Linear Simultaneous Equations (AQA GCSE Further Maths)

Revision Note

Mark Curtis

Written by: Mark Curtis

Reviewed by: Dan Finlay

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Linear Simultaneous Equations

What are linear simultaneous equations?

  • When there are two unknowns (say x and y) in a problem, we need two equations to be able to find them both: these are called simultaneous equations

    • you solve two equations to find two unknowns, x and y

      • for example, 3x + 2y = 11 and 2x - y = 5

      • the solutions are x = 3 and y = 1

  • If they just have x and y in them (no x2 or y2 or xy etc) then they are linear simultaneous equations

How do I solve linear simultaneous equations by elimination?

  • "Elimination" completely removes one of the variables, x or y

  • To eliminate the x's from 3x + 2y = 11 and 2x - y = 5 

    • Multiply every term in the first equation by 2

      • 6x + 4y = 22

    • Multiply every term in the second equation by 3

      • 6x - 3y = 15

    • Subtract the second result from the first to eliminate the 6x's, leaving 4y - (-3y) = 22 - 15, i.e. 7y = 7

    • Solve to find y (y = 1) then substitute y = 1 back into either original equation to find x (x = 3)

  • Alternatively, to eliminate the y's from 3x + 2y = 11 and 2x - y = 5 

    • Multiply every term in the second equation by 2

      • 4x - 2y = 10

    • Add this result to the first equation to eliminate the 2y's (as 2y + (-2y) = 0)

      • The process then continues as above

  • Check your final solutions satisfy both equations

How do I solve linear simultaneous equations by substitution?

  • "Substitution" means substituting one equation into the other

  • Solve 3x + 2y = 11 and 2x - y = 5 by substitution

    • Rearrange one of the equation into y = ... (or x = ...)

      • For example, the second equation becomes y = 2x - 5 

    • Substitute this into the first equation (replace all y's with 2x - 5 in brackets)

      • 3x + 2(2x - 5) = 11

    • Solve this equation to find x (x = 3), then substitute x = 3 into y = 2x - 5 to find y (y = 1)

  • Check your final solutions satisfy both equations

How do you use graphs to solve linear simultaneous equations?

  • Plot both equations on the same set of axes

    • to do this, you can use a table of values or rearrange into y = mx + if that helps

  • Find where the lines intersect (cross over)

    • The x and y solutions to the simultaneous equations are the x and y coordinates of the point of intersection

  • e.g. to solve 2x - y = 3 and 3x + y = 7 simultaneously, first plot them both (see graph)

    • find the point of intersection, (2, 1)

    • the solution is x = 2 and y = 1

Solving Equations Graphically Notes Diagram 1, A Level & AS Level Pure Maths Revision Notes

How do I solve linear simultaneous equations from worded contexts?

EPS Notes fig2 (1), downloadable IGCSE & GCSE Maths revision notes
EPS Notes fig2 (2), downloadable IGCSE & GCSE Maths revision notes

Examiner Tips and Tricks

  • Always check that your final solutions satisfy the original simultaneous equations

    • you will know immediately if you've got the right solutions or not

Worked Example

Solve the simultaneous equations

5x + 2y = 11
4x - 3y = 18

Number the equations.

table row cell 5 x space plus space 2 y space end cell equals cell space 11 end cell row cell 4 x space minus space 3 y space end cell equals cell space 18 end cell end tabletable row blank blank cell space space space space space space space space space space space space open parentheses 1 close parentheses end cell row blank blank cell space space space space space space space space space space space space open parentheses 2 close parentheses end cell end table 

Make the y terms equal by multiplying all parts of equation (1) by 3 and all parts of equation (2) by 2.
This will give two 6y terms with different signs. The question could also be done by making the x terms equal by multiplying all parts of equation (1) by 4 and all parts of equation (2) by 5, and subtracting the equations.

table row cell 15 x space plus space 6 y space end cell equals cell space 33 end cell row cell 8 x space minus space 6 y space end cell equals cell space 36 space end cell end tabletable row blank blank cell space space space space space space space space space space open parentheses 3 close parentheses end cell row blank blank cell space space space space space space space space space space open parentheses 4 close parentheses end cell end table

The 6y terms have different signs, so they can be eliminated by adding equation (4) to equation (3). 

space space space space space space space space space space 15 x space plus space 6 y space equals space 33 space space space space space space space space space space space space
bottom enclose space plus open parentheses space space space space space space 8 x space minus space 6 y space equals space 36 close parentheses space end enclose
space space space space space space space space space space 23 x space space space space space space space space space space space space space equals space 69 space

Solve the equation to findby dividing both sides by 23.

table row cell x space end cell equals cell space 69 over 23 equals space 3 end cell end table

Substitute x space equals space 3 into either of the two original equations.

open parentheses 1 close parentheses space space space space space 5 open parentheses 3 close parentheses space plus space 2 y space equals space 11

Solve this equation to find y.

table row cell 15 space plus space 2 y space end cell equals cell space 11 end cell row cell 2 y space end cell equals cell space 11 space minus space 15 end cell row cell 2 y space end cell equals cell space minus 4 space end cell row cell y space end cell equals cell fraction numerator negative 4 over denominator 2 end fraction space equals space minus 2 end cell end table

Substitute x = 3  and y = - 2 into the other equation to check that they are correct

table row blank blank cell open parentheses 2 close parentheses space space space end cell end tabletable row cell 4 x space minus space 3 y space end cell equals cell space 18 end cell end table
table row cell 4 open parentheses 3 close parentheses space minus space 3 open parentheses negative 2 close parentheses space end cell equals cell space 18 end cell row cell 12 space minus open parentheses negative 6 close parentheses space end cell equals cell space 18 end cell row cell 18 space end cell equals cell space 18 end cell end table

bold italic x bold space bold equals bold space bold 3 bold comma bold space bold space bold italic y bold equals bold minus bold 2

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Mark Curtis

Author: Mark Curtis

Expertise: Maths

Mark graduated twice from the University of Oxford: once in 2009 with a First in Mathematics, then again in 2013 with a PhD (DPhil) in Mathematics. He has had nine successful years as a secondary school teacher, specialising in A-Level Further Maths and running extension classes for Oxbridge Maths applicants. Alongside his teaching, he has written five internal textbooks, introduced new spiralling school curriculums and trained other Maths teachers through outreach programmes.

Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.