Quantum Physics (DP IB Physics)

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  • What is the photoelectric effect?

    The photoelectric effect is a phenomenon in which electrons are emitted from the surface of a metal upon the absorption of electromagnetic radiation.

  • What are photoelectrons?

    Photoelectrons are electrons that are emitted from the surface of a metal upon the absorption of electromagnetic radiation.

  • True or False?

    In the photoelectric effect, each electron in the metal can absorb multiple photons.

    False.

    In the photoelectric effect, each electron in the metal can absorb only one photon.

  • Define threshold frequency.

    Threshold frequency is the minimum frequency of incident electromagnetic radiation required to remove a photoelectron from the surface of a metal.

  • True or False?

    The threshold frequency is different for different metals.

    True.

    The threshold frequency is different for different metals.

  • Define work function.

    The work function is the minimum energy required to release a photoelectron from the surface of a metal.

  • True or False?

    An electron can only escape from the surface of the metal if it absorbs a photon with an energy equal to or higher than the work function.

    True.

    An electron can only escape from the surface of the metal if it absorbs a photon with an energy equal to or higher than the work function.

  • True or False?

    The work function is different for different metals.

    True.

    The work function is different for different metals.

  • State the symbol for work function.

    The symbol for work function is the Greek letter, phi, capital phi.

  • State the symbol for threshold frequency.

    The symbol for work function is space f subscript 0.

  • True or False?

    A photon with a frequency greater than the threshold frequency of a metal will also have an energy greater than the work function of the metal.

    True.

    A photon with a frequency greater than the threshold frequency of a metal will also have an energy greater than the work function of the metal.

    This is because the energy of a photon is directly proportional to its frequency.

  • If a photon has an energy greater than the work function of the metal, what happens to the surplus energy?

    When a photon has an energy greater than the work function of the metal, a photoelectron is released from the metal and the surplus energy is transferred to the kinetic energy of the photoelectron.

  • State the photoelectric equation. in terms of the energy of the incident photon.

    The photoelectric equation is h f space equals space capital phi space plus space E subscript k space m a x end subscript

    Where:

    • h = Planck constant, measured in joule seconds (J s)

    • f = frequency of photon, measured in hertz (Hz)

    • capital phi = work function of metal, measured in joules (J) or electronvolts (eV)

    • E subscript k space m a x end subscript = kinetic energy of photoelectron, measured in joules (J)

  • State the photoelectric equation in terms of the maximum kinetic energy of a photoelectron.

    The photoelectric equation is E subscript k space m a x end subscript space equals space h f space minus space capital phi space

    Where:

    • E subscript k space m a x end subscript = kinetic energy of photoelectron, measured in joules (J)

    • h = Planck constant, measured in joule seconds (J s)

    • f = frequency of photon, measured in hertz (Hz)

    • capital phi = work function of metal, measured in joules (J) or electronvolts (eV)

  • True or False?

    A photoelectron that only just escapes the surface of the metal will have zero kinetic energy.

    True.

    A photoelectron that only just escapes the surface of the metal will have zero kinetic energy.

  • True or False?

    A photon that does not have enough energy to overcome the work function will not liberate any electrons from the surface of the metal.

    True.

    A photon that does not have enough energy to overcome the work function will not liberate any electrons from the surface of the metal.

  • True or False?

    The majority of photoelectrons will have energies equal to E subscript k space m a x end subscript.

    False.

    The majority of photoelectrons will have energies less than E subscript k space m a x end subscript.

  • True or False?

    A photon with a frequency equal to the threshold frequency will be able to liberate an electron from the surface of the metal.

    True.

    A photon with a frequency equal to the threshold frequency will be able to liberate an electron from the surface of the metal, but that photoelectron will have a kinetic energy of zero.

  • True or False?

    The maximum kinetic energy of a photoelectron is independent of the intensity of the radiation.

    True.

    The maximum kinetic energy of a photoelectron is independent of the intensity of the radiation.

  • True or False?

    The maximum kinetic energy of a photoelectron is independent of the frequency of the incident photon.

    False.

    The maximum kinetic energy of a photoelectron depends only on the frequency of the incident photon.

  • State the kinetic energy equation in terms of the maximum kinetic energy of a photoelectron.

    The equation for the maximum kinetic energy of a photoelectron is E subscript k space m a x end subscript space equals space 1 half m subscript e v subscript m a x end subscript squared

    Where:

    • E subscript k space m a x end subscript = kinetic energy of photoelectron, measured in joules (J)

    • m subscript e = electron rest mass, measured in kilograms (kg)

    • v subscript m a x end subscript = maximum velocity of photoelectron, measured in metres per second (m s–1)

  • Why is the kinetic energy of a photoelectron independent of the intensity of the incident radiation?

