Electric & Magnetic Fields (DP IB Physics: SL): Exam Questions

2 hours37 questions
1a2 marks

Sketch a diagram to show the electric field that acts between the two charges.  

5-1-3a-qun-sl-sq-easy-phy
1b2 marks

Indicate, by drawing a circle around an area on your diagram from part (a) where the field lines are more dense and explain why they look like this.

1c2 marks

Sketch a diagram to show the electric field that acts between the two charges. 

5-1-3c-qun-sl-sq-easy-phy
1d2 marks

Identify the differences between the central area of the diagrams you draw in (a) and (c).

2a2 marks

In a vacuum, an alpha particle open parentheses alpha presubscript 2 presuperscript 4 close parentheses approaches an aluminium nucleus open parentheses Al presubscript 13 presuperscript 27 close parentheses

Describe the nature of the force between the alpha particle and the aluminium nucleus.

2b
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3 marks

The distance between the centres of the alpha particle and the aluminium nucleus is 4.7 fm.

Calculate the magnitude of the electrostatic force on each particle.

3a2 marks

Draw the electric field lines around the positive and negative point charges below. 

10-1-ib-hl-sqs-easy-q4a-question
3b2 marks

The diagram shows two parallel plates of opposite charge.

10-1-ib-hl-sqs-easy-q4b-question10-1-ib-hl-sqs-easy-q4b-question

Draw the electric field lines between the two plates.

4a
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3 marks

The diagram shows a negative ion which is free to move in a uniform electric field.   

5a-figure-1

For the negative ion:

(i) State the direction of the electrostatic force acting on it.

[1]

(ii) Explain your answer with reference to the electric field lines in the diagram.

[2]

4b
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2 marks

4.0 × 10–16 J of work is done on the ion to accelerate it through the field a distance of 63 mm in a line parallel to the field lines.

Calculate the magnitude of the electrostatic force acting on the negative ion.

1a2 marks

Electric fields exist in the space around charged particles. The strength of an electric field depends on the position occupied within that space.

Outline what is meant by the strength of an electric field.

1b2 marks

An electron e- and a positron e+ occupy two positions in space.

q1b_electric-fields_ib-sl-physics-sq-medium

Sketch on the image the resultant electric field in the region between the electron and the positron.

1c
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3 marks

The distance between the electron and the positron is 150 cm.

(i) Calculate the magnitude of the electrostatic force between the electron and the positron.

                                                 [2]

(ii) State the direction of the electrostatic force on the electron.

                                                 [1]

1d2 marks

A positive test charge is placed exactly midway between the electron and the positron.

Outline the subsequent motion of the positive test charge. 

2a4 marks

A parallel-plate capacitor is an electrical component that stores electric charge.

It is set up by connecting two metal plates to a power supply. 

q3_electric-fields_ib-sl-physics-sq-medium

Label:

(i) the positively charged metal plate with the letter A

[1]

(ii) the negatively charged metal plate with the letter B

[1]

(iii) the electric field lines between the plates.

[2]

2b2 marks

State, for each of the scenarios below, whether the electric field strength between the metal plates increases, decreases, or stays constant:

(i) a positive test charge moving from one plate to the other.

[1]

(ii) a positive test charge moving between the plates along a line parallel to each other.

[1]

2c
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3 marks

A free electron finds itself incident in the space between the metal plates and is deflected as it moves between them.

q3c_electric-fields_ib-sl-physics-sq-medium

The magnitude of the electric field strength is 200 N C–1.

Calculate the magnitude of the electron’s acceleration in the space between the plates.

2d3 marks

Explain the shape of the path shown in part (c).

3a2 marks

State Coulomb’s law in words.

3b
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4 marks

In simple models of the hydrogen atom, an electron is in a circular orbit around the proton.

The magnitude of the force between the proton and the electron is 5.8 × 10–9 N.

Calculate:

(i) the orbital radius of the electron.

                                                [2]

(ii) the magnitude of the electric field strength due to the proton at any point in the electron’s orbit.

                                                [2]

3c
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4 marks

The gravitational field strength g due to the proton at any point in the electron’s orbit is given by the equation:

g space equals space G m subscript p over r squared

where m subscript p is the proton mass, r is the orbital radius and G is the gravitational constant.

Show that the ratio of the gravitational field strength to the electric field strength due to the proton at any point in the electron’s orbit is of the order 10–28.  

3d
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2 marks

Ionisation is the process of removing an outer shell electron from an atom, so it is transferred from its orbit to a point where the potential is zero.

The potential difference between the electron’s orbit in a hydrogen atom and this point is about 3.4 V.

Calculate the gain in potential energy of an orbiting electron in a hydrogen atom if it is ionised.

