Right-Angled Trigonometry (AQA GCSE Further Maths)

Revision Note

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Paul

Written by: Paul

Reviewed by: Dan Finlay

Pythagoras

What is the Pythagorean theorem?

  • Pythagoras’ theorem is a formula that works for right-angled triangles only

  • It states that for any right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the two shorter sides

    • The hypotenuse is the longest side in a right-angled triangle

      • It will always be opposite the right angle

    • If we label the hypotenuse c, and label the other two sides a and b, then Pythagoras’ theorem tells us that

a squared space plus space b squared space equals space c squared

How can we use Pythagoras’ theorem?

  • If you know two sides of any right-angled triangle you can use Pythagoras’ theorem to find the length of the third side

    • Substitute the values you have into the formula and either solve or rearrange

  • To find the length of the hypotenuse you can use:

c equals blank square root of a squared plus b squared end root

  • To find the length of one of the other sides you can use:

a space equals blank square root of c squared space minus space b squared end root   or  b space equals blank square root of c squared space minus space a squared end root

  • Note that when finding the hypotenuse you should add inside the square root and when finding one of the other sides you should subtract inside the square root

  • Always check your answer carefully to make sure that the hypotenuse is the longest side

  • Note that Pythagoras’ theorem questions will rarely be standalone questions and will often be ‘hidden’ in other geometry questions

Examiner Tips and Tricks

  • Pythagoras' theorem pops up in lots of exam questions so bear it in mind whenever you see a right-angled triangle in an exam question!

Worked Example

Find an expression for the length y, in terms of x.

KMBDZSZH_pythagoras-we-question

Use Pythagoras' theorem to find the hypotenuse of the right-angled triangle on the lef

square root of 5 squared plus 12 squared end root 

Simplify this value

square root of 25 plus 144 end root
equals square root of 169
equals 13 

Write out Pythagoras' theorem for the right-angled triangle on the right, using the length found above of 13 cm

x squared plus 13 squared equals y squared 

Make y the subject by square-rooting both sides 
(you cannot square root each individual term)

square root of x squared plus 169 end root equals y 

No plus-or-minus square root of blank end root is needed as y is a length (positive)

bold italic y bold equals square root of bold italic x to the power of bold 2 bold plus bold 169 end root

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SOHCAHTOA

What is Trigonometry?

  • Trigonometry is the mathematics of angles in triangles

  • It looks at the relationship between side lengths and angles of triangles

  • It comes from the Greek words trigonon meaning ‘triangle’ and metron meaning ‘measure’

     

What are Sin, Cos and Tan?

  • The three trigonometric functions Sine, Cosine and Tangent come from ratios of side lengths in right-angled triangles

  • To see how the ratios work you must first label the sides of a right-angled triangle in relation to a chosen angle

    • The hypotenuse, H, is the longest side in a right-angled triangle

      • It will always be opposite the right angle

    • If we label one of the other angles θ, the side opposite θ will be labelled opposite, O, and the side next to θ will be labelled adjacent, A

  • The functions Sine, Cosine and Tangent are the ratios of the lengths of these sides as follows

Sin space theta blank equals space opposite over hypotenuse space equals space O over H

 Cos space theta blank equals space adjacent over hypotenuse space equals space straight A over straight H

Tan space theta blank equals space opposite over adjacent space equals space straight O over straight A

What is SOHCAHTOA?

  • SOHCAHTOA is a mnemonic that is often used as a way of remembering which ratio is which

    • Sin is Opposite over Hypotenuse

    • Cos is Adjacent over Hypotenuse

    • Tan is Opposite over Adjacent

  • In a right-angled triangle, label one angle other than the right angle and label the sides of the triangles as follows

Right-Angled-Triangles-OAH-Theta, IGCSE & GCSE Maths revision notes
  • Note that θ is the Greek letter theta

    • O = opposite θ

    • A = adjacent (next to) θ

    •  H = hypotenuse - 'H' is always the same, but 'O' and 'A' change depending on which angle we're calling θ

  • Using those labels, the three SOHCAHTOA equations are:

Right-Angled Triangles Diagram 1

How can we use SOHCAHTOA to find missing lengths?

  • If you know the length of one of the sides of any right-angled triangle and one of the angles you can use SOHCAHTOA to find the length of the other sides

    • Always start by labelling the sides of the triangle with H, O and A

    • Choose the correct ratio by looking only at the values that you have and that you want

      • For example if you know the angle and the side opposite it (O) and you want to find the hypotenuse (H) you should use the sine ratio

    • Substitute the values into the ratio

    • Use your calculator to find the solution 

How can we use SOHCAHTOA to find missing angles?

  • If you know two sides of any right-angled triangle you can use SOHCAHTOA to find the size of one of the angles

  • Missing angles are found using the inverse functions:

 theta space equals space Sin to the power of negative 1 end exponent space O over H   ,    theta space equals space Cos to the power of negative 1 end exponent space straight A over straight H   ,   theta space equals space Tan to the power of negative 1 end exponent space straight O over straight A

  • After choosing the correct ratio and substituting the values use the inverse trigonometric functions on your calculator to find the correct answer

Examiner Tips and Tricks

  • SOHCAHTOA (like Pythagoras) can only be used in right-angles triangles – for triangles that are not right-angled, you will need to use the Sine Rule or the Cosine Rule

  • Also, make sure your calculator is set to measure angles in degrees

Worked Example

Find the values of x and y in the following triangles.

