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Concentration of Solutions (AQA GCSE Chemistry)

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  • Using moles, volume in dm3 and concentration, complete the equation:

    Moles =

    (Higher tier only)

    Using moles, volume in dm3 and concentration, the equation is:

    Moles = concentration x volume

  • Calculate the number of moles of solute present in 2.0 dm3 of a solution whose concentration is 0.15 mol dm-3.

    (Higher tier only)

    To calculate the number of moles of solute present in 2.0 dm3 of a solution whose concentration is 0.15 mol dm-3:

    • Moles = concentration x volume

    • Moles = 0.15 x 2.0 = 0.3 moles

  • What are the two common units for concentration?

    (Higher tier only)

    The two common units for concentration are:

    • g / dm3

    • mol / dm3

  • State the equation for concentration using moles and volume.

    (Higher tier only)

    The equation for concentration using moles and volume is:

    concentration = moles / volume

  • What is the concentration of a solution where 1.0 mole of solute is dissolved in 2.0 dm3 of water?

    (Higher tier only)

    The concentration of a solution where 1.0 mole of solute is dissolved in 2.0 dm3 of water is:

    • Concentration = moles / volume

    • Concentration = 1.0 / 2.0 = 0.5 mol dm-3

  • How do you calculate the volume of a solution using moles and concentration?

    (Higher tier only)

    The equation to calculate the volume of a solution using moles and concentration is:

    Volume = moles / concentration

  • Using volume in dm3 and concentration, complete the equation:

    Moles =

    (Higher tier only)

    Using moles, volume in dm3 and concentration, the equation is:

    Moles = concentration x volume

  • Calculate the number of moles in 2.5 dm3 of a solution that has a concentration of 0.30 mol dm-3.

    (Higher tier only)

    To calculate the number of moles present in 2.5 dm3 of a solution which has a concentration of 0.30 mol dm-3:

    • Moles = concentration x volume

    • Moles = 0.30 x 2.5 = 0.75 moles

  • What is 27.50 cm3 in dm3?

    (Higher tier only)

    27.50 cm3 is 0.0275 dm3.

  • A solution of HCl has a volume of 23.55 cm3 and contains 0.00375 moles. What is its concentration in mol/dm3?

    (Higher tier only)

    The concentration in mol/dm3 of a solution of HCl with a volume of 23.55 cm3 and contains 0.00375 moles is:

    • Volume in dm3 = 0.02355 dm3

    • Concentration = fraction numerator 0.00375 over denominator 0.02355 end fraction = 0.16 mol/dm3

  • What are the four steps to solve a titration calculation?

    (Higher tier only)

    The four steps in a titration calculation are:

    1. Write out the balanced equation for the reaction

    2. Calculate the moles of the known solution given the volume and concentration

    3. Use the equation to deduce the moles of the unknown solution

    4. Use the moles and volume of the unknown solution to calculate the concentration

  • Using moles and volume in dm3, complete the equation:

    Concentration =

    (Higher tier only)

    Using moles, volume in dm3 the equation is:

    Concentration = moles over volume

  • What is 0.03905 dm3 in cm3?

    (Higher tier only)

    0.03905 dm3 is 39.05 cm3.

  • Explain how many moles of HCl will be neutralised by 0.05 moles of NaOH.

    HCl + NaOH → NaCl + H2O

    (Higher tier only)

    0.05 moles of HCl would be required as this reaction is a 1:1 ratio.

Previous:Yield & Atom EconomyNext:Amount of Substance & Gas Volume

    1. Topic 1

      Simple Model of the Atom

    2. Topic 2

      The Periodic Table

    3. Topic 3

      Properties of Transition Metals

    1. Topic 1

      Ionic, Covalent & Metallic Bond

    2. Topic 2

      Bonding & Substance Properties

    3. Topic 3

      Structure & Bonding of Carbon

    4. Topic 4

      Bulk & Surface Properties

    1. Topic 1

      Measurement, Mass & Equations

    2. Topic 2

      Calculating Mass of Substances

    3. Topic 3

      Yield & Atom Economy

    4. Topic 4

      Concentration of Solutions

    5. Topic 5

      Amount of Substance & Gas Volume

    1. Topic 1

      Reactivity of Metals

    2. Topic 2

      Reactions of Acids

    3. Topic 3

      Electrolysis

    1. Topic 1

      Exothermic & Endothermic Reactions

    2. Topic 2

      Chemical Cells & Fuel Cells

    1. Topic 1

      Rate of Reaction

    2. Topic 2

      Reversibility & Equilibrium

    1. Topic 1

      Hydrocarbons: Fuel & Feedstock

    2. Topic 2

      Reactions of Alkenes & Alcohols

    3. Topic 3

      Synthetic & Natural Polymers

    1. Topic 1

      Purity, Formulations & Chromatography

    2. Topic 2

      Identification of Common Gases

    3. Topic 3

      Methods of Identifying Ions

    1. Topic 1

      Formation of Earth's Atmosphere

    2. Topic 2

      CO2 & CH4 as Greenhouse Gases

    3. Topic 3

      Causes of Atmospheric Pollution

    1. Topic 1

      Global Reserves & Potable Water

    2. Topic 2

      Life Cycle Analysis & Recycling

    3. Topic 3

      Using Materials

    4. Topic 4

      Haber Process & NPK Fertilisers