4a3 marks

A β particle is placed above a grounded metal plate. 

10-1-hl-sq-medium-q4a

Sketch the electric field lines between the β particle and the metal plate. 

4b3 marks

The β particle is replaced with an α particle at the same position above the grounded metal surface. 

Outline the similarities and differences between the electric field now created to that in part (a).

4c3 marks

The grounded metal surface is removed in order to analyse the combined electric field created between the α particle and the β particle. 

Sketch the electric field produced between an α particle and a β particle.

10-1-hl-sq-medium-q4c
4d2 marks

State and explain whether there is a point of zero electric field for the diagram in part (c).

5a2 marks

A charge –q with mass m orbits a stationary charge with a constant orbital radius r

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Draw the electrostatic force on –q due to the electric field created by q.

5b2 marks

Show that the orbital speed of v is given by: 

v equals square root of fraction numerator 1 over denominator 4 pi epsilon subscript 0 m r end fraction end root space q

1a2 marks

Four point charges A, B, C and D are each placed at a distance d from O as shown. Charges B, C and D each have a charge of +q and A has a charge ­–q.

5-1-ib-sl-sq-hard-q1a-qun

(i) Show that the magnitude of the resultant electric field strength at O is fraction numerator 2 k q over denominator d squared end fraction.

[1]

(ii) Determine the direction of the resultant electric field at O.

[1]

1b2 marks

The arrangement of the charges is changed to the grid shown below. Each charge is now the corner of a square of side x, where x = 2d.

5-1-ib-sl-sq-hard-q1b-qun

Determine the magnitude of the resultant electric field strength at point O in terms of q and d.

2a
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3 marks

The diagram shows an air filter which uses charged collecting plates to remove dust from the air of a workshop.

The air intake passes through a charged, ionising grid which attracts dust particles, cleaning the air which is then returned back into the workshop.

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A dust particle of mass 6.7 × 10–15 kg enters the region between the collecting plates travelling horizontally with an initial velocity of 11 m s–1. The particle carries a charge of 2.6 × 10–18 C.

Assume that the dust particles move horizontally between the plates.

5-1-ib-sl-sq-hard-2a-qun2

Determine the electrostatic force acting on the particle.

2b
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4 marks

Some particles are not caught by the air filter, but pass straight through. Others are caught by the filter. The particles are identical in mass and charge, and they all travel parallel to the plane of the plates. The plates are initially completely clean. Assume the particles are evenly vertically distributed.

Deduce the percentage of dust particles which will be 'trapped' by the negatively charged plate. Ignore the effect of gravity.  

2c3 marks

As the air filter operates, there is a build up of particles on the negative plates. The gap between the plates therefore becomes narrower, by up to 10% of its initial height.

Discuss whether this narrowing makes the filter more or less effective at removing dust particles.

3a
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5 marks

Two charged objects X and Y are made to circle a point O. X and Y are at a distance, d = 1.8 × 10-8 m and they have equal masses, where m = 1.7 × 10-9 kg.

The objects carry an equal but opposite charge, where the magnitude q = 3.2 × 10-19 C.

dae17afb-852e-4b5a-8723-1796e5ba2bd7-1

For this motion calculate

(i) the acceleration of X and Y.

[3]

(ii) the time to make one complete orbit.

[2]

3b
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2 marks

The particles X and Y in part (a) are replaced with a gold nucleus A presubscript 79 presuperscript 197 u, and an alpha particle.

Calculate the field strength at the surface of

(i) a gold nucleus with a radius of 7.0 fm.

[1]

(ii) an alpha particle with a radius of 1.7 fm.

[1]

4a
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3 marks

An experiment to determine the charge on an electron is shown.   

ib-sl-5-1-sq-4a-question

Negatively charged oil drops are sprayed into a region above two parallel metal plates, which are separated by a distance, d. The oil drops enter the region between the plates.

A potential difference V is applied across the plates, which causes an electric field to be set up.

(i) Sketch, on the diagram below, the electric field lines between the plates.

ib-sl-5-1-sq-4a-question-part-2

[1]

(ii) Explain why the oil drop stops falling when V is increased.

[2]

4b
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2 marks

The oil drop has mass = m and charge = q. The distance between the plates = 2.5 cm.

The oil drop stops falling when potential difference, V = 5000 V

Determine the charge to mass ratio of the oil drop.

4c
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2 marks

Two oil drops are suspended between the plates at the same time. The oil drops can be considered as identical point charges with mass 1 × 10−13 kg which are spaced 2.2 mm apart.

Calculate the electrostatic force between the drops.

4d2 marks

For the oil drops in part (c)

Describe and explain the expected observations as the potential difference increases above 5000 V, using a mathematical expression to justify your answer.