Give your answers to 3 significant figures.

Two Right Angled Triangles with measurements, IGCSE & GCSE Maths revision notes

To find x, first label the triangle

Right Pointing Right Angled Triangle with measurements, IGCSE & GCSE Maths revision notes

We know A and we want to know O - that's TOA or tanθ equals opposite over adjacent

tan open parentheses 43 close parentheses equals x over 9

Multiply both sides by 9

9 cross times tan open parentheses 43 close parentheses space equals space x

Enter on your calculator

x equals 8.3926...

Round to 3 significant figures

bold italic x bold equals bold 8 bold. bold 39 bold space bold cm

To find y, first label the triangle

Left Pointing Right Angled Triangle with measurements, IGCSE & GCSE Maths revision notes

We know A and H - that's CAH or cosθ equals adjacent over hypotenuse

cos open parentheses y close parentheses equals 8 over 23

Use inverse cos to find y

y equals cos to the power of negative 1 end exponent open parentheses 8 over 23 close parentheses

Enter on your calculator

y equals 69.6455...

Round to 3 significant figures

bold italic y bold equals bold 69 bold. bold 6 bold degree

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Exact Trig Values

What are exact values in trigonometry?

  • For certain angles the values of sin θ, cos θ and tan θ can be written exactly

    • This means using fractions and surds

    • You should be familiar with these values and be able to derive the values using geometry

  • You are expected to know the exact values of sin, cos and tan for angles of 0°, 30°, 45°, 60°, 90°, 180° and their multiples

  • The exact values you are expected to know are summarised here:

Trigonometry Exact Values RN table, downloadable IGCSE & GCSE Maths revision notes
  • Note that the values of sin θ  going from 0° to 90° match those of cos θ going from 90° to 0°

How are exact values in trigonometry derived?

  • There are two special right-angled triangles that can be used to derive all of the exact values you need to know

  • Consider a right-angles triangle with a hypotenuse of 2 units and a shorter side length of 1 unit

    • Using Pythagoras’ theorem the third side will be square root of 3

    • The angles will be 90°, 60° and 30°

    • Using SOHCAHTOA gives…

      • Sin 60° = fraction numerator square root of 3 over denominator 2 end fraction              Sin 30°  = size 16px 1 over size 16px 2

      • Cos 60°  = size 16px 1 over size 16px 2                 Cos 30° = fraction numerator square root of 3 over denominator 2 end fraction

      • Tan 60°  = square root of 3               Tan 30° = begin mathsize 16px style fraction numerator 1 over denominator square root of 3 end fraction end style = begin mathsize 16px style fraction numerator square root of 3 over denominator 3 end fraction end style

  • Consider an isosceles triangle with two equal side lengths (the opposite and adjacent) of 1 unit

    • Using Pythagoras’ theorem it will have a hypotenuse of square root of 2

    • The two equal angles will be 45°

    • Using SOHCAHTOA gives…

      • Sin 45 degree space equals space fraction numerator 1 over denominator square root of 2 end fraction space equals space fraction numerator square root of 2 over denominator 2 end fraction

      • Cos 45 degree space equals space fraction numerator 1 over denominator square root of 2 end fraction space equals space fraction numerator square root of 2 over denominator 2 end fraction

      • Tan 45 degree= 1

5-4-2-exact-values-notes-diagram-1

Examiner Tips and Tricks

  • You will be expected to be comfortable using exact trig values for certain angles but it can be easy to muddle them up if you just try to remember them from a list

  • sketch the triangles and trig graphs on your paper so that you can use them as many times as you need to during the exam

    • sketch the triangles for the key angles 45 degree30 degree60 degree

    • sketch the trig graphs for the key angles 0 degree, 90 degree, 180 degree270 degree, 360 degree

Worked Example

Using an equilateral triangle of side length 2 units, derive the exact values for the sine, cosine and tangent of 60° and 30°.

Sketch the triangle and create two right angled triangles by drawing the line of symmetry through the middle.

30-60-exact-trig-values, IGCSE & GCSE Maths revision notes

Use Pythagoras' theorem to find the vertical height of the triangle.

B D space equals space square root of 2 to the power of 2 space end exponent minus space 1 squared end root space equals space square root of 3

Use SOHCAHTOA to find the trig ratios for 30° and 60°.

Sin 60° = fraction numerator B D over denominator A B end fraction equals fraction numerator square root of 3 over denominator 2 end fraction              Sin 30°  = fraction numerator A D over denominator A B end fraction equals space 1 half

Cos 60°  = fraction numerator A D over denominator A B end fraction equals space 1 half                   Cos 30° = fraction numerator B D over denominator A B end fraction equals space fraction numerator square root of 3 over denominator 2 end fraction

Tan 60°  = fraction numerator BD space over denominator AD end fraction equals fraction numerator space square root of 3 over denominator 1 end fraction space equals space square root of 3                Tan 30° = space fraction numerator A D over denominator B D end fraction equals fraction numerator 1 over denominator square root of 3 end fraction equals fraction numerator square root of 3 over denominator 3 end fraction

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Paul

Author: Paul

Expertise: Maths Content Creator (Previous)

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams – one of the many reasons he is excited to be a member of the SME team.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.