Expanding & Factorising (AQA GCSE Further Maths)

Revision Note

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Dan Finlay

Written by: Dan Finlay

Reviewed by: Lucy Kirkham

Basic Expanding & Factorising

How do I expand brackets?

  • Expanding brackets means multiplying all the terms inside a bracket by the term outside of the bracket

  • For GCSE Mathematics you will have learnt how to expand a single bracket

    • Multiply each term inside the bracket by the term outside the bracket

table row cell 2 x open parentheses 3 x minus 4 y plus 5 close parentheses end cell equals cell 2 x cross times 3 x minus 2 x cross times 4 y plus 2 x cross times 5 end cell row blank equals cell 6 x squared minus 8 x y plus 10 x end cell end table

  • You will also have learnt how to expand double brackets

    • You can turn this into two single brackets by multiplying each term inside one bracket by the other bracket

    • For Level 2 Further Mathematics you might get more than two terms in a bracket

      • Therefore using a grid or turning the expression into single brackets will be more helpful than using FOIL

table row cell open parentheses 2 x plus 5 close parentheses open parentheses 3 x minus 4 y plus 5 close parentheses end cell equals cell 2 x open parentheses 3 x minus 4 y plus 5 close parentheses plus 5 open parentheses 3 x minus 4 y plus 5 close parentheses end cell row blank equals cell 6 x squared minus 8 y x plus 10 x plus 15 x minus 20 y plus 25 end cell row blank equals cell 6 x squared plus negative 8 x y plus 25 x minus 20 y plus 25 end cell end table

  • A bracket that is raised to the power of 2 can also be written as a double bracket

    • open parentheses x plus y plus z close parentheses squared equals open parentheses x plus y plus z close parentheses open parentheses x plus y plus z close parentheses

    • Write as a double bracket and then expand

      • Do not just square each term inside the bracket

  • Be very careful when working with negatives

  • Remember to simplify expressions where possible

How do I factorise out a term from an expression?

  • Factorising is the opposite of expanding

  • Firstly find the highest common factor of each term in the expression and put this outside a bracket

    • The highest common factor could be a single number or a variable or both 

      • 12 x plus 8 equals 4 open parentheses... plus... close parentheses

      • 2 x squared minus 5 x equals x open parentheses... negative... close parentheses

      • 6 x squared plus 8 x y plus 4 x equals 2 x open parentheses... plus... plus... close parentheses

    • If the terms involve the same variable(s) to different powers then the highest common factor will include the variable(s) with the smallest power

      • 4 x to the power of 5 plus 5 x to the power of 4 equals x to the power of 4 open parentheses... plus... close parentheses

      • 6 x to the power of 4 y to the power of 7 minus 8 x to the power of 9 y to the power of 5 equals 2 x to the power of 4 y to the power of 5 open parentheses... negative... close parentheses

    • The highest common factor could also contain brackets

      • open parentheses x plus 1 close parentheses squared plus 5 open parentheses x plus 1 close parentheses equals open parentheses x plus 1 close parentheses open parentheses... plus... close parentheses

      • open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses x plus 4 close parentheses equals open parentheses x plus 1 close parentheses open parentheses x plus 2 close parentheses open parentheses... plus... close parentheses

  • Then find what you need to multiply the highest common factor by to get each term

    • You might need to use the index law: x to the power of a cross times x to the power of b equals x to the power of a plus b end exponent

Worked Example

(a) Expand and simplify open parentheses x plus 4 close parentheses open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses.

The second bracket has more than two terms so turn the expression into single bracket expansions

table row cell open parentheses x plus 4 close parentheses open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses end cell equals cell x open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses plus 4 open parentheses x to the power of 4 minus 5 x cubed plus 4 x squared minus 7 x close parentheses end cell row blank equals cell x to the power of 5 minus 5 x to the power of 4 plus 4 x cubed minus 7 x plus 4 x to the power of 4 minus 20 x cubed plus 16 x squared minus 28 x end cell end table

Collect like terms

bold italic x to the power of bold 5 bold minus bold italic x to the power of bold 4 bold minus bold 16 bold italic x to the power of bold 3 bold plus bold 9 bold italic x to the power of bold 2 bold minus bold 28 bold italic x

(b) Factorise fully open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses.

There are two terms in this expression; open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses and open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses
Both contain the common factor open parentheses x plus 1 close parentheses
As a bracket is a factor, using "big square brackets" can help keep track of what's left

open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 close parentheses plus open parentheses x plus 1 close parentheses open parentheses x minus 2 close parentheses equals open parentheses x plus 1 close parentheses open square brackets table row cell table row cell open parentheses 2 x plus 3 close parentheses end cell plus end table end cell cell open parentheses x minus 2 close parentheses end cell end table close square brackets

Simplify the "big square brackets"

table attributes columnalign right center left columnspacing 0px end attributes row blank equals cell open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 plus x minus 2 close parentheses end cell row blank equals cell open parentheses x plus 1 close parentheses open parentheses 3 x plus 1 close parentheses end cell end table

The whole expression is now fully simplified (but it's always worth checking!)

