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First exams 2025

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Energy & Power (HL IB Physics)

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Ashika

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Ashika

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Energy & Power

  • The power of a mechanical process is the rate at which energy is transferred
  • This energy transferred is the work done
  • Therefore, power is:

The rate of work done (energy transfer)

  • Time is an important consideration when it comes to power
  • Two cars transfer the same amount of energy, or do the same amount of work to accelerate over a distance
  • If one car has more power, it will transfer that energy, or do that work, in a shorter amount of time

Power cars, IGCSE & GCSE Physics revision notes

Two cars accelerate to the same final speed, but the one with the most power will reach that speed sooner

  • Two electric motors:
    • lift the same weight
    • by the same height
    • but one motor lifts it faster than the other

  • The motor that lifts the weight faster has more power

Electric Motors Power, downloadable AS & A Level Physics revision notes

Two motors with different powers

  • Power can be calculated using the equation:

 

P space equals space fraction numerator increment W space over denominator increment t end fraction space equals space F v

 

  • Where:
    • P = power (W)
    • ΔW = change in work done (J)
    • Δt = time interval (s)
    • F = force (N)
    • v = velocity (m s–1)

 

  • The equation with F and v is only relevant where a constant force moves a body at constant velocity
    • Power is required in order to produce an acceleration
  • The force must be applied in the same direction as the velocity

 

  • Power is also used in electricity
  • Appliances are given a power rating, for example, 1000 W
    • The power ratings indicate the amount of energy transferred per second to the appliance

The Watt

  • Power is measured in watts (W)
  • The watt, W, is commonly used as the unit power (and radiant flux)
    • It is defined as 1 W = 1 J s–1

  • The SI unit for energy is kg m2 s–3
  • One watt is defined as:

A transfer of 1 joule of energy in 1 second

Worked example

A car engine exerts the following force for 1.0 km in 200 s.Determine what is the average power developed by the engine.

Worked example

A lorry moves up a road that is inclined at 14.5° to the horizontal.The lorry has a mass of 3500 kg and is travelling at a constant speed of 9.4 m s–1. The force due to air resistance is negligible.

Calculate the useful power from the engine to move the lorry up the road.

Answer:

Step 1: List the known quantities

  • Angle of slope, theta space equals space 14.5 degree
  • Mass, m space equals space 3500 space kg
  • Speed, v space equals space 9.4 space straight m space straight s to the power of negative 1 end exponent

Step 2: Write out the equation for the power of a constant force at a constant speed

P space equals space F v

Step 3: Calculate the constant force

  • The force needed to move the lorry up the slope is that which overcomes the component of the weight force pulling it down the slope

F space equals space m g space sin theta

F space equals space 3500 space cross times space 9.81 space cross times space sin open parentheses 14.5 close parentheses

F space equals space 8596.8 space straight N space

Step 4: Determine the power

P space equals space 8596.8 space cross times space 9.4

P space equals space 80 space 810 space straight W space equals space 81 space 000 space straight W space open parentheses 2 space straight s. straight f. close parentheses

Examiner Tip

The force represented in exam questions will often be a drag force. Whilst this is in the opposite direction to its velocity, remember the force needed to calculate the power is equal to (or above) this drag force to overcome it therefore you equate it to that value.

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Ashika

Author: Ashika

Expertise: Physics Project Lead

Ashika graduated with a first-class Physics degree from Manchester University and, having worked as a software engineer, focused on Physics education, creating engaging content to help students across all levels. Now an experienced GCSE and A Level Physics and Maths tutor, Ashika helps to grow and improve our Physics resources.