Testing Cations & Anions
Testing for Cations
- The flame test is used to identify the positive metals ion (cations) by the colour of the flame they produce
- Ions from different metals produce different colours
- To carry out a flame test:
- Dip the loop of an unreactive metal wire such as nichrome or platinum in dilute acid
- Hold it in the blue flame of a Bunsen burner until there is no colour change
- Dip the loop into the solid sample / solution and place it in the edge of the blue Bunsen flame
- It is important that place the wire into acid first to prevent contamination
- Not doing this might result in two or more ions being present on the wire meaning the colours will mix
- One colour could mask another colour and you will not be able to identify the ion
How to carry out a flame test
The blue flame must be used to carry out a flame test
- The colour of the flame is observed and used to identify the metal ion present:
Cation | Flame Colour |
Li+ | Red |
Na+ | Yellow-orange |
K+ | Lilac |
Ca2+ | Brick-red |
Ba2+ | Apple-green |
Diagram showing the colours formed in the flame test for metal ions
Examiner Tip
You must be specific when giving the colours.
You will not score the mark for stating that copper produces a 'green' flame. It must be 'apple-green.'
Testing for Anions
- Negatively charged non- metal ions are known as anions
- You must be able to test for halide ions
- These are the ions formed by the elements in Group 7
How do I test for halide ions?
- Add silver nitrate solution, AgNO3
- If a halide is present it forms a silver halide precipitate
- For example, the following reaction occurs between aqueous potassium chloride and and silver nitrate solution:
potassium chloride + silver nitrate → potassium nitrate + silver chloride
KCl (aq) + AgNO3 (aq) → KNO3 (aq) + AgCl (s)
- The silver halide formed, in this case silver chloride forms a precipitate
- This is represented using the state symbol, s
- The ionic equation for the precipitation reaction occurring in this example is:
Ag+ (aq) + Cl– (aq) → AgCl (s)
- The general ionic equation for the precipitation reaction that occurs when a silver halide is formed is:
Ag+ (aq) + X– (aq) → AgX (s)
- The potassium and nitrate ions do not participtate in the precipitate reaction so are known as spectator ions
- Depending on the halide present, a different coloured precipitate is formed, allowing for identification of the halide ion
- Silver chloride forms a white precipitate
- Ag+ (aq) + Cl– (aq) → AgCl (s)
- Silver bromide forms a cream precipitate
- Ag+ (aq) + Br– (aq) → AgBr (s)
- Silver iodide forms a yellow precipitate
- Ag+ (aq) + I– (aq) → AgI (s)
Diagram to show the precipitates formed by different halide ions
Each silver halide produces a precipitate of a different colour
Examiner Tip
It is important that you include state symbols when you are writing equations for precipitation reactions but you will be told to include these in your exam.