Single Slit Intensity Pattern
Single Slit Diffraction Pattern
- The diffraction pattern of monochromatic light passing through a single rectangular slit, is a series of light and dark fringes on a faraway screen
- This is similar to a double slit diffraction pattern:
- The bright fringes are also areas of maximum intensity, produced by the constructive interference of each part of the wavefront as it passes through the slit
- The dark fringes are also areas of zero or minimum intensity, produced by the destructive interference of each part of the wavefront as it passes through the slit
The diffraction pattern produced by a laser beam diffracted through a single slit onto a screen is different to the diffraction pattern produced through a double slit
- However, the single and double-slit diffraction patterns are different
- The central maximum of the diffraction pattern is:
- Much wider and brighter than the other bright fringes
- Much wider than that of the double-slit diffraction pattern
- On either side of the wide central maxima for the single slit diffraction pattern are much narrower and less bright maxima
- These get dimmer as the order increases
Single Slit Intensity Pattern
- If a laser emitting blue light is directed at a single slit, where the slit width is similar in size to the wavelength of the light, its intensity pattern will be as follows:
The intensity pattern of blue laser light diffracted through a single slit
- The features of the single slit intensity pattern are:
- The central bright fringe has the greatest intensity of any fringe and is called the central maximum
- The dark fringes are regions with zero intensity
- Moving away from the central maxima either side, the intensity of each bright fringe gets less
Changes in Wavelength
- When the wavelength passing through the gap is increased then the wave diffracts more
- This increases the angle of diffraction of the waves as they pass through the slit
- So the width of the bright maxima is also increased
- Red light
- Which has the longest wavelength of visible light
- Will produce a diffraction pattern with wide fringes
- Because the angle of diffraction is wider
- Blue light
- Which has a much shorter wavelength
- Will produce a diffraction pattern with narrow fringes
- Because the angle of diffraction is narrower
Fringe width depends on the wavelength of the light
- If the blue laser is replaced with a red laser:
- There is more diffraction as the waves pass through the single slit
- So the fringes in the intensity pattern would therefore be wider
The intensity pattern of red laser light shows longer wavelengths diffract more than shorter wavelengths
Changes in Slit Width
- If the slit was made narrower:
- The angle of diffraction is greater
- So, the waves spread out more beyond the slit
- The intensity graph when the slit is made narrower will show that:
- The intensity of the maxima decreases
- The width of the central maxima increases
- The spacing between fringes is wider
Single Slit Equation
- These properties of wavelength and slit width for single slit diffraction for the first minima can be explained using the equation:
- Where:
- θ = the angle of diffraction of the first minima (°)
- λ = wavelength (m)
- b = slit width (m)
- Hence,
- The longer the wavelength, the larger the angle of diffraction
- The narrower the slit width then the larger the angle of diffraction
Slit width and angle of diffraction are inversely proportional. Increasing the slit width leads to a decrease in the angle of diffraction, hence the maxima appear narrower
Single Slit Geometry
- The diffraction pattern made by waves passing through a slit of width b can be observed on a screen placed a large distance away
The geometry of single-slit diffraction
- If the distance, D, between the slit and the screen is considerably larger than the slit width, :
- The light rays can be considered as a set of plane wavefronts that are parallel to each other
Determining the path difference using two parallel waves
- For two paths, r1 and r2, travelling parallel to each other at an angle, θ, between the normal and the slit, the path difference will be:
path difference = r1 − r2 =
- For a minima, or area of destructive interference:
The path difference must be a half-integral multiple of the wavelength
path difference =
- Equating these two equations for path difference:
- Where n is a non-zero integer number, n = 1, 2, 3...
- Since the angle θ is small, the small-angle approximation may be used:
- Therefore, the first minima, n = 1, occurs at:
- This leads to the equation for angle of diffraction of the first minima:
Worked example
A group of students are performing a diffraction investigation where a beam of coherent light is incident on a single slit with width, b.
The light is then incident on a screen which has been set up a distance, D, away.
A pattern of light and dark fringes is seen.
The teacher asks the students to change their set-up so that the width of the first bright maximum increases.
Suggest three changes the students could make to the set-up of their investigation which would achieve this.
Step 1: Write down the equation for the angle of diffraction
-
- The width of the fringe is related to the size of the angle of diffraction, θ
Step 2: Use the equation to determine the factors that could increase the width of each fringe
Change 1
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- The angle of diffraction, θ, is inversely proportional to the slit width, b
-
- Therefore, reducing the slit width would increase the fringe width
Change 2
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- The angle of diffraction, θ, is directly proportional to the wavelength, λ
-
- Therefore, increasing the wavelength of the light would increase the fringe width
Change 3
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- The distance between the slit and the screen will also affect the width of the central fringe
- A larger distance means the waves must travel further hence, will spread out more
- Therefore, moving the screen further away would increase the fringe width