The Mole (Edexcel GCSE Chemistry: Combined Science)

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The Mole

  • Chemical amounts are measured in moles
  • The symbol for the unit mole is mol
  • One mole of a substance contains the same number of the stated particles, atoms, molecules, or ions as one mole of any other substance
  • The number of atoms, molecules or ions in a mole (1 mol) of a given substance is the Avogadro constant. The value of the Avogadro constant is 6.02 x 1023 per mole

For example:
  • One mole of sodium (Na) contains  6.02 x 1023  atoms of sodium
  • One mole of hydrogen (H2) contains  6.02 x 1023  molecules of hydrogen
  • One mole of sodium chloride (NaCl) contains  6.02 x 1023 formula units of sodium chloride

The Moles & Particles Formula Triangle, downloadable IB Chemistry revision notes

The formula triangle showing the relationship between moles, particles and the Avogadro constant

Worked example

Particles from Moles: How many hydrogen atoms are in 0.010 moles of CH3CHO?

Answer:

    • There are 4 H atoms in 1 molecule of CH3CHO
    • So, there are 0.040 moles of H atoms in 0.010 moles of CH3CHO
    • The number of H atoms is the amount in moles x L
    • This comes to 0.040 x (6.02 x 1023) = 2.4 x 1022 atoms

Worked example

Moles from Particles: How many moles of hydrogen atoms are in 3.612 x 1023 molecules of H2O2? 

Answer:

    • In 3.612 x 1023 molecules of H2O2  there are 2 x (3.612 x 1023) atoms of H
    • So, there are 7.224 x 1023 atoms of H
    • The number of moles of H atoms is the number of particles ÷ L
    • This comes to 7.224 x 1023 ÷ (6.02 x 1023) = 1.20 moles of H atoms

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Linking the Mole and Relative Atomic Mass

Linking the Mole and Relative Atomic Mass

  • One mole of any element is equal to the relative atomic mass of that element in grams or for a compound the relative formula mass in grams
  • This is called the molar mass
  • If you had 6.02 x 1023 atoms of carbon in your hand, that number of carbon atoms would have a mass of 12 g (because the Aof carbon is 12)
  • So one mole of helium atoms would have a mass of 4 g (Aof He is 4), one mole of lithium would have a mass of 7 g (Aof Li is 7) and so on
  • To find the mass of one mole of a compound, we add up the relative atomic masses
    • So one mole of water would have a mass of (2 x 1) + 16 = 18 g
    • So one carbon atom has the same mass as 12 hydrogen atoms

Moles and Molar Mass

  • Although elements and chemicals react with each other in molar ratios, in the laboratory we use digital balances and grams to measure quantities of chemicals as it is impractical to try and measure out moles
  • Therefore we have to be able to convert between moles and grams
  • We can use the following formula to convert between moles, mass in grams and the molar mass:

The Moles & Mass Formula Triangle, downloadable IB Chemistry revision notes

Formula triangle for moles, mass and molar mass

 

Worked example

Mass from Moles: What is the mass of 0.250 moles of zinc?

Answer:

    • From the periodic table the relative atomic mass of Zn is 65.38
    • So, the molar mass is 65.38 g mol-1
    • The mass is calculated by moles x molar mass
    • This comes to 0.250 mol x 65.38 g mol-1 = 16.3 g

Worked example

Moles from Mass: How many moles are in 2.64 g of sucrose, C12H22O11  (Mr = 342.3)?

Answer:

    • The molar mass of sucrose is 342.3 g mol-1
    • The number of moles is found by mass ÷ molar mass
    • This comes to  2.64 g ÷ 342.3 g mol-1 = 7.71 x 10-3 mol

Examiner Tip

Always show your workings in calculations as its easier to check for errors and you may pick up credit if you get the final answer wrong.

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Stewart

Author: Stewart

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Exam Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.