Fusion & Stars (DP IB Physics)

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  • What is nuclear fusion?

    Nuclear fusion is the joining of two smaller nuclei to form one larger nucleus, releasing a large amount of energy in the process.

  • Where does nuclear fusion take place in stars?

    Nuclear fusion takes place in the centres (cores) of stars.

  • Why do nuclei require very high kinetic energies in order to fuse?

    Nuclei require very high kinetic energies to fuse to

    • overcome the repulsive coulomb forces between protons

    • get close enough for the strong nuclear force to act

  • Write a nuclear equation for the fusion of two hydrogen-1 nuclei into a hydrogen-2 nucleus.

    The nuclear equation for the fusion of two hydrogen-1 nuclei into a hydrogen-2 nucleus is: straight H presubscript 1 presuperscript 1 space plus space straight H presubscript 1 presuperscript 1 space rightwards arrow space straight H presubscript 1 presuperscript 2 space plus thin space straight e presubscript plus 1 end presubscript presuperscript 0 space plus italic space nu subscript straight e

    • straight H presubscript 1 presuperscript 1 = a hydrogen-1 nucleus, or a proton

    • straight H presubscript 1 presuperscript 2 = a hydrogen-2 nucleus, or 1 proton and 1 neutron

    • straight e presubscript plus 1 end presubscript presuperscript 0 = a positron, emitted when a proton turns into a neutron

    • nu subscript straight e = an electron neutrino, emitted along with the positron

  • In what form is energy released from nuclear fusion reactions?

    In fusion reactions, energy is released in the form of kinetic energy of the nuclei produced as well as gamma rays and neutrinos.

  • True or False?

    In a nuclear fusion reaction, the mass of the fused nucleus is the same as the mass of the two nuclei that fused together.

    False.

    In a nuclear fusion reaction, the mass of the fused nucleus is less than the mass of the two nuclei that fused together. The remaining mass has been converted to energy.

  • Calculate the energy released each time deuterium and tritium fuse into helium:

    straight H presubscript 1 presuperscript 2 space plus space straight H presubscript 1 presuperscript 3 space rightwards arrow space He presubscript 2 presuperscript 4 space plus space straight n presubscript 0 presuperscript 1

    Deuterium (hydrogen-2) has a binding energy of 1.11 MeV per nucleon, tritium (hydrogen-3) has a binding energy of 2.83 MeV per nucleon, and helium-4 has a binding energy of 7.07 MeV per nucleon.

    The energy released per fusion is about 17.6 MeV.

    • calculate the binding energy before the reaction = (1.11 × 2) + (2.83 × 3)

    • calculate the binding energy after the reaction = (7.07 × 4)

    • determine the difference in binding energy = (7.07 × 4) - (1.11 × 2) - (2.83 × 3) = 17.57 MeV

  • True or False?

    Fission reactions release more energy per kg than fusion reactions.

    False.

    Fusion reactions release much more energy per kg than fission.

  • What two conditions are required for nuclear fusion to occur?

    The two conditions required for nuclear fusion to occur are:

    1. High temperature

    2. High pressure or density

  • What is radiation pressure?

    Radiation pressure is a pressure that arises due to the transfer of momentum from photons to the surrounding matter.

  • How do main sequence stars remain in equilibrium?

    Main sequence stars remain in equilibrium because fusion reactions generate radiation pressure which acts outwards and balances the inwards-acting gravitational force.

  • When does a protostar become a main sequence star?

    A protostar becomes a main sequence star when nuclear fusion reactions are initiated in its core and the inward force of gravity is balanced by the outward pressure from the fusion reactions.

  • True or False?

    All stars form from a cloud of dust and gas which becomes a protostar and then a main sequence star.

    True.

    All stars follow the same initial stages in their life cycle:

    1. Nebula (cloud of dust and gas)

    2. Protostar

    3. Main sequence star

    The stages that follow depend on the mass of the main sequence star that forms.

  • Name the stages, in the correct order, in the life cycle of a star similar to the Sun.

    The stages, in the correct order, in the life cycle of a star similar to the Sun are:

    1. Nebula (cloud of dust and gas)

    2. Protostar

    3. Main sequence star

    4. Red giant

    5. Planetary nebula

    6. White dwarf

  • When does a main sequence star turn into a red giant?

    A main sequence star turns into a red giant when hydrogen in the star's core begins to run out and the star begins to fuse helium into heavier elements.

  • True or False?

    A high-mass star will eventually explode as a supernova and become a white dwarf.

    False.

    A high mass star will eventually explode as a supernova and become a neutron star or a black hole.

  • Name the stages, in the correct order, in the life cycle of a star with a mass larger than the Sun.

