Averages from Tables (Edexcel GCSE Maths)

Revision Note

Averages from Tables & Charts

What are frequency tables?

  • Frequency tables are used to summarise data in a neat format

    • They also put the data in order

  • For example, the table below shows the number of pets in different houses along a street

    • The number of pets is the data value, x

    • The number of houses is the frequency, f

      • The frequency is how many times a data value is recorded (or seen)

  • The total frequency, n, can be calculated by adding together all the values in the frequency column

Number of pets
(data value, x)

Number of houses
(frequency, f)

0

2

1

7

2

6

3

4

4

1

Total frequency (n) = 20 

How do I find the mode from a frequency table?

  • The mode is the data value with the highest frequency

    •  The mode for the example above is 1 pet per house

      • The mode is not the frequency, 7, this is the number of houses that have exactly 1 pet

How do I find the median from a frequency table?

  • The median is the data value in the middle of the frequency

    • It is the open parentheses fraction numerator n plus 1 over denominator 2 end fraction close parentheses to the power of t h end exponent value, where n is the total frequency

  • From above, n equals 20 so the median is the open parentheses fraction numerator 20 plus 1 over denominator 2 end fraction close parentheses to the power of t h end exponent = 10.5th  value in the table

    • The first two rows have a combined (cumulative) frequency of 2 + 7 = 9

    • The first three rows have a combined frequency of 2 + 7 + 6 = 15

    • Therefore the 10th and 11th values are in the third row (x = 2)

      • The median is 2 pets per house

How do I find the mean from a frequency table?

  • The mean from a frequency table has the following formula:

    • mean space equals fraction numerator space total space of space apostrophe data space value space cross times space frequency apostrophe over denominator total space frequency end fraction

      • It helps to create a new column of 'data value × frequency'

      • Add up the values in this column

      • Divide by the total frequency

  • The mean is 35 over 20 = 1.75 pets per house

    • Means do not need to be whole numbers

Number of pets
(data value, x)

Number of houses
(frequency, f)

data value × frequency
(xf)

0

2

0 × 2 = 0

1

7

1 × 7 = 7

2

6

2 × 6 = 12

3

4

3 × 4 = 12

4

1

4 × 1 = 4

 

Total = 20 

Total = 35 

How do I find the range from frequency tables?

  • The range is the difference of the largest and smallest data values

    • The range above is 4 - 0 = 4

      • The range is not the difference of the largest and smallest frequencies

What else should I know about frequency tables?

  • Tables can be converted back into a list of data values using their frequencies 

    • From above, 0 pets were recorded twice, 1 pet was recorded 7 times, 2 pets were recorded 6 times, etc

      • The list of pets recorded is 0,0,1,1,1,1,1,1,1,2,2,2,2,2,2,3,3,3,3,4

  • You could then find the mode, median and mean from this list of numbers

Worked Example

The table shows data for the shoe sizes of pupils in class 11A.

Shoe size

Frequency

6

1

6.5

1

7

3

7.5

2

8

4

9

6

10

11

11

2

12

1

(a) Find the mean shoe size for the class, giving your answer to 3 significant figures.

It helps to label shoe size (x) and frequency (f)
Add an extra column and calculate the values of 'shoe size × frequency', (xf)
Find the total frequency and total xf  value

Shoe size (x)

Frequency (f)

xf

6

1

6 × 1 = 6

6.5

1

6.5 × 1 = 6.5

7

3

7 × 3 = 21

7.5

2

7.5 × 2 = 15

8

4

8 × 4 = 32

9

6

9 × 6 = 54

10

11

10 × 11 = 110

11

2

11 × 2 = 22

12

1

12 × 1 = 12

 

Total = 31 

Total = 278.5 

Use the formula that the mean is the total of the xf  column divided by the total frequency 

Mean equals fraction numerator 278.5 over denominator 31 end fraction equals 8.983 space 870 space...

Give your final answer to 3 significant figures

The mean shoe size is 8.98 (to 3 s.f.)

Note that the mean does not have to be an actual shoe size

(b) Find the median shoe size.

The median is the open parentheses fraction numerator n plus 1 over denominator 2 end fraction close parentheses to the power of t h end exponent value where n is the total frequency

fraction numerator n plus 1 over denominator 2 end fraction equals fraction numerator 31 plus 1 over denominator 2 end fraction equals 32 over 2 equals 16

The median is the 16th value
There are 1 + 1 + 3 + 2 + 4 = 11 values in the first five rows of the table
There are 11 + 6 = 17 values in the first six rows of the table
Therefore the 16th value must be in the sixth row 

The median shoe size is 9  

(c) Find the range of the shoe sizes.

 The range is the highest shoe size subtract the lowest show size

12 - 6

The range of the shoe sizes is 6

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.