Solving Linear Inequalities (Edexcel GCSE Maths: Foundation)

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Naomi C

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Naomi C

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Interpreting Inequalities

What is a linear inequality?

  • An inequality tells you that something is greater than (>) or less than (<) something else
    • x > 5 means x is greater than 5 
      • x could be 6, 7, 8, 9, ...
  • Inequalities may also include being equal (=) 
    • ⩾ means greater than or equal to
    • ⩽ means less than or equal to
      • x ⩽ 10 means x is less than or equal to 10
        • x could be 10, 9, 8, 7, 6, ...
  • When they cannot be equal, they are called strict inequalities
    • > and < are strict inequalities
      • x > 5 does not include 5 (strict)
      • x ⩾ 5 does include 5 (not strict)

How do I find integers that satisfy inequalities?

  • You may be given two end points and have to list the integer (whole number) values of x that satisfy the inequality
  • Look at whether each end point is included or not 
    • 3 ⩽ x ⩽ 6
      • x = 3, 4, 5, 6
    • 3 ⩽ x < 6
      • x = 3, 4, 5
    • 3 < x ⩽ 6
      • x = 4, 5, 6
    • 3 < x < 6
      • x = 4, 5
  • If only one end point is given, there are an infinite number of integers
    • x > 2
      • x = 3, 4, 5, 6, ...
    • x ⩽ 2
      • x = 2, 1, 0, -1, -2, ...
      • Remember zero and negative whole numbers are integers
      • If the question had said positive integers only then just list x = 2, 1
  • You may be asked to find integers that satisfy two inequalities
    • 0 < x < 5 and x ⩾ 3
      • List separately: x = 1, 2, 3, 4 and x = 3, 4, 5, 6,  ...
      • Find the values that appear in both lists: x = 3, 4 
  • If the question does not say x is an integer, do not assume x is an integer!
    • x > 3 actually means any value greater than 3
      • 3.1 is possible
      • π = 3.14159... is possible
  • You may be asked to find the smallest or largest integer
    • The smallest integer that satisfies x > 6.5 is 7

How do I represent a linear inequality on a number line?

  • The inequality -3 < x ≤ 4 is shown on a number line below

A number line representing an inequality

  • Draw circles above the end points and connect them with a horizontal line
    • Leave an open circle for end points with strict inequalities, < or >
      • These end points are not included
    • Fill in a solid circle for end points with ≤ or ≥ inequalities
      • These end points are included

open circles when not including the ends, closed circles when including the ends

  • Use a horizontal arrow for inequalities with one end point
    • x > 5 is an open circle at 5 with a horizontal arrow pointing to the right 

Worked example

(a)

List all the integer values of x that satisfy 

negative 4 less or equal than x less than 2

Integer values are whole numbers 
-4 ≤ x shows that x includes -4, so this is the first integer

x = -4

x < 2 shows that x does not include 2
Therefore the last integer is x = 1

x = 1

For the answer, list all the integers from -4 to 1
Remember integers can be zero and negative

bold italic x bold equals bold minus bold 4 bold comma bold space bold minus bold 3 bold comma bold space bold minus bold 2 bold comma bold space bold minus bold 1 bold comma bold space bold 0 bold comma bold space bold 1

  

(b)

 Represent the inequality negative 2 less or equal than x less than 1 on a number line.

-2 is included so use a closed circle

1 is not included so use an open circle

Number line from -2 to 1, not including -2

   

Solving Linear Inequalities

How do I solve a linear inequalities?

  • Solving linear inequalities is just like Solving Linear Equations
    • Follow the same rules, but keep the inequality sign throughout
    • If you change the inequality sign to an equals sign you are changing the meaning of the problem
  • When you multiply or divide both sides by a negative number, you must flip the sign of the inequality 
    • E.g. 
      space 1 less than 2
open parentheses cross times negative 1 close parentheses space space space space space space space space space space space space space space space space space space space open parentheses cross times negative 1 close parentheses
space minus 1 greater than negative 2
  • Never multiply or divide by a variable (x) as this could be positive or negative
  • The safest way to rearrange is simply to add and subtract to move all the terms onto one side

How do I solve double inequalities?

  • Inequalities such as a space less than space 2 x space less than space b can be solved by doing the same thing to all three parts of the inequality
    • Use the same rules as solving linear inequalities

Examiner Tip

  • Do not change the inequality sign to an equals when solving linear inequalities.
    • In an exam you will lose marks for doing this. 
  • Remember to reverse the direction of the inequality sign when multiplying or dividing by a negative number!

Worked example

Solve the inequality 2 x minus 5 less or equal than 21.

Add 5 from both sides

2 x less or equal than 26

Now divide both sides by 2

x less or equal than 13

bold italic x bold less or equal than bold 13 

Worked example

Solve the inequality 5 minus 2 x less or equal than 21.

Subtract 5 from both sides, keeping the inequality sign the same

negative 2 x less or equal than 16

Now divide both sides by -2.
However because you are dividing by a negative number, you must flip the inequality sign

x greater or equal than negative 8

bold italic x bold greater or equal than bold minus bold 8 or bold minus bold 8 bold less or equal than bold italic x

Worked example

Solve the inequality negative 7 space less or equal than space 3 x space minus space 1 space less than space 2, illustrating your answer on a number line.

This is a double inequality, so any operation carried out to one side must be done to all three parts
Use the expression in the middle to choose the inverse operations needed to isolate x

Add 1 to all three parts
Remember not to change the inequality signs

negative 6 space less or equal than space 3 x space less than space 3

Divide all three parts by 3
3 is positive so there is no need to flip the signs

bold minus bold 2 bold space bold less or equal than bold space bold italic x bold space bold less than bold space bold 1

Illustrate the final answer on a number line, using an open circle at 1 and a closed circle at -2.

2-18-solving-inequalities

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Naomi C

Author: Naomi C

Expertise: Maths

Naomi graduated from Durham University in 2007 with a Masters degree in Civil Engineering. She has taught Mathematics in the UK, Malaysia and Switzerland covering GCSE, IGCSE, A-Level and IB. She particularly enjoys applying Mathematics to real life and endeavours to bring creativity to the content she creates.