Averages from Grouped Data (Edexcel GCSE Maths)
Revision Note
Written by: Roger B
Reviewed by: Dan Finlay
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Averages from Grouped Data
What is grouped data?
Data can be collected into groups or class intervals
It is useful for organising data if you have a lot of individual data points
You can present grouped data in a grouped frequency table
Grouped data may be discrete or continuous
Discrete data is numerical data that can only take on specific values, it needs to be counted
E.g. Shoe size
Continuous data can take any value within a range of infinite values, it needs to be measured
E.g. Length of a foot in cm
Why do I find an estimate for the mean from grouped data?
It is impossible to find the mean for grouped data, because we don't have access to the original data values
i.e. there is no way to find the exact sum of all the data values
so we can't use the formula,
However we can estimate the mean for grouped data
To do this we use the class midpoints as our data values
e.g. if a class interval is 150 ≤ x < 160
we assume that all the data values are equal to the midpoint, 155
Examiner Tips and Tricks
When presented with data in a table it may not be obvious whether the data is grouped or not
When you see the phrase “estimate the mean” you know that you are in the world of grouped data!
How do I find an estimate for the mean from grouped data?
To find an estimate for the mean from grouped data, complete the following steps:
STEP 1
Draw an extra two columns on the end of a table of the grouped dataIn the first new column write down the midpoint of each class interval
If the midpoint isn't obvious, add the endpoints and divide by 2
e.g. if a class interval is 150 ≤ x < 160
the midpoint is
STEP 2
Calculate "frequency" × "midpoint" (this is often called fx)Write these values in the second column you added to the table
STEP 3
Find the total for the fx columnIf the question does not tell you the total number of data values (i.e. the total frequency), find the total of the frequency column also
STEP 4
Estimate the mean by using the formulai.e. divide the total of the fx column by the total number of data values
How do I find the modal class?
For grouped data we talk about the modal class instead of the mode
This is the class with the highest frequency
Find the highest frequency in the table
The corresponding class interval tells you the modal class
How do I find the class interval that the median lies in?
Find the position of the median using , where is the number of data values (total of the frequency column)
Use the table to deduce the class interval containing the value
e.g. if the median is the 7th value and the frequency of the first two class intervals are 4 and 7
the median will lie in the second class interval of the table
Note that rather than 'the median' we refer to the 'class interval containing the median'
Examiner Tips and Tricks
Be careful not to confuse the modal class with its frequency
e.g. if the highest frequency in the table is 34, corresponding to the class interval
then the modal class is , not '34'!
This also applies to the interval containing the median
Worked Example
The weights of 20 three-week-old Labrador puppies were recorded at a vet's clinic. The results are shown in the table below.
Weight, w kg | Frequency |
3 ≤ w < 3.5 | 2 |
3.5 ≤ w < 4 | 4 |
4 ≤ w < 4.5 | 6 |
4.5 ≤ w < 5 | 5 |
5 ≤ w < 5.5 | 2 |
5.5 ≤ w < 6 | 1 |
(a) Estimate the mean weight of these puppies.
First add two columns to the table
Complete the first new column with the midpoints of the class intervals
Complete the second extra column by calculating "fx"
A total row is also useful
Weight, w kg | Frequency | Midpoint | "fx" |
3 ≤ w < 3.5 | 2 | 3.25 | 2 × 3.25 = 6.5 |
3.5 ≤ w < 4 | 4 | 3.75 | 4 × 3.75 = 15 |
4 ≤ w < 4.5 | 6 | 4.25 | 6 × 4.25 = 25.5 |
4.5 ≤ w < 5 | 5 | 4.75 | 5 × 4.75 = 23.75 |
5 ≤ w < 5.5 | 2 | 5.25 | 2 × 5.5 = 10.5 |
5.5 ≤ w < 6 | 1 | 5.75 | 1 × 5.75 = 5.75 |
Total | 20 |
| 87 |
Now we can find the mean using
4.35 kg
(b) Write down the modal class.
The highest frequency in the table is 6
This corresponds to the interval 4 ≤ w < 4.5
4 ≤ w < 4.5
A common error here would be to write down 6
(the frequency) as the modal class
(c) Find the interval that contains the median.
There are 20 dogs
The median interval will be the interval containing the 10.5th dog
Keep a running total
Weight, w kg | Frequency | Running Total |
3 ≤ w < 3.5 | 3 | 3 |
3.5 ≤ w < 4 | 4 | 3 + 4 = 7 |
4 ≤ w < 4.5 | 6 | 7 + 6 = 13 |
4.5 ≤ w < 5 | 5 | 13 + 5 = 18 |
5 ≤ w < 6 | 2 | 18 + 2 = 20 |
The 10.5th dog is in the third interval
The median is in the interval 4 ≤ w < 4.5
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