The diagram below shows an arrangement used to investigate double-slit interference using microwaves.
The diagram below shows the view from above.
The microwaves from the transmitter are polarised. These waves are detected by the aerial in the microwave detector. The aerial is a vertical metal rod.
The detector is moved along the dotted line HL. As it is moved, maximum and minimum signals are detected. Maximum signals are first detected at points I and J. The next maximum signal is detected at position K.
The distances between each of the two slits, S1 and S2 and the microwave receiver when the aerial is in position K are S1K = 0.1115 m and S2K = 0.0315 m
Which of the following reasons explains why the signal strength falls to a minimum between H and I, and between I and J?
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Reason 1
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Reason 2
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Reason 3
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A.
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Waves are out of phase
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Gives rise to a path difference
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Destructive interference occurs
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B.
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Waves are out of phase
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Gives rise to a path difference
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Constructive interference occurs
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C.
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Path difference for the two waves
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Gives rise to a phase difference
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Constructive interference occurs
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D.
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Path difference for the two waves
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Gives rise to a phase difference
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Destructive interference occurs
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