Hooke's Law (OCR GCSE Physics A (Gateway))

Revision Note

Katie M

Written by: Katie M

Reviewed by: Caroline Carroll

Hooke's Law

  • The relationship between the extension of an elastic object and the force applied is defined by Hooke's Law

  • Hooke's Law states that:

    The extension of an elastic object is directly proportional to the force applied, up to the limit of proportionality

  • Directly proportional means that as the force is increased, the extension increases 

    • If the force is doubled, then the extension will double

    • If the force is halved, then the extension will also halve

  • The limit of proportionality is the point beyond which the relationship between force and extension is no longer directly proportional 

    • This limit varies according to the material

Load extension and force, downloadable AS & A Level Physics revision notes

Hooke's Law states that a force applied to a spring will cause it to extend by an amount proportional to the force

  • Hooke's Law is defined by the equation:

F = k × x

  • Where:

    • F = force in newtons (N)

    • k = spring constant in newtons per metres (N/m)

    • x = extension in metres (m)

  • The symbol x can represent either the extension or compression of an elastic object

  • The Hooke's law equation can be rearranged using the following formula triangle:

Hookes Law Formula Triangle GCSE, downloadable IGCSE & GCSE Physics revision notes
  • The spring constant represents how stiff the spring is

    • The higher the spring constant, the higher the stiffness

  • The extension of an object can be calculated by:

Final length – Original length

  • The extension of the spring can be measured by marking the position of bottom of the unstretched spring

  • When the spring is stretched the final length must be measured from the bottom of the spring

Extension worked example, IGCSE & GCSE Physics revision notes

The extension measured from its final and original length

Worked Example

The figure below shows the forces acting on a child who is balancing on a pogo stick. The child and pogo stick are not moving.

Hookes Law Worked Example, downloadable IGCSE & GCSE Physics revision notes

The spring constant of the spring on the pogo stick is 4900 N/m. The weight of the child causes the spring to compress elastically from a length of 40 cm to a new length of 33 cm. Calculate the weight of the child.

Answer:

Step 1: List the known quantities

  • Spring constant, k = 4900 N/m

  • Original length = 40 cm

  • Final length = 33 cm

Step 2: Write the relevant equation

F = kx

Step 3: Calculate the extension, x

x = final length – original length = 40 – 33 = 7 cm

Step 4: Convert any units

  • Since the spring constant is given in N/m, x must be in metres (m)

7 cm = 0.07 m

Step 5: Substitute the values into the Hooke's Law equation

F = 4900 × 0.07 = 343 N

Examiner Tips and Tricks

Look out for unit conversions! Unless the spring constant is given in N/cm, make sure the extension is converted into metres (÷ 100) before substituting values into the Hooke's Law equation. 

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Katie M

Author: Katie M

Expertise: Physics

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.

Caroline Carroll

Author: Caroline Carroll

Expertise: Physics Subject Lead

Caroline graduated from the University of Nottingham with a degree in Chemistry and Molecular Physics. She spent several years working as an Industrial Chemist in the automotive industry before retraining to teach. Caroline has over 12 years of experience teaching GCSE and A-level chemistry and physics. She is passionate about creating high-quality resources to help students achieve their full potential.