three neutrons are released in the process, along with a large amount of energy

Nuclear Fusion Equations

  • An example of a fusion reaction is deuterium and tritium nuclei combining at high energies to produce a helium nucleus, a neutron and a lot of energy
  • This can be written as a nuclear equation:

straight H presubscript 1 presuperscript 2 space plus space straight H presubscript 1 presuperscript 3 space rightwards arrow space He presubscript 2 presuperscript 4 space plus space straight n presubscript 0 presuperscript 1 + energy

  • Where:
    • straight H presubscript 1 presuperscript 2 is deuterium (an isotope of hydrogen with 1 proton and 1 neutron)
    • straight H presubscript 1 presuperscript 3 is tritium (an isotope of hydrogen with 1 proton and 2 neutrons)
    • He presubscript 2 presuperscript 4 is a stable helium nucleus
    • straight n presubscript 0 presuperscript 1 is a neutron
  • The sum of the top (nucleon) numbers on the left-hand side equals the sum of the top number on the right-hand side: 2 + 3 = 4 + 1
  • The same is true for the lower (proton) numbers: 1 + 1 = 2 + 0

Representing Nuclear Fusion Reactions

Nuclear Fusion

Isotopes of hydrogen, deuterium and tritium, can fuse into a helium nucleus and a neutron plus the release of energy

  • The above equation represents a fusion reaction where
    • A deuterium nucleus collides with a tritium nucleus
    • They become close enough to fuse into a helium-4 nucleus
    • A neutron is released in the process, along with a large amount of energy

Worked example

A possible nuclear equation for the fission of uranium-235 is

straight U presubscript 92 presuperscript 235 space plus space straight n presubscript 0 presuperscript 1 space rightwards arrow space Rb presubscript 37 presuperscript 96 space plus space Cs presubscript 55 presuperscript 137 space plus space straight N straight n presubscript 0 presuperscript 1

Calculate the number of neutrons N released in this reaction.

Answer:

Step 1: Calculate the nucleon number on the left side of the equation

235 + 1 = 236

Step 2: Calculate the nucleon number on the right side of the equation 

96 + 138 + (N × 1) = 233 + N

Step 3: Equate the nucleon number for both sides of the equation 

236 = 233 + N

Step 4: Rearrange for the number of neutrons, N

N = 236 – 233 = 3

Worked example

One of the nuclear fusion reactions that occurs in the Sun is shown below.

straight H presubscript..... end presubscript presuperscript..... end presuperscript space plus space straight H presubscript..... end presubscript presuperscript..... end presuperscript space rightwards arrow space He presubscript 2 presuperscript 3 space plus thin space straight gamma

Complete the equation.

Answer:

Step 1: Recall the proton number for hydrogen and the meaning of isotope

  • Isotopes are elements with the same proton number but different nucleon numbers
  • Hydrogen has a proton number of 1
  • So, the bottom number for both hydrogen nuclei is 1

Step 2: Determine the nucleon numbers of the hydrogen isotopes

  • The total nucleon number on the right side of the equation is 3, as gamma is an electromagnetic wave so does not have a nucleon or proton number
  • The hydrogen nuclei on the left side are isotopes
  • Therefore, their nucleon numbers must be 1 and 2

Step 3: Write the equation out in full and check both sides

straight H presubscript 1 presuperscript 1 space plus space straight H presubscript 1 presuperscript 2 space rightwards arrow space He presubscript 2 presuperscript 3 space plus thin space straight gamma

  • Nucleon numbers: 1 + 2 = 3 + 0
  • Proton numbers: 1 + 1 = 2 + 0
  • The numbers balance, so the equation must be correct

Writing Nuclear Equations for Fission & Fusion

Higher Tier

  • Given some information about different nuclei, you could be asked to write full, balanced nuclear equations for particular nuclear reactions, such as fission or fusion
  • Remember the key rule for writing balanced equations:

The sum of the nucleon numbers and proton numbers must be equal before and after the reaction

  • In nuclear fusion equations:
    • Two small nuclei react
    • One larger nucleus is produced
    • There may be a neutron released, but not always
  • In nuclear fission equations:
    • One large nucleus absorbs a neutron
    • Two smaller nuclei are produced
    • Two or three neutrons are always released
  • The worked examples below illustrate the kinds of questions that could be asked

Worked example

The diagram below shows an example of a nuclear fusion reaction in which two isotopes of helium open parentheses He close parentheses fuse together to make a beryllium-7 open parentheses Be presubscript 4 presuperscript 7 close parentheses nucleus plus the emission of a gamma ray.

