Ultrasound in Medical & Industrial Imaging (HT only)v
- When ultrasound reaches a boundary between two media, some of the waves are partially reflected
- The remainder of the waves continue through the material and are transmitted
- Ultrasound transducers are able to:
- Emit ultrasound
- Receive ultrasound
- The time taken for the reflections to reach a detector can be used to determine how far away a boundary is
- This is because ultrasound travels at different speeds through different media
- This is by using the speed, distance, time equation
- Where:
- v = speed in metres per second (m/s)
- s = distance in metres (m)
- t = time in seconds (s)
- This allows ultrasound waves to be used for both medical and industrial imaging
Ultrasound in Medicine
- In medicine, ultrasound can be used:
- To construct images of a foetus in the womb
- To generate 2D images of organs and other internal structures (as long as they are not surrounded by bone)
- As a medical treatment such as removing kidney stones
- An ultrasound detector is made up of a transducer that produces and detects a beam of ultrasound waves into the body
- The ultrasound waves are reflected back to the transducer by boundaries between tissues in the path of the beam
- For example, the boundary between fluid and soft tissue or tissue and bone
- When these echoes hit the transducer, they generate electrical signals that are sent to the ultrasound scanner
- Using the speed of sound and the time of each echo’s return, the detector calculates the distance from the transducer to the tissue boundary
- By taking a series of ultrasound measurements, sweeping across an area, the time measurements may be used to build up an image
- Unlike many other medical imaging techniques, ultrasound is non-invasive and is believed to be harmless
Ultrasound can be used to construct an image of a foetus in the womb
Ultrasound in Industry
- In industry, ultrasound can be used to:
- Check for cracks inside metal objects
- Generate images beneath surfaces
- A crack in a metal block will cause some waves to reflect earlier than the rest, so will show up as pulses on an oscilloscope trace
- Each pulse represents each time the wave crosses a boundary
- The speed of the waves is constant, so measuring the time between emission and detection can allow the distance from the source to be calculated
Ultrasound is partially reflected at boundaries, so in a bolt with no internal cracks, there should only be two pulses (at the start and end of the bolt)
Worked example
In the diagram above, a very high-frequency sound wave is used to check for internal cracks in a large steel bolt. The oscilloscope trace shows that the bolt does have an internal crack. Each division on the oscilloscope represents a time of 0.000002 s. The speed of sound through steel is 6000 m/s.
Calculate the distance, in cm, from the head of the bolt to the internal crack.
Step 1: List the known quantities
-
- Speed of ultrasound, v = 6000 m/s
- Time taken, t = 5 × 0.000002 = 0.00001 s
Step 2: Write down the equation relating speed, distance and time
distance, d = v × t
Step 3: Calculate the distance
d = 6000 × 0.00001 = 0.06 m
Step 4: Convert the distance to cm
d = 6 cm