Determine an Empirical Formula (Edexcel GCSE Chemistry): Revision Note

Exam code: 1CH0

Stewart Hird

Written by: Stewart Hird

Updated on

Determine an Empirical Formula

Aim:

To determine the empirical formula of magnesium oxide by combustion of magnesium

Diagram:

Finding the Formula of Magnesium Oxide, downloadable IGCSE & GCSE Chemistry revision notes

Finding the empirical formula of magnesium oxide involves heating magnesium ribbon very strongly in a crucible. A lid is used to trap any smoke (not shown)

Method:

  • Measure mass of crucible with lid

  • Add sample of magnesium into crucible and measure mass with lid (calculate the mass of the metal by subtracting the mass of empty crucible)

  • Strongly heat the crucible over a Bunsen burner for several minutes

  • Lift the lid frequently to allow sufficient air into the crucible for the magnesium to fully oxidise without letting magnesium oxide smoke escape

  • Continue heating until the mass of crucible remains constant (maximum mass), indicating that the reaction is complete

  • Measure the mass of crucible and contents (calculate the mass of metal oxide by subtracting the mass of empty crucible)

Working out the empirical formula:

Step 1 - Calculate the masses of metal and oxygen:

  • Mass of metal:

    • Subtract the mass of the crucible from the mass of the crucible and magnesium

  • Mass of oxygen:

    • Subtract the mass of the crucible from the mass of the crucible and magnesium oxide

Step 2 – Divide each mass by the relative atomic mass (Ar)

Step 3 – Simplify the ratio

Step 4 – Write the empirical formula

Worked Example

A student heated a sample of magnesium in a crucible. The following masses were recorded:

Mass (g)

Crucible + lid

24.83

Crucible + lid + magnesium

25.07

Crucible + lid + magnesium oxide (after heating)

25.23

Step 1 - Calculate the masses of magnesium and oxygen:

mass of magnesium = 25.07 − 24.83 = 0.24 g

mass of magnesium oxide = 25.23 − 24.83 = 0.40 g

mass of oxygen gained = 0.40 − 0.24 = 0.16 g

Step 2 - Divide each mass by the relative atomic mass (Ar):

Magnesium

Oxygen

Mass (g)

0.24

0.16

Ar

24

16

Moles

fraction numerator 0.24 over denominator 24 end fraction = 0.01

fraction numerator 0.16 over denominator 16 end fraction = 0.01

Step 3 - Simplify the ratio:

Mg : O = 0.01 : 0.01

Mg : O = 1 : 1

Step 4 - Write the empirical formula:

The empirical formula is MgO

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Stewart Hird

Author: Stewart Hird

Expertise: Chemistry Content Creator

Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Topic Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.