    The kinetic energy of a photoelectron is independent of the intensity of the incident radiation because each electron can only absorb one photon.

  • Why does the kinetic energy of the photoelectrons vary for a specific metal?

    The kinetic energy of the photoelectrons varies because some of the electrons are closer to the surface of the metal than others.

    Those that are closer to the surface require less energy to escape and therefore have more surplus energy left over from the photon.

  • Define photoelectric current.

    The photoelectric current is a measure of the number of photoelectrons emitted per second from the surface of a metal undergoing the photoelectric effect.

  • True or False?

    Photoelectric current is proportional to the intensity of the incident radiation.

    True.

    Photoelectric current is proportional to the intensity of the incident radiation.

  • Define stopping potential in relation to the photoelectric effect.

    Stopping potential is the potential difference required to stop photoelectron emission from occurring.

  • What information does the stopping potential provide about the photoelectrons?

    The stopping potential provides information about the maximum kinetic energy of the photoelectrons.

  • What quantum effect can a gold leaf electroscope be used to demonstrate?

    A gold leaf electroscope can be used to demonstrate the photoelectric effect.

  • How is a gold leaf electroscope used to show the photoelectric effect?

    To show the photoelectric effect using a gold leaf electroscope:

    • the metal plate is given a negative charge

    • the gold leaf is repelled

    • UV light is shone onto the metal plate

    • photoelectrons are emitted

    • the gold leaf is no longer repelled

  • True or False?

    In the gold leaf electroscope demonstration, the gold leaf begins to fall down instantly when illuminated with UV light.

    True.

    In the gold leaf electroscope demonstration, the gold leaf begins to fall down instantly when illuminated with UV light. This is evidence for the one-to-one quantised transfer of energy from photon to electron.

  • True or False?

    In the gold leaf electroscope demonstration, the gold leaf takes longer to fall at low intensities of UV light and does not happen instantly.

    False.

    In the gold leaf electroscope demonstration, the gold leaf does take longer to fall at low intensities of UV light, but it does still happen instantly.

  • True or False?

    In the gold leaf electroscope demonstration, the gold leaf does not fall down when lower frequencies of light are used.

    True.

    In the gold leaf electroscope demonstration, the gold leaf does not fall down when lower frequencies of light are used.

    This provides evidence for the threshold frequency and work function of metals.

  • True or False?

    In the gold leaf electroscope demonstration, the gold leaf falls when the intensity of the light is increased, even if the frequency is lower than the threshold frequency.

    False.

    In the gold leaf electroscope demonstration, the gold leaf does not fall when the intensity of the light is increased if the frequency is lower than the threshold frequency.

    This provides evidence for the threshold frequency and work function.

  • True or False?

    Wave theory can be used to explain the photoelectric effect.

    False.

    Wave theory cannot be used to explain the photoelectric effect; the wave model predicts that:

    • photoelectrons would be released at any frequency because energy would be accumulated by the electron with each wavefront

    • the kinetic energy of the emitted photoelectrons should be dependent on the intensity because, for a given frequency, the energy of a wave is proportional to the intensity of the light

  • True or False?

    Louis de Broglie proposed that electrons could behave like waves.

    True.

    Louis de Broglie proposed that electrons could behave like waves, based on the idea that waves (light) can behave like particles (photons).

  • What is meant by de Broglie wavelength?

    The de Broglie wavelength is the wavelength associated with a moving particle.

  • State the equation for the de Broglie wavelength.

    The equation for the de Broglie wavelength is: lambda space equals h over p

    Where:

    • lambda = de Broglie wavelength, measured in metres (m)

    • h = Planck constant (6.63 × 10-34 J s)

    • p = momentum, measured in kilogram metres per second (kg m s–1)

  • How is momentum derived from the kinetic energy equation?

    Momentum derived from the kinetic energy equation as follows:

    • E subscript k space equals space 1 half m v squared space equals fraction numerator space open parentheses m v close parentheses squared over denominator 2 m end fraction space equals fraction numerator space p squared over denominator 2 m end fraction

    • p space equals space square root of 2 m E subscript k end root

  • State the equation linking the de Broglie wavelength and the kinetic energy of the moving particle.

    The equation linking the de Broglie wavelength and the kinetic energy of the moving particle lambda space equals fraction numerator h over denominator square root of 2 m E subscript k end root end fraction

    Where:

    • lambda = de Broglie wavelength, measured in metres (m)

    • h = Planck constant (6.63 × 10-34 J s)

    • m = mass of the particle, measured in kilograms (kg)

    • E subscript k = kinetic energy of the particle, measured in joules (J)

  • True or False?

    For everyday objects travelling at normal speeds, the de Broglie wavelength is far too small for any quantum effects to be observed.

