Atomic Mass Unit (DP IB Physics: HL)

• The unified atomic mass unit u is roughly equal to the mass of one proton or neutron:
  • 1u = 1.66 × 10⁻²⁷ kg

• It is sometimes abbreviated to a.m.u
• This value will be given on your data booklet in the exam
• The a.m.u is commonly used in nuclear physics to express the mass of subatomic particles.
• It is defined as: 

1 u is a twelfth of the mass of a (neutral) atom of carbon-12

Part (a)

Part (b)

Step 1: Identify the components of copernicium-285

• • Since the element is copernicium which is the 112th element, this atom must have 112 protons
  • Therefore, it will have:

285 – 112 = 173 neutrons in its nucleus

Step 2: Determine the amount of atomic mass units for these components

• • The proton's mass can be found by multiplying the number of them by their mass in amu which is given in the data booklet:

112 × 1.007276 = 112.814912 u

• • The neutron's mass similarly can be found using their relevant amu mass:

173 × 1.008665 = 174.499045 u

Step 3: Combine the amu mass of the protons and neutrons

• • This combination is a mass of:

112.814912 + 174.499045 = 287.313957 u

Step 4: Convert the amount of mass from amu to kg

• • The conversion is done using the value:
    • 1 u = 1.66 × 10⁻²⁷ kg

287.313957 × 1.66 × 10⁻²⁷ = 4.7694116862 × 10^-25 kg

Step 5: State the final answer to 5 decimal places

• • The final answer for the total mass of all components of nucleus of element copernicium-285 is approximately:

4.76941 × 10^-25 kg