Cracking Hydrocarbons (WJEC GCSE Chemistry)

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Cracking Fractions

  • Fractional distillation separates crude oil into fractions containing hydrocarbons of similar chain lengths
  • Each fraction has different values for its supply and demand
    • Supply is how much of a particular fraction can be produced from refining the crude oil
    • Demand is how much customers want to buy

Supply & demand of crude oil fractions

Supply & Demand of Crude oil Fractions

Demand for short chain hydrocarbon molecules such as petrol, kerosene and diesel is greater than the supply, while demand for long chain hydrocarbons such as fuel oil is less than the supply

  • The demand for certain fractions outstrips the supply so cracking is used to convert excess unwanted fractions into more useful ones

What is cracking?

  • Cracking is an industrial process used to break low demand, long chain hydrocarbon molecules into more useful, small chain hydrocarbon molecules
    • Any long chain hydrocarbon can be cracked into smaller chain hydrocarbons
    • For example, kerosene and diesel oil are often cracked to produce petrol, alkenes and hydrogen
  • Cracking involves heating the hydrocarbon molecules to around 600 – 700°C to vaporise them
  • The vapours then pass over a hot powdered catalyst of alumina or silica
  • This process breaks covalent bonds in the molecules as they come into contact with the surface of the catalyst, causing thermal decomposition reactions
  • The molecules are broken up in a random way which produces a mixture of shorter alkanes and alkenes
    • Alkanes are saturated molecules containing carbon-carbon single bonds only
    • Alkenes are unsaturated molecules containing carbon=carbon double bonds 
  • Hydrogen and a greater proportion of alkenes form when cracking is performed at higher temperatures and higher pressure

Example of cracking

Cracking Decane

Decane is cracked to produce octane for petrol and ethene for polymerisation and ethanol synthesis

Useful hydrocarbon molecules

  • Shorter alkanes are useful because they have a lower boiling point and are more flammable
    • This makes them more useful fuels
  • Shorted alkenes are useful because they contain a carbon=carbon double bond which makes them reactive
    • This makes alkenes, such as ethene, useful as a starting point in the production of polymers / plastics

Equations for Cracking

  • By the Law of Conservation of Mass, the reactant hydrocarbon that is being cracked must have the same number of carbon and hydrogen atoms as all of the product hydrocarbons combined
    • The reactant hydrocarbon must be an alkane (general formula CnH2n+2)
    • The product hydrocarbons are a mixture of alkanes (general formula CnH2n+2AND alkenes (general formula CnH2n)
  • For example, the cracking of hexane to form butane and ethene, which are both useful shorter hydrocarbons
    • Ethene is the starting material for the plastic polythene 
    • Butane is used as a fuel

C6H14  C4H10 + C2H4 

    • Hexane contains 6 carbon atoms; butane and ethene contain (4 + 2 =) 6 carbon atoms
    • Hexane contains 14 hydrogen atoms; butane and ethene contain (10 + 4 =) 14 hydrogen atoms 
  • We can also use the general formulae for alkanes and alkenes to check that we have correct equations
    • The reactant hexane and butane product are both alkanes and follow the CnH2n+2 general formula 
    • The other product, ethene, is an alkene and follows the general formula CnH2n  

Examiner Tip

Always check that sum of the carbons and hydrogens adds up on each side of the equation AND that you have made alkanes or alkenes.

Worked example

a)
Complete the following symbol equation for the cracking of eicosane, C20H42.
 
C20H42 → .................... + C2H4 
 
b)
Explain whether the unknown product is an alkane or an alkene.

 

Answer:

a)
The complete symbol equation is:
C20H42 → C18H38 + C2H4 
 
  • Eicosane contains 20 carbon atoms while the known product contains 2 carbon atoms
    • Therefore, the unknown product must contain 20 - 2 = 18 carbon atoms
  • Eicosane contains 42 hydrogen atoms while the known product contains 4 hydrogen atoms
    • Therefore, the unknown product must contain 42 - 4 = 38 hydrogen atoms
b)
The unknown product is an alkane because:
  • It has the general formula CnH2n+2

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Richard

Author: Richard

Expertise: Chemistry

Richard has taught Chemistry for over 15 years as well as working as a science tutor, examiner, content creator and author. He wasn’t the greatest at exams and only discovered how to revise in his final year at university. That knowledge made him want to help students learn how to revise, challenge them to think about what they actually know and hopefully succeed; so here he is, happily, at SME.