Quadratic Sequences (Edexcel GCSE Maths)
Revision Note
Written by: Mark Curtis
Reviewed by: Dan Finlay
Quadratic Sequences
What is a quadratic sequence?
A quadratic sequence has an n th term formula that involves n2
The second differences are constant (the same)
These are the differences between the first differences
For example, 3, 9, 19, 33, 51, …
1st Differences: 6, 10, 14, 18, ...2nd Differences: 4, 4, 4, ...
The sequence with the n th term formula n2 are the square numbers
1, 4, 9, 16, 25, 36, 49, ...
From 12, 22, 32, 42, ...
How do I find the nth term formula for a simple quadratic sequence?
STEP 1
Work out the sequences of first and second differencese.g. for the sequence 1, 10, 23, 40, 61
sequence | 1 | 10 | 23 | 40 | 61 |
first difference | +9 | +13 | +17 | +21 | |
second difference | +4 | +4 | +4 |
STEP 2
Divide the second difference by 2 to find the coefficient of n2e.g. a = 4 ÷ 2 = 2
STEP 3
Write out the first three or four terms of an2 and subtract the terms from the corresponding terms of the given sequencee.g. for the sequence 1, 10, 23, 40, 61
sequence | 1 | 10 | 23 | 40 |
2n2 | 2 | 8 | 18 | 32 |
difference | -1 | 2 | 5 | 8 |
STEP 4
Work out the nth term of these differences to find the bn + ce.g. the nth term of -1, 2, 5, 8, ... is bn + c = 3n − 4
STEP 5
Find an2 + bn + c by adding together this linear nth term to an2e.g. an2 + bn + c = 2n2 + 3n − 4
Examiner Tips and Tricks
You must learn the square numbers from 12 to 152
Worked Example
For the sequence 5, 7, 11, 17, 25, ....
(a) Find a formula for the nth term.
Start by finding the first and second differences
Sequence: 5, 7, 11, 17, 25
First differences: 2, 4, 6, 8, ...
Second difference: 2, 2, 2, ...
Hence
a = 2 ÷ 2 = 1
Now write down an2 (just n2 in this case as a = 1) and subtract the terms from the original sequence
sequence: 5, 7, 11, 17, ...
an2. : 1, 4, 9, 16, ...
difference: 4, 3, 2, 1, ...
Work out the nth term of these differences to give you bn + c
bn + c = −n + 5
Add an2 and bn + c together to give you the nth term of the sequence
nth term = n2 − n + 5
(b) Hence find the 20th term of the sequence.
Substitute n = 20 into n2 − n + 5
(20)2 − 20 + 5 = 400 − 15
20th term = 385
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