Quadratic Sequences (Edexcel GCSE Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

Quadratic Sequences

What is a quadratic sequence?

  • A quadratic sequence has an n th term formula that involves n2

  • The second differences are constant (the same)

    • These are the differences between the first differences

    • For example,   3, 9, 19, 33, 51, …
      1st Differences: 6, 10, 14, 18, ...

      2nd Differences:  4,   4,   4, ...

  • The sequence with the n th term formula n2 are the square numbers 

    • 1, 4, 9, 16, 25, 36, 49, ...

      • From 12, 22, 32, 42, ...

How do I find the nth term formula for a simple quadratic sequence?

  • STEP 1
    Work out the sequences of first and second differences

    • e.g. for the sequence 1, 10, 23, 40, 61

sequence

1

10

23

40

61

first difference

+9

+13

+17

+21

second difference

+4

+4

+4

  • STEP 2
    Divide the second difference by 2 to find the coefficient of n2

    • e.g.  a = 4 ÷ 2 = 2

  • STEP 3
    Write out the first three or four terms of an2 and subtract the terms from the corresponding terms of the given sequence

    • e.g. for the sequence 1, 10, 23, 40, 61

sequence

1

10

23

40

2n2

2

8

18

32

difference

-1

2

5

8

  • STEP 4
    Work out the nth term of these differences to find the bnc

    • e.g. the nth term of -1, 2, 5, 8, ... is  bn= 3n − 4

  • STEP 5
    Find an2 + bn + c by adding together this linear nth term to an2

    • e.g.  an2 + bn += 2n2 + 3n − 4

Examiner Tips and Tricks

  • You must learn the square numbers from 12 to 152

Worked Example

For the sequence 5, 7, 11, 17, 25, ....

(a) Find a formula for the nth term.
Start by finding the first and second differences

Sequence:   5,   7,   11,   17,   25

First differences:      2,    4,     6,      8, ...           

Second difference:     2,    2,     2, ...               

Hence 

a = 2 ÷ 2 = 1

Now write down an2 (just n2 in this case as a = 1) and subtract the terms from the original sequence

sequence:   5,  7, 11, 17, ...

          an2. :  1,  4,  9,   16, ...

 difference:  4,  3,  2,  1, ...   

Work out the nth term of these differences to give you bnc

bnc = −n + 5

Add an2 and bntogether to give you the nth term of the sequence

nth term = n2 − n + 5

(b) Hence find the 20th term of the sequence.

Substitute n = 20 into n2 − n + 5

(20)2 − 20 + 5 = 400 − 15 

20th term = 385

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.