Expanding Triple Brackets

How do I expand three brackets?

  • Multiply out any two brackets using a standard method and simplify this answer (collect any like terms)

  • Replace the two brackets above with one long bracket containing the expanded result

  • Expand this long bracket with the third (unused) bracket

    • This step often looks like (x + a)(x2 + bx + c)

    • Every term in the first bracket must be multiplied with every term in the second bracket

      • This leads to six terms 

    • A grid can often help to keep track of all six terms, for example (x + 2)(x2 + 3x + 1)

      •  

        x2

        +3x

        +1

        x

        x3

        3x2

        x

        +2

        2x2

        6x

        2

      • add all the terms inside the grid (diagonals show like terms) to get x3 + 2x2 + 3x2 + 6x + x + 2

      • collect like terms to get the final answer of x3 + 5x2 + 7x + 2

  • Simplify the final answer by collecting like terms (if there are any)

  • It helps to put negative terms in brackets when multiplying

Worked Example

Expand  open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses open parentheses 3 x minus 1 close parentheses.

Start by expanding the first two sets of brackets and simplify by collecting 'like' terms

table row blank blank cell open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses end cell row blank equals cell 2 x cross times x plus 2 x cross times 4 plus open parentheses negative 3 close parentheses cross times x plus open parentheses negative 3 close parentheses cross times 4 end cell row blank equals cell 2 x squared plus 8 x minus 3 x minus 12 end cell row blank equals cell 2 x squared plus 5 x minus 12 end cell end table

Rewrite the original expression with the first two brackets expanded

open parentheses 2 x squared plus 5 x minus 12 close parentheses open parentheses 3 x minus 1 close parentheses

Multiply all of the terms in the first set of brackets by all of the terms in the second set of brackets

2 x squared cross times 3 x plus 5 x cross times 3 x plus open parentheses negative 12 close parentheses cross times 3 x plus 2 x squared cross times open parentheses negative 1 close parentheses plus 5 x cross times open parentheses negative 1 close parentheses plus open parentheses negative 12 close parentheses cross times open parentheses negative 1 close parentheses

Simplify

6 x cubed plus 15 x squared minus 36 x minus 2 x squared minus 5 x plus 12

Collect 'like' terms

bold 6 bold italic x to the power of bold 3 bold plus bold 13 bold italic x to the power of bold 2 bold minus bold 41 bold italic x bold plus bold 12

Factorising by Grouping

How do I factorise expressions with common brackets?

  • To factorise 3x(t + 4) + 2(t + 4), both terms have a common bracket, (t + 4)

    • the whole bracket, (t + 4), can be "taken out" like a common factor

      • (t + 4)(3x + 2)

    • this is like factorising 3xy + 2y to y(3x + 2)

      • y represents (t + 4) above

 

How do I factorise by grouping?

  • Some questions may require you to form the common bracket yourself

    • for example, factorise xy + px + qy + pq

      • "group" the first pair of terms, xy + px, and factorise, x(y + p)

      • "group" the second pair of terms, qy + pq, and factorise, q(y + p),

    • now factorise x(y + p) + q(y + p) as above

      • (y + p)(x + q)

  • This is called factorising by grouping

  • The groupings are not always the first pair of terms and the second pair of terms, but two terms with common factors

Examiner Tips and Tricks

  • As always, once you have factorised something, expand it by hand to check your answer is correct.

Worked Example

Factorise ab + 3b + 2a + 6.

Method 1
Notice that ab and 3b have a common factor of b
Notice that 2a and 6 have a common factor of 2

Factorise the first two terms, using b as a common factor

b(a + 3) + 2+ 6 

Factorise the second two terms, using 2 as a common factor 

b(a + 3) + 2(a + 3) 

(+ 3) is a common bracket 
We can factorise using (a + 3) as a factor

(a + 3)(b + 2)

Method 2
Notice that ab and 2a have a common factor of a
Notice that 3b and 6 have a common factor of 3

Rewrite the expression grouping these terms together 

ab + 2a + 3b + 6 

Factorise the first two terms, using a as a common factor 

a(b + 2) + 3b + 6 

Factorise the second two terms, using 3 as a common factor 

a(b + 2) + 3(b + 2) 

(b + 2) is a common bracket
 We can factorise using (b + 2) as a factor

(b + 2)(a + 3)

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Dan Finlay

Author: Dan Finlay

Expertise: Maths Lead

Dan graduated from the University of Oxford with a First class degree in mathematics. As well as teaching maths for over 8 years, Dan has marked a range of exams for Edexcel, tutored students and taught A Level Accounting. Dan has a keen interest in statistics and probability and their real-life applications.

Lucy Kirkham

Author: Lucy Kirkham

Expertise: Head of STEM

Lucy has been a passionate Maths teacher for over 12 years, teaching maths across the UK and abroad helping to engage, interest and develop confidence in the subject at all levels.Working as a Head of Department and then Director of Maths, Lucy has advised schools and academy trusts in both Scotland and the East Midlands, where her role was to support and coach teachers to improve Maths teaching for all.