Factor Theorem (AQA GCSE Further Maths)

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Definition of a Polynomial

What is a polynomial?

  • A polynomial is a sum of terms with non-negative integer powers of x 

    • the highest power of x is its degree

  • The following are polynomials:

    • x cubed plus 4 x squared minus 3 x plus 1 (degree 3)

    • 5 x to the power of 6 minus 2 x squared (degree 6)

    • 10 (degree 0)

  • The following are not polynomials:

    • 1 over x plus x cubed (the 1 over xcan be written x to the power of negative 1 end exponent which has a negative power)

    • x squared plus 3 x plus square root of x (the square root of xcan be written x to the power of 1 half end exponentwhich has a non-integer power)

    • x to the power of 5 plus 2 minus sin space x (sin space x is not a power of x)

  • There are words to name different types of polynomials:

    • degree

      name

      0

      constant

      1

      linear

      2

      quadratic

      3

      cubic

      4

      quartic

      5

      quintic

      ...

      ...

  • For the polynomial 6 x to the power of 4 minus 3 x squared plus 2 x plus 8

    • ... the degree is 4 (it's a quartic)

    • ... the coefficient of x2 is -3

    • ... the quadratic term (or term involving x2) is -3x2

    • ... the coefficient of x3 is 0

    • ... the constant is 8

How do I add / subtract / multiply polynomials?

  • Adding and subtracting two polynomials requires collecting like terms

    • for example, open parentheses x cubed plus 4 x close parentheses plus open parentheses x squared plus 8 x plus 3 close parentheses gives x cubed plus x squared plus 12 x plus 3

    • whereas open parentheses x cubed plus 4 x close parentheses minus open parentheses x squared plus 8 x plus 3 close parentheses gives x cubed minus x squared minus 4 x minus 3

      • the second bracket expands to negative x squared minus 8 x minus 3

  • Multiplying two polynomials can be done by expanding brackets or using a grid method (multiplying rows by columns then combining terms to get the answer)

    • for example, open parentheses x cubed plus 4 x close parentheses open parentheses x squared plus 8 x plus 3 close parentheses can be done as follows:

    •  

      x3

      4x

      x2

      x5

      4x3

      8x

      8x4

      32x2

      3

      3x3

      12x

    • add any like terms that arise: 3 x cubed plus 4 x cubed equals 7 x cubed

    • the final answer is therefore x to the power of 5 plus 8 x to the power of 4 plus 7 x cubed plus 32 x squared plus 12 x

Factor Theorem

What is a factor of a polynomial?

  • You already know that some quadratic expressions can be factorised

    • x squared plus 5 x plus 6 factorises to open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses

    • (x + 2) and (x + 3) are called factors

      • as the power of x in each factor is 1, they can also be called linear factors

  • Similarly, other polynomials can be factorised

  • 4 x cubed plus 8 x squared minus 9 x minus 18 factorises to open parentheses x plus 2 close parentheses open parentheses 2 x plus 3 close parentheses open parentheses 2 x minus 3 close parentheses

    • there are three linear factors

      • or, by expanding the last two brackets, open parentheses x plus 2 close parentheses open parentheses 4 x squared minus 9 close parentheses, you could write it as one linear factor and one quadratic factor

  • Rational factors refer to linear factors in the form (ax + b), with a number in front of the x, like (2x + 3)

What is the Factor Theorem for (x - a)?

  • Let f(x) be a polynomial

    • The Factor Theorem states that if f(a) = 0 then (x - a) is a factor  

    • It also works in reverse, so if (x - a) is a factor then f(a) = 0

  • For example, try substituting x = 2 and x = 4 into straight f open parentheses x close parentheses equals x cubed minus 6 x squared plus 11 x minus 6

    • straight f open parentheses 2 close parentheses equals 2 cubed minus 6 cross times 2 squared plus 11 cross times 2 minus 6 equals 0 (zero)

    • straight f open parentheses 4 close parentheses equals 4 cubed minus 6 cross times 4 squared plus 11 cross times 4 minus 6 equals 6 (not zero)

    • The Factor Theorem says that (x - 2) is a factor of f(x), but (x - 4) is not

      • It tells you without you having to factorise f(x)

  • Be careful with the signs

    • f(2) = 0 means (x - 2) is a factor, not (x + 2)

What is the Factor Theorem for (ax - b)?

