Quadratic Simultaneous Equations (AQA GCSE Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

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Quadratic Simultaneous Equations

What are quadratic simultaneous equations?

  • When there are two unknowns (say x and y) in a problem, we need two equations to be able to find them both: these are called simultaneous equations

  • If there is an x2 or y2 or xy in one of the equations then they are quadratic (or non-linear) simultaneous equations

How do I solve quadratic simultaneous equations?

  • Use the method of substitution

    • Substitute the linear equation, y = ... (or x = ...), into the quadratic equation

      • Do not try to substitute the quadratic equation into the linear equation

  • Solve x2 + y2 = 25 and y - 2x = 5 

    • Rearrange the linear equation into y = 2x + 5

    • Substitute this into the quadratic equation, replacing all y's with (2x + 5) in brackets

      •  x2 + (2x + 5)2 = 25

    • Expand and solve this quadratic equation (x = 0 and x = -4)

    • Substitute each value of x into the linear equation, y = 2x + 5, to get their value of y

    • Present your solutions in a way that makes it obvious which x belongs to which y

      • x = 0, y = 5 or x = -4, y = -3

  • Check your final solutions satisfy both equations

How do you use graphs to solve quadratic simultaneous equations?

  • Plot both equations on the same set of axes

    • to do this, you can use a table of values (or, for straight lines, rearrange into y = mx + c if it helps)

  • Find where the lines intersect (cross over)

    • The x and y solutions to the simultaneous equations are the x and y coordinates of the point of intersection

  • e.g. to solve y = x2 + 3x + 1 and y = 2x + 1 simultaneously, first plot them both (see graph)

    • find the points of intersection, (-1, -1) and (0, 1)

    • the solutions are x = -1 and y = -1 or x = 0 and y = 1

Solving Equations Graphically - Notes Diagram 4, A Level & AS Level Pure Maths Revision Notes

Examiner Tips and Tricks

  • If the resulting quadratic has a repeated root then the line is a tangent to the curve

  • If the resulting quadratic has no roots then the line does not intersect with the curve – or you have made a mistake!

  • When giving your final answer, make sure you indicate which x and y values go together

    • If you don’t make this clear you can lose marks for an otherwise correct answer

  • Don't make the common mistake of thinking each squared term in x2 + y2 = 25 can be square-rooted to give x + y = 5 (they can't, the most you can do is square root of x squared plus y squared end root equals plus-or-minus 5, but you shouldn't be making x or y the subject of this anyway!)

Worked Example

Solve the equations

x2 + y2 = 36
x = 2y + 6

Number the equations.

x squared space plus space y squared space equals space 36
x space equals space 2 y space plus space 6space space space space space space space space space space open parentheses 1 close parentheses
space space space space space space space space space space open parentheses 2 close parentheses 

There is one quadratic equation and one linear equation so this must be done by substitution.

Equation (2) is equal to x so this can be eliminated by substituting it into the x part for equation (1).
Substitute x space equals space 2 y space plus space 6 into equation (1).

open parentheses 2 y space plus space 6 close parentheses squared space plus space y squared space equals space 36

Expand the brackets, remember that a bracket squared should be treated the same as double brackets.

open parentheses 2 y space plus space 6 close parentheses open parentheses 2 y space plus space 6 close parentheses space space plus space y squared space equals space 36
4 y to the power of 2 space end exponent plus space 6 open parentheses 2 y close parentheses space plus space 6 open parentheses 2 y close parentheses space plus space 6 squared space plus space y to the power of 2 space end exponent equals space 36

Simplify.

table attributes columnalign right center left columnspacing 0px end attributes row cell 4 y to the power of 2 space end exponent plus space 12 y space plus space 12 y space plus space 36 space plus space y to the power of 2 space end exponent end cell equals cell space 36 end cell row cell 5 y to the power of 2 space end exponent plus space 24 y space plus space 36 space end cell equals cell space 36 end cell end table

Rearrange to form a quadratic equation that is equal to zero.

table row cell 5 y to the power of 2 space end exponent plus space 24 y space plus space 36 space minus space 36 space end cell equals cell space 0 end cell row cell 5 y squared space plus space 24 y space end cell equals cell space 0 end cell end table

The question does not give a specified degree of accuracy, so this can be factorised.
Take out the common factor of table attributes columnalign right center left columnspacing 0px end attributes row blank blank y end table.

table row cell y open parentheses 5 y space plus space 24 close parentheses space end cell equals cell space 0 end cell end table

Solve to find the values of y.
Let each factor be equal to 0 and solve.

table row cell y subscript 1 space end cell equals cell space 0 space space space space space space space space space space space space space space end cell row cell 5 y subscript 2 space plus space 24 space end cell equals cell space 0 space space rightwards double arrow space space y subscript 2 equals space minus 24 over 5 space equals space minus 4.8 end cell end table

Substitute the values of y into one of the equations (the linear equation is easier) to find the values of x.

              x subscript 1 space equals space 2 left parenthesis 0 right parenthesis space plus space 6 space equals space 6 space space space space space space space space space space space space x subscript 2 space equals space 2 open parentheses negative 24 over 5 close parentheses space plus space 6 space equals space minus 9.6 space plus space 6

bold italic x subscript bold 1 bold space bold equals bold space bold 6 bold comma bold space bold space bold italic y subscript bold 1 bold equals bold space bold 0 
bold italic x subscript bold 2 bold space bold equals bold minus bold 3 bold. bold 6 bold comma bold space bold space bold space bold italic y subscript bold 2 bold space bold equals bold minus bold 4 bold. bold 8 

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.