    The stages, in the correct order, in the life cycle of a star with a mass larger than the Sun are:

    1. Nebula (cloud of dust and gas)

    2. Protostar

    3. Main sequence

    4. Red supergiant

    5. Supernova

    6. Black hole, or neutron star

  • What is a supernova?

    A supernova is a large exploding star.

  • Under what conditions does a supernova occur?

    A supernova occurs when a star much more massive than the Sun reaches the end of its red supergiant stage. It collapses, becomes very unstable and explodes.

  • What determines whether the remnant core of a massive star becomes a neutron star or a black hole?

    The mass of the remnant core determines whether a massive star becomes a neutron star or a black hole.

  • True or False?

    High-mass stars have significantly longer lifetimes than low-mass stars.

    False.

    High-mass stars have significantly shorter lifetimes than low-mass stars.

    The greater the mass of a star, the higher its temperature, therefore, the greater the rate of fusion and the quicker the fuel is depleted in its core.

  • What is a Hertzsprung-Russell (HR) diagram?

    The Hertzsprung-Russell (HR) diagram is a plot of a star's luminosity on the y-axis and its surface temperature on the x-axis.

  • Which star on the H-R diagram has the highest surface temperature, A, B, C or D?

    Hertzsprung-Russell diagram showing stars A, B, C, D plotted by temperature (K) and luminosity (Sun = 1). Absolute magnitude and spectral class also indicated.

    The star with the highest surface temperature is star B.

    The hottest stars are located towards the left side of the H-R diagram.

  • Which star on the H-R diagram has the lowest surface temperature, A, B, C or D?

    Hertzsprung-Russell diagram showing stars A, B, C, D plotted by temperature (K) and luminosity (Sun = 1). Absolute magnitude and spectral class also indicated.

    The star with the coolest surface temperature is star D.

    The coolest stars are located towards the right side of the H-R diagram.

  • Which star on the H-R diagram is the brightest, A, B, C or D?

    Hertzsprung-Russell diagram showing stars A, B, C, D plotted by temperature (K) and luminosity (Sun = 1). Absolute magnitude and spectral class also indicated.

    The brightest star is star A.

    The brightest stars are found near the top of the H-R diagram.

  • Which star on the H-R diagram is most similar to the Sun, A, B, C or D?

    Hertzsprung-Russell diagram showing stars A, B, C, D plotted by temperature (K) and luminosity (Sun = 1). Absolute magnitude and spectral class also indicated.

    The most similar star to the Sun is star C.

    The luminosity scale is given in solar units, where the luminosity of the Sun = 1

  • Where is the main sequence located on the H-R diagram?

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. It features blobs representing different star categories.

    On the H-R diagram, main sequence stars are stars found in a band from the top left to the bottom right.

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. The main sequence is highlighted in blue.
  • Where are white dwarfs located on the H-R diagram?

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. It features blobs representing different star categories.

    On the H-R diagram, white dwarfs are located below the main sequence and slightly to the left.

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. The white dwarfs are highlighted in blue.
  • Where are red giants located on the H-R diagram?

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. It features blobs representing different star categories.

    On the H-R diagram, red giants are located above the main sequence and slightly to the right.

    Graph showing luminosity on the y-axis and temperature/spectral class on the x-axis. Red giants are highlighted in blue.
  • What type of stars are the hottest and dimmest on the H-R diagram?

    The hottest and dimmest stars on the H-R diagram are white dwarfs.

  • What type of stars are the coolest and brightest on the H-R diagram?

    The coolest and brightest stars on the H-R diagram are red supergiants.

  • What are the three types of light spectra?

    The three types of light spectra are:

    • continuous spectra

    • emission spectra

    • absorption spectra

  • True or False?

    Absorption spectra are observed when white light passes through a hot, low-pressure gas.

    False.

    Absorption spectra are observed when white light passes through a cool, low-pressure gas.

  • True or False?

    Continuous spectra are produced by hot, dense sources.

    True.

    Continuous spectra are produced from hot, dense sources, such as the cores of stars.

  • Why do stars emit absorption spectra?

    Stars emit absorption spectra because:

    • the hot, dense core produces a continuous spectrum

    • the cool, low-density gas in the outer layers absorbs photons

    • the resulting spectrum is a set of dark lines on a coloured background

  • How can the chemical composition of a star be determined?

    The chemical composition of a star can be determined by analysing its absorption spectrum and identifying elements by their unique pattern of spectral lines.

  • Define 1 astronomical unit (AU).

    One astronomical unit (AU) is the mean distance between the centre of the Earth and the centre of the Sun.

    1 AU is equal to approximately 1.5 × 1011 m.

  • Define 1 light-year (ly).

    One light-year is the distance travelled by light in one year.

    1 ly is equal to approximately 9.5 × 1015 m.

  • Define 1 parsec (pc).

    One parsec is a unit of distance that gives a parallax angle of 1 second of an arc.

