Describing Oscillations (DP IB Physics): Revision Note

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Katie M

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Properties of Oscillations

  • An oscillation is defined as follows:

The repetitive variation with time t of the displacement x of an object about the equilibrium position (x = 0)

  • The equilibrium position (x = 0) is the position when there is no resultant force acting on the object

    • This is the fixed central point that the object oscillates around

4-1-1-graphing-oscillations_sl-physics-rn

A pendulum oscillates between A and B. On a displacement-time graph, the oscillating motion of the pendulum is represented by a wave, with an amplitude equal to x0

  • A particle undergoing an oscillation can be described by the following properties:

    • displacement

    • amplitude

    • time period

    • frequency

    • angular frequency

Displacement

  • Displacement (x) is the horizontal or vertical distance of a point on the wave from its equilibrium position

    • It is a vector quantity

    • It can be positive or negative, depending on which side of the oscillation it is

    • It is measured in metres (m)

Amplitude

  • Amplitude (x0) is the maximum value of the displacement on either side of the equilibrium position

    • Amplitude is measured in metres (m)

5-5-4-amplitude-explanation

When the pendulum is in its extreme position, this is its amplitude

Time period

  • Period (T) or time period, is the time interval for one complete oscillation measured in seconds (s)

    • If the oscillations have a constant period, they are said to be isochronous

Displacement time wave, downloadable AS & A Level Physics revision notes

Diagram showing the time period of a wave

Frequency

  • Frequency (f) is the number of oscillations per second and it is measured in hertz (Hz)

    • Hz has the SI units per second s−1 because f space equals space 1 over T

Angular frequency

  • Angular frequency (ω) is the rate of change of angular displacement with respect to time

    • It is measured in radians per second (rad s−1)

Worked Example

The diagram below shows plane waves on the surface of water at a particular instant. A and B are two points on the wave.

WE - Wave properties question image, downloadable AS & A Level Physics revision notes

Determine:

(a) The amplitude

(b) The wavelength

Answer:

worked-example

Examiner Tips and Tricks

When labelling the amplitude and time period on a diagram:

  • Make sure that your arrows go from the very top of a wave to the very top of the next one

  • If your arrow is too short, you will lose marks

  • The same goes for labelling amplitude, don’t draw an arrow from the bottom to the top of the wave, this will lose you marks too.

Calculating Time Period of an Oscillation

  • This equation relates the frequency and the time period of an oscillation: 

Frequency-period equation, downloadable AS & A Level Physics revision notes

The equation linking time period and frequency

  • Angular frequency () can be calculated using the equation:

omega space equals space fraction numerator 2 straight pi over denominator T end fraction space equals space 2 straight pi f

  • Where:

    • = angular frequency (rad s-1)

    • 2π = circumference of a circle

    • T = time period (s)

    • f = frequency of oscillation (Hz)

  • The angular displacement of objects in oscillation can be determined by matching the displacement to an object in circular motion:

    • After moving from one amplitude position = −to the equilibrium position = 0, the mass on the spring has an angular displacement of 1 fourth of a circle = 1 fourth cross times 2 straight pi space equals space straight pi over 2 radians

    • Continuing the oscillation from the equilibrium position to the other amplitude position, the angular displacement is also straight pi over 2 radians

    • Continuing the oscillation back to the starting point means the mass travels a further angular displacement of straight pi over 2 plus straight pi over 2 space equals space straight pi radians

    • Hence, the total angular displacement in one oscillation is straight pi plus straight pi space equals bold space 2 straight pi radians

5-5-2-angular-frequency-oscillation-link

The motion of an oscillating object can be analysed in terms of a fraction of an object in circular motion

Worked Example

A child on a swing performs 0.2 oscillations per second.

Calculate the time period of the oscillation.

Answer:

Step 1: Write down the known quantities

  • Frequency, f = 0.2 Hz

Step 2: Write down the relationship between the period T and the frequency f

T space equals space 1 over f

Step 3: Substitute the value of the frequency into the above equation and calculate the period 

T italic space equals space fraction numerator 1 over denominator 0.2 end fraction space equals space 5.0 space straight s

Worked Example

A cuckoo in a cuckoo clock emerges from a fully compressed position to a fully extended position in 1.5 seconds. 

Calculate the angular frequency of the cuckoo as it emerges from the clock. 

Answer:

Step 1: Consider the motion of the cuckoo

  • The cuckoo goes from being fully compressed to fully extended which means that it travels for an angular displacement of half a circle and not a full circle

  • So, the angular displacement will be π

5-5-2-angular-frequency-we_ocr-al-physics

Step 2: Substitute into the equation for angular velocity and time period

ω fraction numerator 2 straight pi over denominator T end fraction= fraction numerator straight pi over denominator 1.5 end fraction = 2.09 rad s-1

Step 3: State the final answer

  • The angular frequency of the cuckoo as it emerges from the clock is 2.1 rad s-1 (2 s.f.)

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Katie M

Author: Katie M

Expertise: Physics Content Creator

Katie has always been passionate about the sciences, and completed a degree in Astrophysics at Sheffield University. She decided that she wanted to inspire other young people, so moved to Bristol to complete a PGCE in Secondary Science. She particularly loves creating fun and absorbing materials to help students achieve their exam potential.