  • Let f(x) be a polynomial

    • The Factor Theorem above can be extended to say that if  then (ax - b) is a factor  

    • It also works in reverse, so if (ax - b) is a factor then straight f open parentheses b over a close parentheses equals 0

  • This is sometimes called The Factor Theorem for rational factors, (ax - b)

  • For example, you can show that (2x - 3) is a factor of straight f open parentheses x close parentheses equals 4 x cubed plus 8 x squared minus 9 x minus 18 without doing any factorising

    • If (2x - 3) really is a factor, then the Factor Theorem says straight f open parentheses 3 over 2 close parentheses should equal zero - check to see if that's true

      • straight f open parentheses 3 over 2 close parentheses equals 4 open parentheses 3 over 2 close parentheses cubed plus 8 open parentheses 3 over 2 close parentheses squared minus 9 open parentheses 3 over 2 close parentheses minus 18 equals 0 so yes, (2x - 3) is a factor (by the Factor Theorem)

  • Be careful with the signs and fraction order

    •  straight f open parentheses 3 over 2 close parentheses equals 0 means (3x - 2) is a factor, not any of (3x + 2), (2x - 3) or (2x + 3)

Examiner Tips and Tricks

  • To help remember what to substitute into f(x) when (ax - b) is a factor, a good trick is to set (ax - b) equal to zero and solve for x

    • For example, to show that (7x + 5) is a factor, first try solving 7x + 5 = 0 to get x equals negative 5 over 7 , which shows you what to substitute into f(x), i.e. straight f open parentheses negative 5 over 7 close parentheses

Worked Example

If open parentheses 2 x plus 1 close parentheses is a factor of 2 x cubed plus k x squared minus 8 x minus 3 where k is an integer, find the value of k.

Assign the straight f open parentheses x close parentheses notation to the given polynomial.

table row cell space straight f open parentheses x close parentheses space end cell equals cell space 2 x to the power of 3 space end exponent plus space k x squared space minus space 8 x space minus space 3 end cell end table

Set the factor equal to 0 and solve for x to find the value that should be substituted into straight f open parentheses x close parentheses.

table row cell 2 x space plus space 1 space end cell equals cell space 0 end cell row cell x space end cell equals cell space minus 1 half end cell end table

Therefore straight f open parentheses negative 1 half close parentheses space equals space 0.

Substitute x space equals space minus 1 half and set to 0.

table row cell space 2 open parentheses negative 1 half close parentheses to the power of 3 space end exponent plus space k open parentheses negative 1 half close parentheses squared space minus space 8 open parentheses negative 1 half close parentheses space minus space 3 space end cell equals cell space 0 end cell end table

Simplify.

table row cell space 2 open parentheses negative 1 over 8 close parentheses plus space k open parentheses 1 fourth close parentheses space minus space 8 open parentheses negative 1 half close parentheses space minus space 3 space end cell equals cell space 0 end cell row cell negative 2 over 8 plus space k over 4 space plus space 4 space minus space 3 space end cell equals cell space 0 end cell row cell negative 1 fourth plus space k over 4 space plus space 1 space end cell equals cell space 0 end cell end table

Subtract 1 from both sides and multiplying both sides by 4.

table row cell negative 1 fourth plus space k over 4 space end cell equals cell space minus 1 end cell row cell negative 1 space plus space k space end cell equals cell space minus 4 end cell end table

Solve by adding 1 to both sides. 

bold italic k bold space bold equals bold space bold minus bold 3

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