Conservation of Mass & Balancing Chemical Equations (AQA GCSE Chemistry: Combined Science)

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The Law of Conservation of Mass

  • The Law of Conservation of Mass states that no matter is lost or gained during a chemical reaction.
  • Mass is always conserved, therefore the total mass of the reactants is equal to the total mass of the products, which is why all chemical equations must be balanced
  • The sum of the relative atomic/molecular masses of the reactants will be the same as the sum of the relative atomic/molecular masses of the products
  • A precipitation reaction is one in which two solutions react to form an insoluble solid called a precipitate
  • If the reaction flask is closed and no other substance can enter or leave the system, then the total mass of the reaction flask will remain constant
  • For example, the reaction between calcium chloride and sodium sulfate produces a precipitate of calcium sulfate.
  • If carried out in a closed system then the mass before and after the reaction will be the same
  • The balanced equation is:

CaCl2 (aq) + Na2SO4 (aq) CaSO4 (s) + 2NaCl (aq)

Image showing that the mass of a chemical reaction remains the same at the start and end of a chemical reaction

Diagram showing the conservation of mass in a precipitation reaction

  • If the reaction flask is open and a gaseous product is allowed to escape, then the total mass of the reaction flask will change as product mass is lost when the gas leaves the system
  • For example, the reaction between hydrochloric acid and calcium carbonate produces carbon dioxide gas:

2HCl (aq) + CaCO3 (s) CaCl2 (aq) + H2O (l) + CO2 (g)

  • Mass will be lost from the reaction flask unless it is closed
  • If the mass of a reaction flask is found to increase then it may be due to one of the reactants being a gas found in the air and all of the products are either solids or liquids

Examiner Tip

Matter cannot be created or destroyed, so the total amount of matter before and after a reaction is the same. What changes is the chemical and physical properties of the reactants as they transform into products.

Representing reactions as equations

  • The numbers involved in chemical formulae and equations give a lot of information about the chemicals involved
  • In chemical formulae:
    • If there is no subscript number after an element, then there must be one of that particular element
      • e.g. CO contains one carbon and one oxygen atom
    • If there is a subscript number after an element, then that number belongs to the element just before it
      • e.g. CO2 contains one carbon atom and two oxygen atoms
    • If there is a subscript number after brackets, then that number belongs to all of the elements inside the bracket
      • e.g. Ca(OH)2 contains one calcium atom, two oxygen atoms AND two hydrogen atoms
    • The most complicated examples contain a subscript number inside the bracket as well as outside,
      • e.g. Ca(NO3)2 contains one calcium atom
      • Inside the bracket, there is one nitrogen atom and three oxygen atoms but the subscript 2 outside the bracket applies to the nitrogen and oxygen inside the bracket
      • This means that there are two nitrogen atoms and six oxygen atoms
  • Chemical equations use the chemical symbols of each reactant and product.
  • When balancing equations, there has to be the same number of atoms of each element on either side of the equation in accordance with the Law of Conservation of Mass.
  • The following non-metals must be written as molecules: H2, N2, O2, F2, Cl2, Br2 and I2.
  • To balance an equation you work across the equation from left to right, checking one element after another.
  • If there is a group of atoms, for example, a nitrate group (NO3) that has not changed from one side to the other, then count the whole group as one entity rather than counting the individual atoms.
  • Examples of chemical equations:
    • Acid-base neutralisation reaction:

NaOH (aq) + HCl (aq)  ⟶ NaCl (aq) + H2O (l) 

    • Redox reaction:

2Fe2O3 (aq) + 3C (s) ⟶ 4Fe (s) + 3CO2 (g)

  • In each equation there are equal numbers of each atom on either side of the reaction arrow so the equations are balanced.

Examiner Tip

  • A large number before any chemical applies to that entire chemical
  • The last equation above starts with 2Fe2O3
    • The Fe2O3 suggests that there are two iron atoms and three oxygen atome
    • The large 2 in front applies to the whole Fe2O3, i.e. 2 x Fe2O3
      • Therefore, there are four iron atoms and six oxygen atoms involved in the reaction

Balancing equations

  • The best approach is to practice lot of examples of balancing equations
  • By trial and error change the coefficients (multipliers) in front of the formulae, one by one checking the result on the other side
  • Balance elements that appear on their own, last in the process

Worked example

Symbol equations 1

Aluminium reacts with copper(II) oxide to produce aluminium oxide and copper. Balance the symbol equation for the reaction taking place.

_Al (s) +  _CuO (s)  ⟶  _Al2O3 (s) +  _Cu (s)

Answer:

  • The balanced symbol equation is:

2Al (s) +  3CuO (s) ⟶  Al2O3 (s) +  3Cu (s)

  • Step 1 - balancing aluminium atoms
    • There are 2 aluminium atoms on the product side, so 2 aluminium atoms are needed on the reactant side
      • 2Al  +  _CuO  ⟶  _Al2O3  +  _Cu
  • Step 2 - balancing oxygen atoms
    • There are 3 oxygen atoms on the product side, so 3 oxygen atoms are needed on the reactant side
    • This means that 3 CuO will be needed as we cannot change the chemical formula 
      • 2Al  +  3CuO  ⟶  _Al2O3  +  _Cu
  • Step 3 - balancing copper atoms
    • There are 3 copper atoms on the reactant side, so 3 copper atoms are needed on the product side
      • 2Al  +  3CuO  ⟶  _Al2O3  +  3Cu
  • The equation is now balanced

Worked example

Symbol equations 2

When magnesium oxide, MgO, reacts with nitric acid, HNO3, it forms magnesium nitrate, Mg(NO3)2, and water. Write a symbol equation for this reaction. 

Answer:

  • The balanced symbol equation is:

MgO (s) + 2HNO3 (aq) ⟶ Mg(NO3)2 (aq) + H2O (l)

  • Step 1 - writing the unbalanced equation
    • Magnesium oxide, MgO, reacts with nitric acid, HNO3, it forms magnesium nitrate, Mg(NO3)2, and water
      • MgO + HNO3 ⟶ Mg(NO3)2 + H2O
    • The Mg and O atoms (not including the O in the NO3 group appear to be balanced), so we should focus on the H atoms and NO3 groups
  • Step 2 - balancing hydrogen atoms
    • There are 2 hydrogen atoms on the product side, so 2 hydrogen atoms are needed on the reactant side
    • This means that 2 HNO3 will be needed as we cannot change the chemical formula 
      • MgO + 2HNO3 ⟶ Mg(NO3)2 + H2O
    • This also balances the nitrate, NO3, groups
  • Step 3 - checking the equation
    • The equation appears balanced so we need to check that it is 
      • Reactant side:
        • 1 Mg atom
        • 1 O atom - not including those in the NO3 group
        • 2 H atoms
        • 2 NO3 groups - remember to keep groups as a single entity if they are unchanged on both sides of the equation
      • Product side:
        • 1 Mg atom
        • 2 NO3 groups - remember to keep groups as a single entity if they are unchanged on both sides of the equation
        • 2 H atoms
        • 1 O atom - not including those in the NO3 group
    • The equation is now balanced

Examiner Tip

  • Careful: A common mistake when balancing symbol equations is to add, change or remove small numbers in the chemical formula of a substance
    • You cannot do this because it changes what the substance is
    • For example, if a product was water, H2O, and you added a second oxygen to make it H2O2 then it is no longer water
  • If you are not confident balancing symbol equations, draw them out

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Stewart

Author: Stewart

Expertise: Chemistry Lead

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Exam Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.