    1 pc is equal to approximately 3.1 × 1016 m.

  • What is stellar parallax?

    Stellar parallax is the displacement in the apparent position of a nearby star against a background of distant stars when viewed from different positions of the Earth during its orbit around the Sun.

  • True or False?

    Stellar parallax is accurate for measuring distances up to about 100 light-years.

    False.

    Stellar parallax is accurate for measuring distances up to about 100 parsecs.

  • What is the equation for calculating the distance to a star using parallax angle?

    The equation for calculating the distance to a star is: d space equals space 1 over p

    Where

    • d = distance, measured in parsecs (pc)

    • p = parallax angle, measured in arcseconds (")

  • How many light-years are there in 1 parsec?

    There are approximately 3.3 light-years in 1 parsec.

    • 1 light–year is approximately 9.5 × 1015 m

    • 1 parsec is approximately 3.1 × 1016 m

    • therefore, 1 pc = fraction numerator 3.1 cross times 10 to the power of 16 over denominator 9.5 cross times 10 to the power of 15 end fraction = 3.26 ly

  • True or False?

    The parallax angle increases as the distance to a star increases.

    False.

    The parallax angle decreases as the distance to a star increases.

  • State the inverse square law of flux for a star.

    The inverse square law of flux for a star is: F space equals space fraction numerator L over denominator 4 straight pi d squared end fraction

    • F = radiant flux intensity, measured in watts per metre (W m-2)

    • L = luminosity of the star, measured in watts (W)

    • d = distance to star from Earth, measured in metres (m)

  • State Wien's displacement law for a star.

    Wien's displacement law for a star is: lambda subscript m a x end subscript T space equals space 2.9 cross times 10 to the power of negative 3 end exponent space straight m space straight K

    • lambda subscript m a x end subscript = peak wavelength of a star's emission, measured in metres (m)

    • T = surface temperature of the star, measured in kelvin (K)

  • State the Stefan-Boltzmann law for a star.

    The Stefan-Boltzmann law for a star is: L space equals space 4 straight pi r squared sigma T to the power of 4

    • L = luminosity of the star, measured in watts (W)

    • r = radius of the star, measured in metres (m)

    • T = surface temperature of the star, measured in kelvin (K)

    • sigma = Stefan-Boltzmann constant (5.67 × 10−8 W m−2 K−4)

  • True or False?

    The radius of a star can be directly measured.

    False.

    The radius of a star cannot be directly measured but must be calculated using other observable properties.

  • What information is needed to calculate the radius of a star using the Stefan-Boltzmann law?

    To calculate the radius of a star using the Stefan-Boltzmann law:

    • surface temperature can be calculated using Wien’s displacement law

    • luminosity can be calculated using the inverse square law of flux equation

  • How much greater is the luminosity of a star of radius 5 R subscript circled dot and surface temperature of 4 T subscript circled dot compared to the Sun?

    The star has a luminosity of 6400 space L subscript circled dot

    • Stefan-Boltzmann law: L space equals space 4 straight pi r squared sigma T to the power of 4

    • luminosity of the Sun: L subscript circled dot space equals space 4 straight pi R subscript italic circled dot squared sigma T subscript circled dot to the power of 4

    • luminosity of the star: L space equals space 4 straight pi open parentheses 5 R subscript italic circled dot close parentheses squared sigma open parentheses 4 T subscript circled dot close parentheses to the power of 4

    • luminosity of the star: L space equals space open parentheses 5 squared cross times 4 to the power of 4 close parentheses L subscript circled dot space equals space 6400 space L subscript circled dot

  • How much hotter is the surface of star X compared to the surface of star Y?

    HR diagram showing luminosity vs temperature. The crossing dashed lines show stars of radii 10R, 1R, and 0.1R.

    The surface of star X is about 6 times hotter than that of star Y.

    • Stefan-Boltzmann law: L space equals space 4 straight pi r squared sigma T to the power of 4

    • star X has a luminosity of 10 to the power of 4 space L subscript circled dot and a radius of 10 space R subscript circled dot

    • star Y has a luminosity of 10 to the power of negative 3 end exponent space L subscript circled dot and a radius of 0.1 space R subscript circled dot

    • ratio of temperatures: T subscript straight X over T subscript straight Y space equals space fourth root of open parentheses L subscript straight X over R subscript straight X squared close parentheses cross times open parentheses R subscript straight Y squared over L subscript straight Y close parentheses end root

    • ratio of temperatures: T subscript straight X over T subscript straight Y space equals space fourth root of open parentheses 10 to the power of 4 over 10 squared close parentheses cross times open parentheses fraction numerator 0.1 squared over denominator 10 to the power of negative 3 end exponent end fraction close parentheses end root space equals space 5.62 space almost equal to space 6