2-9-worked-example---writing-fusion-equationsworked-example---writing-fusion-equations

Write a balanced nuclear equation for this fusion reaction.

Answer:

Step 1: Write a word equation using the information in the question

  • Underline or highlight the keywords in the question:

"Two isotopes of helium fuse together to make a beryllium-7 nucleus plus the emission of a gamma ray"

  • Write a word equation for the reaction:

helium + helium → beryllium-7 + gamma

Step 2: Work out the symbols for the helium isotopes

  • The straight X presubscript straight Z presuperscript straight A notation for beryllium-7 is Be presubscript 4 presuperscript 7
    • This means it contains 4 protons and 3 neutrons
    • Using the diagram, we can deduce the light particles are protons and the dark particles are neutrons
  • Isotopes are elements with the same proton number but different nucleon numbers
  • So, both helium nuclei must have a proton number of 2
  • The two helium isotopes are therefore: 
    • Helium-3:  He presubscript 2 presuperscript 3 (2 protons, 1 neutron)
    • Helium-4:  He presubscript 2 presuperscript 4 (2 protons, 2 neutrons)
  • Gamma particles have no mass or charge so have nucleon and proton numbers of 0

Step 3: Write the balanced nuclear equation using the correct symbols

He presubscript 2 presuperscript 3 space plus space He presubscript 2 presuperscript 4 space rightwards arrow space Be presubscript 4 presuperscript 7 space plus space straight gamma presubscript 0 presuperscript 0

  • Nucleon numbers: 3 + 4 = 7 + 0
  • Proton numbers: 2 + 2 = 4 + 0
  • The numbers balance, so the equation must be correct

Worked example

The table shows some information about different nuclei involved in a nuclear fission reaction.

Nucleus Symbol Number of protons Number of neutrons
Uranium U 92 143
Barium Ba 56 88
Krypton Kr 36 53

 

A nucleus of uranium undergoes fission when bombarded with a slow-moving neutron (n) causing it to split into the daughter nuclei barium and krypton plus the release of further neutrons.

Write a balanced nuclear equation for this fission reaction.

......... space plus space......... space rightwards arrow space......... space plus space......... space plus space.........

Answer:

Step 1: Write a word equation using the information in the question

  • Underline or highlight the keywords in the question which tell us about the nuclei on the left-hand side (LHS):

"A nucleus of uranium undergoes fission when bombarded with a slow-moving neutron"

  • Underline or highlight the keywords in the question which tell us about the nuclei on the right-hand side (RHS):

"causing it to split into the daughter nuclei barium and krypton plus the release of further neutrons"

  • Write a word equation for the reaction:

uranium + neutron → barium + krypton + neutrons

Step 2: Determine the correct symbols for each nucleus or particle

  • We need to write each nucleus or particle in straight X presubscript straight Z presuperscript straight A notation
  • It can be useful to draw an extra row and column onto the table to do this (green indicates the changes made to the table):
Nucleus Symbol straight X presubscript straight Z presuperscript straight A Number of protons Z Number of neutrons Nucleon number A
Uranium straight U presubscript 92 presuperscript 235 92 143 92 + 143 = 235
Barium Ba presubscript 56 presuperscript 144 56 88 56 + 88 = 144
Krypton Kr presubscript 36 presuperscript 89 36 53 36 + 53 = 89
Neutron straight n presubscript 0 presuperscript 1 0 1 0 + 1 = 1

 

Step 3: Write the nuclear equation using the symbols

straight U presubscript 92 presuperscript 235 space plus space straight n presubscript 0 presuperscript 1 space rightwards arrow space Ba presubscript 56 presuperscript 144 space plus space Kr presubscript 36 presuperscript 89 space plus space straight n presubscript 0 presuperscript 1

Step 4: Balance the equation by checking the total nucleon and proton numbers on each side

  • Total proton number:
    • On the LHS: 92 + 0 = 92
    • On the RHS: 56 + 36 + 0 = 92
  • The total proton number is the same on both sides
  • Total nucleon number:
    • On the LHS: 235 + 1 = 236
    • On the RHS: 144 + 89 + 1 = 234
  • There is a difference of 2, and the question states there is a "release of further neutrons"
  • This means there must be 2 extra neutrons released i.e. 3 neutrons in total
  • To represent this, we put a 3 in front of the neutron symbol on the RHS, so, the fully balanced equation is:

straight U presubscript 92 presuperscript 235 space plus space straight n presubscript 0 presuperscript 1 space rightwards arrow space Ba presubscript 56 presuperscript 144 space plus space Kr presubscript 36 presuperscript 89 space plus space 3 straight n presubscript 0 presuperscript 1

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.