    True.

    For everyday objects travelling at normal speeds, the de Broglie wavelength is far too small for any quantum effects to be observed.

  • True or False?

    The quantum effects of electron diffraction will only be observable when the width of the aperture is of a similar size to the de Broglie wavelength.

    True.

    The quantum effects of electron diffraction will only be observable when the width of the aperture is of a similar size to the de Broglie wavelength.

  • What type of atomic lattice is usually used to demonstrate electron diffraction?

    The type of atomic lattice usually used to demonstrate electron diffraction is graphite film because of its crystalline structure.

  • Describe the diffraction pattern produced from electron diffraction.

    The diffraction pattern produced from electron diffraction is a series of concentric rings.

  • Explain why the radius of the electron diffraction pattern decreases as the voltage applied to the electron diffraction tube is increased.

    As the voltage applied to the electron diffraction tube is increased:

    • the speed of the electrons increases

    • the momentum of the electrons increases

    • the kinetic energy of the electrons increases

    • the de Broglie wavelength decreases

    • the angle of diffraction decreases

    • therefore, the radius of the diffraction pattern decreases

  • What is meant by wave-particle duality?

    Wave-particle duality is the theory that light can behave as a particle and as a wave.

  • Give one experiment that provides evidence that light behaves like a wave, and one that provides evidence that light behaves like a particle.

    One experiment that provides evidence that light behaves like a wave is Young's double slit experiment.

    One experiment that provides evidence that light behaves like a particle is the photoelectric effect.

  • Which scientist proposed the corpuscular theory of light, that first described light as particle-like in 1672?

    Newton proposed the corpuscular theory of light in 1672, which first described light as particle-like.

  • Which scientist proposed the wavelet theory of light that first described light as a wave in 1690?

    Huygens proposed the wavelet theory of light in 1690, which first described light as a wave.

  • Which scientist proved that light has wave-like behaviour in 1803 with his double slit diffraction experiment?

    Young proved that light has wave-like behaviour in 1803 with his double slit diffraction experiment.

  • Which scientist first observed the photoelectric effect in 1887, proving that light also has particle-like behaviour?

    Hertz first observed the photoelectric effect in 1887, proving that light also has particle-like behaviour.

  • Which scientist first proposed the idea of quantised energy around 1900?

    Planck first proposed the idea of quantised energy around 1900 when he identified the Planck constant.

  • Which scientist proposed that light can be described as discrete quanta of energy that behaves like particles in 1905?

    Einstein proposed that light can be described as discrete quanta of energy that behaves like particles in 1905.

  • Which scientist proposed wave-particle duality in 1924 and theorised the existence of matter waves?

    De Broglie proposed wave-particle duality in 1924 and theorised the de Broglie wavelength.

  • What is the Compton effect?

    The Compton effect is the interaction of a high-energy photon with an orbital electron, which causes an increase in the wavelength of the photon and the ejection of the electron.

  • What does Compton scattering provide evidence for?

    Compton scattering provides evidence for the particle nature of light.

  • True or False?

    Compton scattering can be explained by considering the incident X-rays as waves.

    False.

    Compton scattering cannot be explained by considering the incident X-rays as waves. It can only be explained using a particle model.

  • Describe the process of Compton scattering.

    In Compton scattering:

    • a photon collides with an orbital electron and transfers some of its energy

    • the wavelength of the photon increases because its energy decreases

    • the photon is deflected from its initial path

    • the electron is ejected from the atom

  • True or False?

    In Compton scattering, the electron and photon are deflected in the same direction due to conservation of momentum.

    False.

    In Compton scattering, the electron and photon are deflected in different directions due to conservation of momentum.

  • State the equation for Compton scattering.

    The equation for Compton scattering is increment lambda space equals space fraction numerator h over denominator m subscript e c end fraction space open parentheses 1 space minus space cos space theta close parentheses

    Where:

    • increment lambda = change in wavelength of the photon, measured in metres (m)

    • h = Planck constant (6.63 × 10-34 J s)

    • m subscript e = rest mass of an electron (9.11 × 10-31 kg)

    • c = speed of light (3.00 × 108 m s–1)

  • What is the name of this constant fraction numerator h over denominator m subscript e c end fraction?

    The constant fraction numerator h over denominator m subscript e c end fraction is called the Compton wavelength.

  • Write an expression for the conservation of energy in Compton scattering.

    Conservation of energy in Compton scattering: E subscript i space equals space E subscript f space plus thin space E subscript e

    • energy before = initial photon energy = E subscript i

    • energy after = final photon energy + electron energy = E subscript f space plus space E subscript e

    • energy before = energy after, or E subscript i space equals space E subscript f space plus thin space E subscript e