Titration Calculations (AQA GCSE Chemistry)

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How to do titration calculations

Higher tier only

  • Once a titration is completed and the average titre has been calculated, you can now proceed to calculate the unknown variable using the formula triangle as shown below

Concentration moles formula triangle, downloadable IB Chemistry revision notes

Formula triangle showing the relationship between concentration, number of moles and volume of liquid

Worked example

25.00 cmof 0.15 mol/dm3 barium hydroxide, Ba(OH)2, was required to neutralise 12.80 cm3 of nitric acid, HNO3 , during a titration. Calculate the concentration of HNO3 that was used. Give your answer to 2 decimal places.

Ba(OH)2 (aq) + 2HNO3 (aq) → Ba(NO3)2 (aq) + 2H2O (l)

Answer:

  • Step 1: Calculate the number of moles of barium hydroxide 
    • Moles of barium hydroxide = concentration x volume (dm3) = 0.15 x 0.025 = 3.75 x 10–3 mols
  • Step 2: Using the equation, calculate the number of moles of nitric acid 
    • Moles of nitric acid = 3.75 x 10–3 x 2 = 7.5 x 10-3
    • The number of moles must be multiplied by 2 due to the 1:2 ratio
  • Step 3: Calculate the concentration of nitric acid
    • Concentration of nitric acid = fraction numerator 7.5 cross times 10 to the power of negative 3 end exponent over denominator 0.0128 end fraction = 0.59 mol/dm3 to 2 dp
  • Remember to convert cm3 to dm3 by dividing by 1000 

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Stewart

Author: Stewart

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Stewart has been an enthusiastic GCSE, IGCSE, A Level and IB teacher for more than 30 years in the UK as well as overseas, and has also been an examiner for IB and A Level. As a long-standing Head of Science, Stewart brings a wealth of experience to creating Exam Questions and revision materials for Save My Exams. Stewart specialises in Chemistry, but has also taught Physics and Environmental Systems and Societies.