Collisions & Explosions (DP IB Physics: HL)

• In both collisions and explosions, momentum is always conserved
  • However, kinetic energy might not always be

• A collision (or explosion) is either:
  • Elastic – if the kinetic energy is conserved
  • Inelastic – if the kinetic energy is not conserved

• Collisions are when objects strike against each other
  • Elastic collisions are commonly those where objects colliding do not stick together and then move in opposite directions
  • Inelastic collisions are commonly those where objects collide and stick together after the collision

Elastic collisions are where two objects move in opposite directions. Inelastic collisions are where two objects stick together

• An explosion is commonly to do with recoil
  • For example, a gun recoiling after shooting a bullet or an unstable nucleus emitting an alpha particle and a daughter nucleus

• To find out whether a collision is elastic or inelastic, compare the kinetic energy before and after the collision
• The equation for kinetic energy is:

• The principle of conservation of momentum can be used to solve various types of problems for isolated systems such as problems involving:
  • Collisions
  • Fluid jets
  • Conveyor belts
  • Explosions & many more

• Kinetic energy can also be used to check if a collision is elastic or inelastic
  • In elastic collisions, momentum and kinetic energy are conserved
  • In inelastic collisions, momentum is conserved, but kinetic energy is not
  • Inelastic includes explosions

Step 1: List the known quantities

• • Mass of the crossbow: 2 kg
  • Mass of the arrow: 100 g = 0.1 kg
  • Speed of arrow during release: 40 m s⁻¹

Step 2: Determine the momentum before release

• • Since before release neither the arrow nor the crossbow was moving, their momentum together is 0 kg m s⁻¹

Step 3: Determine the momentum of the arrow

• • The momentum of the arrow can be found from the equation:

p = m × v

p_arrow = 0.1 × 40 = 4 kg m s⁻¹

Step 4: Determine the recoil velocity of the crossbow

• • The arrow has a momentum of 4 kg m s⁻¹ and the system had a total momentum of 0 kg m s⁻¹ before the collision
  • Therefore, the crossbow must have a momentum of 4 kg m s⁻¹ in the opposite direction to the arrow
  • Therefore:

p_crossbow = m × v

p_crossbow ÷ m = v

v = 4 ÷ 2 = 2 m/s in opposite direction to arrow

Step 5: State the final answer

• • The magnitude of the recoil velocity of the crossbow is 2 m s⁻¹.