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Write down the equation of a circle, centred at the origin, with a radius of .
The equation of a circle centred at the origin with a radius of is:
How do you find the radius of the circle given by ?
To find the radius of the circle given by you need to square root 81.
This is because from the equation .
This gives a radius of 9.
You do not need , as a radius is always positive.
Write down the equation of the circle shown.
The equation is as the radius is 5 so in .
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Write down the equation of a circle, centred at the origin, with a radius of .
The equation of a circle centred at the origin with a radius of is:
How do you find the radius of the circle given by ?
To find the radius of the circle given by you need to square root 81.
This is because from the equation .
This gives a radius of 9.
You do not need , as a radius is always positive.
Write down the equation of the circle shown.
The equation is as the radius is 5 so in .
How would you find the diameter of the circle ?
To find the diameter of the circle , first compare it to the equation of a circle given by .
You can see that the radius, , is 10, because .
The diameter is double the radius. This means the diameter is 20.
True or False?
The radius of the circle is .
True.
The radius of the circle is .
It is possible for a radius to be left as a square root.
You can also use surd methods to simplify them, such as .
True or False?
The point lies on the circumference of the circle .
True.
The point lies on the circumference of the circle .
You can show this by substituting in and into the left-hand side.
This gives .
This matches the right-hand side, so the equation is satisfied (the point lies on the circle).
How can you find out if the point lies inside or outside the circle ?
To find out if the point lies inside or outside the circle , first substitute and into the left-hand side of the equation.
This gives .
Compare this number to the right-hand side of the equation. If it is less than the right-hand side, the point lies inside the circle.
so the point lies inside the circle.
True or False?
The -intercepts of the circle are .
False.
The equation rearranges to .
This means the radius is (because and ).
The -intercepts of a circle centred at the origin are (plus or minus the radius).
Therefore the -intercepts are .
True or False?
The equation represents a circle.
False.
The equation rearranges to , which has a negative right-hand side.
The equation of a circle is , so the right-hand side must always be positive.
Explain why the line never intersects the circle .
The circle is centred at the origin with a radius of 10.
The line is a vertical line through 12 on the -axis.
This will never intersect the circle, as the circle lies between on the -axis.
True or False?
A radius which passes through a point P on a circle, is perpendicular to the tangent to the circle which passes through point P.
True.
A radius which passes through a point P on a circle, is perpendicular to the tangent to the circle which passes through point P.
If the gradient of the radius passing through point P on a circle is known, how can you find the gradient of the tangent to the circle at point P?
If the gradient of the radius passing through point P on a circle is known, the gradient of the tangent to the circle at point P will be its negative reciprocal.
This is because a radius and a tangent which meet at a point, will meet at right angles.
Given a point on the circumference of a circle with centre , outline how you would find the equation of the tangent passing through .
Given a point on the circumference of a circle with centre , outline how to find the equation of the tangent passing through :
Find the gradient of the radius: .
Use the fact that the tangent is perpendicular to this, so has gradient .
The equation of the tangent will be in the form .
Substitute the gradient , and the point into to find
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