Syllabus Edition

First teaching 2023

First exams 2025

|

Amount of Substance (SL IB Physics)

Revision Note

Ashika

Author

Ashika

Last updated

Amount of Substance

  • The mole is one of the seven SI base units
    • It is used to measure the amount of substance, not a mass
  • One mole is defined as follows:

The amount of substance that contains as many elementary entities as the number of atoms in 12 g of carbon-12

  • This amount of substance is exactly 6.02214076 × 1023 elementary entities (i.e. particles, atoms, molecules)
    • At IB level, this number can be rounded to 6.02 × 1023
  • One mole of gas contains a number of particles (atoms or molecules) equal to the Avogadro Constant
  • For example, 1 mole of sodium (Na) contains 6.02 × 1023 atoms of sodium
  • The number of atoms can be determined if the number of moles is known by multiplying by NA.
    • For example: 2.0 mol of argon contains:  2.0 × NA = 2.0 × 6.02 × 1023 = 1.20 × 1024 atoms
  • The number of moles, n of a substance can be calculated using the equation

n space equals fraction numerator space N over denominator N subscript A end fraction

  • Where:
    • N = number of particles (molecules or atoms, depending on the substance)
    • n = number of moles of gas (mol)
    • NA = 6.02 × 1023 mol–1 (Avogadro constant)

Molar Mass

  • One mole of any element is equal to the relative atomic mass of that element in grams
    • E.g. Helium has a relative atomic mass of 4 - this means 1 mole of helium has a mass of 4 g

  • If the substance is a compound, add up the relative atomic masses, for example, water (H2O) is made up of
    • 2 hydrogen atoms (each with atomic mass of 1) and 1 oxygen atom (atomic mass of 16)
    • So, 1 mole of water would have a mass of (2 × 1) + 16 = 18 g
  • The molar mass, m of a substance is defined as the mass m of the substance divided by the amount (in moles) of that substance
  • The molar mass is calculated as follows:

m subscript r space end subscript space equals fraction numerator space m over denominator n end fraction

  • Where:
    • mr = molar mass in g mol–1
    • m = mass in grams (g)
    • n = number of moles (mol)

Worked example

120 moles of nitrogen gas are in a container.

Calculate the number of nitrogen gas molecules in the container.

Answer:

Step 1: List the known quantities

  • Number of moles, n = 120 

Step 2: Rearrange the number of moles equation for the number of molecules, N

N space equals space n N subscript A

Step 3: Substitute in the values

N space equals space open parentheses 6.02 space cross times space 10 to the power of 23 close parentheses space cross times space 120 space equals space 7.2 space cross times space 10 to the power of 25 molecules

Worked example

A container is filled with 2.6 × 1020 molecules of argon gas which has a mass number of 40. 

Calculate the total mass of argon in the container.

Answer:

Step 1: List the known quantities

  • Number of argon gas molecules, N = 2.6 × 1020
  • Molar mass of argon, mr = 40 g mol–1 (same as the atomic mass)

Step 2: Calculate the number of moles of argon in the container

n space equals space fraction numerator space N over denominator N subscript A end fraction space equals space fraction numerator 2.6 space cross times space 10 to the power of 20 space over denominator 6.02 space cross times space 10 to the power of 23 end fraction space equals space 4.3 space cross times space 10 to the power of negative 4 end exponent space space moles

Step 3: Calculate the total mass of the argon in the container

m space equals space m subscript r space cross times space n space equals space 40 space cross times space open parentheses 4.3 space cross times space 10 to the power of negative 4 end exponent close parentheses space equals space 0.0172 space g

Examiner Tip

The value of the Avogadro constant is given on your data sheet, so you don't need to learn this value. However, it does help make calculations quicker if you do!

Take care with the units for molar mass, this is g mol–1, so multiplying by the number of moles gives a mass in grams and not kilograms.

You've read 0 of your 10 free revision notes

Unlock more, it's free!

Join the 100,000+ Students that ❤️ Save My Exams

the (exam) results speak for themselves:

Did this page help you?

Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.